Use for the Tesla Switch

[Bit's-n-Bytes]

SO watts aren't time based?

Watts aren't, but watthours is. got time for skype?

[Web000x]

Watts do have a time rate involved. They are equivalent to the magnitude of joules per second. 'Watt Hours' is a translation back into joules.

Although, most people on the forum know this, but 'positive active power in' has nothing to do with 'negative active energy return' as per Eric Dollard's mathematics.

It is all about the electric wave distortion. When you change your capacitance or inductance(induced by switching), you are changing the "spatial distribution" of the circuit which confuses it by means of reactive power into a magnitude of -(Volts)*(Amperes) = Negative Energy. I am not talking about reactive energy by itself but also, a real negative power factor. From my constant study of Eric Dollard's algebra, that is where the energy comes from.

I know that there is a unification between Dollard/Bedini/Tesla, but nobody really speaks the language we all need. Hopefully I can figure out how Dollard's math applies to all of it since it is all we really have at the moment.

Looking forward to the conference.

Dave

[Matthew Jones]

Ya....
Thats confusing...

I need to produce straight numbers. If I can I have people who will pay attention. Nobody here want to pay the bill. With 6 running Tesla switch's in my community people are taking notice.

Thanks and good luck with your endeavors

Matt

[Kempis]

PM

@Matt,

You've PM

Kempis

[John_K]

Going over old ground

John B,

I'm pretty sure I have it figured out. You said that it's about the impedance, same as the SSG.

The 3 battery test helped me, thanks for kicking my brain into gear.

"The load must be chosen correctly so the battery is in a state of constant charge".

That means that you must match the impedance of the batteries so that the difference in potential just flows through, like opening the floodgates.

In the 3 battery test you have 2 x 12v batteries in series - 24v. But you also have twice the impedance of one 12v battery. So the load is really just the device that matches the impedance of the 2 x 12v batteries in series. In effect, the load is also in series with the 3rd battery so it's like you have 2 impedances in series, parallelled with another 2 impedances in series.

Because there is a difference in potential between the 2 sides, the batteries want to balance themselves with each other. It's the same as if you parallel two identiacl batteries together. If one is a little higher in impedance than the other, they will balance each other out. The voltage we see on the meter is really just and indication of the internal resistance of the battery. Higher impedance = lower voltage and vice-versa.

I can't believe it was in front of my eyes for so long but I was blind because it is so simple.

Also, there is no closed loop to kill the dipole.

John K.

Hey Jeff,

Remember this? Think about it. I'll test you in the morning


John K.

[Bit's-n-Bytes]

Hey Jeff,

Remember this? Think about it. I'll test you in the morning


John K.

It's all in the load.

Great job!

We'll have some cool things to show at the conference for sure.


Jeff

[rosehillworks]

Thank's

@John K
Thank YOU for the explanation

[Matthew Jones]

Hey Jeff,....

Sure does work that way too.

It an easy thing to check for sure. You just have to remember the load can regauge your power.

Matt

[John_K]

Tesla Switch

Yes, the load is very important.

The impedance of the load should be as low as possible. Think, if you just used a piece of wire as the "load" you would get maximum charge but what is the use of that?

Now insert a low resistance load such as a car headlight with a resistance of 1 ohm. Now you still good get charging and some light.

Now place another car headlight in parallel with the first. You've just halved the resistance of the total load so the charging gets better.

Why is the charging better? The differential potential between the 24v side and the 12v side is higher because the total impedance of the load is lower.

Hey Mr Jones, glad you piped in. I know you already have this figured out.


John K.

[Matthew Jones]

What I would love is to find a way to dynamically find the impedance of a battery, so the load can be altered in stages.

Thats the money right there.

As the impedance changes variables start to play. I wanna get past that.

Matt

[WeThePeople]

What I would love is to find a way to dynamically find the impedance of a battery, so the load can be altered in stages.

Thats the money right there.

As the impedance changes variables start to play. I wanna get past that.

Matt

That is a very heavy statement,
and absolutely correct too.

But only in a purely resistive load enviroment.

You can graph a plot using a constant voltage tracking load unit,
then feed that into a stamp micro to feed a current limiter circuit.

But other than tailoring extended operation of incandescent lamps with an annoying brightness variance, it has little use.

A circuit to keep the loading corrected to the source impedance,
that effectively still charges capacitance banks politely,
or pulses inductive loads without the source seeing the surges,
begins to look like two good-ole bucky' power supply circuits,
with a sizable capactor bank between them, doesn't it ?

[John_K]

What I would love is to find a way to dynamically find the impedance of a battery, so the load can be altered in stages.

Thats the money right there.

As the impedance changes variables start to play. I wanna get past that.

Matt

Hey Matt,

Have you thought about using the voltage of the battery to do that? Since the voltage is directly linked to battery impedance could you just use a voltage divider and an ADC to sense when the impedance changes or not?


John K.

[John_K]

We'll have some cool things to show at the conference for sure.


Jeff

You betcha buddy! I'm so excited I'm nearly wetting myself.

Just have to build the flux capacitor!


John K.

[Matthew Jones]

Hey Matt,

Have you thought about using the voltage of the battery to do that? Since the voltage is directly linked to battery impedance could you just use a voltage divider and an ADC to sense when the impedance changes or not?


John K.

The only problem is every battery is different. And I am not sure why. Some batteries allow a large current flow (20 amp pulses) up to about 13.5 volt on the low side. Several Batts do not though. They only allow around a 10 amp flow at about 13.00v.
I keep running them through.
I am going to start running a Parallax Propeller in the system soon. It has 8 processors and is capable of alot more operations at the same time. I just learned how to use an ADC.
So I am working on some kinda means to track everything dynamically and log it. After that I'll figure out something.

That article On Brandt continues to go through my head. He said the newer batteries would not balance and it effected his overall runtime in the Car or Truck or whatever he was running.
Now that I have the ability to come up with a significant power output, I think that 800 lbs of good lead I have managed to save up is going to get put to use soon.

Matt

[nvisser]

flux capacitor

Jk
You are so funny!
Jeff to.