Refreshing...again.
I really can not tell if you are so retarded for real, or is it your obsession and stubbornness to demonstrate your point, proving me wrong.
So, let me restart/refresh from your previous post above with your results.
Your results, which only means "time of contact" (as you have written above)...trying to translate it to you ...:
It only means the time the brush establishes contact with commutator segment...which is perfect, brilliant, excellent...However, Those results does NOT reflect how many times that "time of contact" REPEATS related to the Main Frame Time from Shaft, and of course commutator which is mounted thereto.
Based on normal and simple logic, no one with a healthy and calmed mind... could think that 6.1 or 9.5 milliseconds where one (1) Second contains One Thousand (1000) Milliseconds...and one (1) minute contains 60,000 milliseconds...is going to represents the repetition value on a shaft and commutator spinning at 1000 Revolutions Per Minute or 16.666 Revolutions Per Second.
So after you did your excellent calculation about "time of contact" between brush-commutator segment ...we need to know now how many times that value (time of contact) repeats within one minute (60 seconds) AND also for one Second of rotation from main shaft...:
First let's convert your results back from milliseconds to seconds:
Case 1- For the 1" radius Commutator (9.5 mS) = 0.0095 seconds
Case 2- For the 4" radius Commutator (6.1 mS) = 0.0061 seconds
For One (1) Second of Rotation...:
Case 1 (r=1"comm) = (1.0 Sec/0.0095 Sec)=105.26
Case 2 (r=4" comm) = (1.0 Sec/0.0061 Sec)=163.93
So, on the four inches radius commutator, the time of contact REPEATS around Sixty (60) times MORE than for the Case 1, or one inch radius commutator...and that is ONLY for One(1) second of rotation.
Now, One Minute has Sixty Seconds right?...so then:
For One (1) Minute of Rotation:
Case 1- 1" Radius= 1 minute= 60 Sec/0.0095 Sec= 6,315.79
Case 2- 4" Radius= 1 minute= 60 Sec/0.0061 Sec= 9,836.06
So, in one minute the 4" commutator segment establishes contact with brush roughly around 3520 more than the one inch commutator...
Now that is a big time difference between those two different diameter commutators...considering some motor applications stay operating for very long periods of time.
Not that "unnoticeable" now right?
Now I am resting this case here Bistander, it is completely up to you to keep refuting you are completely wrong...but you will be doing it by yourself
To me it is the end of this non sense argument.
Ufopolitics
Originally posted by bistander
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I really can not tell if you are so retarded for real, or is it your obsession and stubbornness to demonstrate your point, proving me wrong.
So, let me restart/refresh from your previous post above with your results.
Your results, which only means "time of contact" (as you have written above)...trying to translate it to you ...:
It only means the time the brush establishes contact with commutator segment...which is perfect, brilliant, excellent...However, Those results does NOT reflect how many times that "time of contact" REPEATS related to the Main Frame Time from Shaft, and of course commutator which is mounted thereto.
Based on normal and simple logic, no one with a healthy and calmed mind... could think that 6.1 or 9.5 milliseconds where one (1) Second contains One Thousand (1000) Milliseconds...and one (1) minute contains 60,000 milliseconds...is going to represents the repetition value on a shaft and commutator spinning at 1000 Revolutions Per Minute or 16.666 Revolutions Per Second.
So after you did your excellent calculation about "time of contact" between brush-commutator segment ...we need to know now how many times that value (time of contact) repeats within one minute (60 seconds) AND also for one Second of rotation from main shaft...:
First let's convert your results back from milliseconds to seconds:
Case 1- For the 1" radius Commutator (9.5 mS) = 0.0095 seconds
Case 2- For the 4" radius Commutator (6.1 mS) = 0.0061 seconds
For One (1) Second of Rotation...:
Case 1 (r=1"comm) = (1.0 Sec/0.0095 Sec)=105.26
Case 2 (r=4" comm) = (1.0 Sec/0.0061 Sec)=163.93
So, on the four inches radius commutator, the time of contact REPEATS around Sixty (60) times MORE than for the Case 1, or one inch radius commutator...and that is ONLY for One(1) second of rotation.
Now, One Minute has Sixty Seconds right?...so then:
For One (1) Minute of Rotation:
Case 1- 1" Radius= 1 minute= 60 Sec/0.0095 Sec= 6,315.79
Case 2- 4" Radius= 1 minute= 60 Sec/0.0061 Sec= 9,836.06
So, in one minute the 4" commutator segment establishes contact with brush roughly around 3520 more than the one inch commutator...
Now that is a big time difference between those two different diameter commutators...considering some motor applications stay operating for very long periods of time.
Not that "unnoticeable" now right?
Now I am resting this case here Bistander, it is completely up to you to keep refuting you are completely wrong...but you will be doing it by yourself
To me it is the end of this non sense argument.
Ufopolitics
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