want to make a high Voltage rating capacitor ?

[Ajnabii]

Hi every one

i want to make high voltage rating capacitor and i need a 20uf and 16000 volt capacitor please help me in this....

is it possible just like that.....

[ewizard]

You can run the numbers:
http://www.electronics2000.co.uk/cal...calculator.php

Some combination will get you there if you have enough caps.

[wayne.ct]

16 uf, 4000 Volt

40 identical caps arranged as shown will give you an effective cap of 16 uf, 4000 Volt, according to THEORY. Always consider that reality will not match the calculations. REAL is true and theory is almost always wrong, though it may be helpful.

Here is how to do the calculation:

1. Consider one line of capacitors in series independent of the final calculation which will be step 2.

10 caps, 40 uF each: Apply the formula: 1/Ctot = 10 * 1/40uF = 1/4uF.

Therefore, each line is equal to 4uF.

Volt handling capacity = 10 * 400 V = 4000 V.

Step 2. Consider four lines in parallel. Use the results of Step 1 which is the EFFECTIVE rating of each line, in isolation.

4 lines, 4uF each: Apply the formula: 4 * 4uF = 16 uF.

Volt handling capacity is NOT improved or diminished, i.e. 4000 V.

In summary: As configured = 16 uF, 4000 V.

[wayne.ct]

How many capacitors?

So, you need a 20uf and 16000 volt capacitor?

1. Do the voltage calculation first. One capacitor is rated at 400 V and you want an effective rating of 16000 V. How many capacitors do you need in ONE line of your final array? 16000 V / 400 V = 40 capacitors in one line.

2. What is the capacitance of 40 capacitors in series? One capacitor is 20 uF.
1/CTOT = X * 1/20 uF = 40/20 uF = 2/1 uF (where X = 40)

Therefore, CTOT = 0.5 uF

3. How many lines of capacitors? (40 capacitors per line)

Desired cap = 20 uF = (number of lines) * 0.5 uF.

Therefore, number of lines = 40 lines.

4. How many capactors?

Number of capacitors = Number of lines * number of capacitors per line

= 40 * 40 = 1600 capacitors.

If you get a different result, reply with your "better" calculation!

[wayne.ct]

What if you only have 40 capacitors?

In other words, what is the best you can do with what you have?

First of all, notice that the calculations are easiest if you have a RECTANGULAR array. So, you can arrange your 40 capacitors in a 4 by 5 array. OR, you can arrange them in a 5 by 4 array. Or, you can leave 4 unused and create a square array, i.e. 4 by 4.

Here are the results of each: (All capacitors are 20 uF and 400 V rating.

4 lines of 5 capacitors: 16 uF and 2000 V

5 lines of 4 capacitors: 25 uF and 1600 V

4 lines of 4 capacitors: 20 uF and 1600 V

Once again, if I have made an error of calculation, please post a reply.

[wayne.ct]

Correction

In the image, the capacitors are indicated to be 20 uF and 40 uF. This is an internal contradiction and you need to make the appropriate adjustment in your thinking. What can you do with that tidbit? Have fun kiddies!

[Ernst]

Formula can be made a little simpler:

Voltage per line = nr of caps * voltage rating per cap.

Example: 20 capacitors of 400 Volt each in series will give you 20 * 400 V = 8000 Volt.

Capacitance per line = capacitance per cap / nr of caps
(only with identical caps!)

Example: 20 capacitors of 40 uF each in series will give you 40uF / 20 = 2 uF

Capacitance multiple lines = .capacitance per line * nr of lines

Example: 4 lines of 2 uF each in parallel will give you 2uF * 4 = 8 uF

===================
So....
You want 20 uF and 16000 V and you have a bag of 40 uF / 400 V

You will need to make strings of 16000 V / 400V = 40 pieces
Each string will then be 40 uF / 40 = 1 uF
You then need 20 uF / 1 uF = 20 strings

Total nr of capacitors required: 20 strings * 40 capacitors = 800 capacitors

Planning to kill someone?

Ernst.

[blackchisel97]

You could use 8 of these - 40 UF 5KV High Voltage Pulse Energy Capacitor NEW HV Laser Tesla Coil | eBay Two serial strings of four connected in parallel will get you 20uF and 20kV. Enough to disable a rhinoceros

V

[wayne.ct]

Nice Flames

Yeah, top notch material....

[Ernst]

You could use 8 of these - 40 UF 5KV High Voltage Pulse Energy Capacitor NEW HV Laser Tesla Coil | eBay Two serial strings of four connected in parallel will get you 20uF and 20kV. Enough to disable a rhinoceros

V

Energy contained if fully charged: E = CV²/2 = 0.000020 * 20,000² / 2 = 4,000 J.
(enough to heat a cup of water to boiling point)

Instant power when shorted: 20,000 * 1,400 * 2 = 56 MW

That will make a lot of noise and probably evaporate your wire...

Fun stuff to play with, but a little bit expensive.

Ernst.

[Ajnabii]

40 identical caps arranged as shown will give you an effective cap of 16 uf, 4000 Volt, according to THEORY. Always consider that reality will not match the calculations. REAL is true and theory is almost always wrong, though it may be helpful.

Here is how to do the calculation:

1. Consider one line of capacitors in series independent of the final calculation which will be step 2.

10 caps, 40 uF each: Apply the formula: 1/Ctot = 10 * 1/40uF = 1/4uF.

Therefore, each line is equal to 4uF.

Volt handling capacity = 10 * 400 V = 4000 V.

Step 2. Consider four lines in parallel. Use the results of Step 1 which is the EFFECTIVE rating of each line, in isolation.

4 lines, 4uF each: Apply the formula: 4 * 4uF = 16 uF.

Volt handling capacity is NOT improved or diminished, i.e. 4000 V.

In summary: As configured = 16 uF, 4000 V.

You can run the numbers:
http://www.electronics2000.co.uk/cal...calculator.php

Some combination will get you there if you have enough caps.

So, you need a 20uf and 16000 volt capacitor?

1. Do the voltage calculation first. One capacitor is rated at 400 V and you want an effective rating of 16000 V. How many capacitors do you need in ONE line of your final array? 16000 V / 400 V = 40 capacitors in one line.

2. What is the capacitance of 40 capacitors in series? One capacitor is 20 uF.
1/CTOT = X * 1/20 uF = 40/20 uF = 2/1 uF (where X = 40)

Therefore, CTOT = 0.5 uF

3. How many lines of capacitors? (40 capacitors per line)

Desired cap = 20 uF = (number of lines) * 0.5 uF.

Therefore, number of lines = 40 lines.

4. How many capactors?

Number of capacitors = Number of lines * number of capacitors per line

= 40 * 40 = 1600 capacitors.

If you get a different result, reply with your "better" calculation!

In other words, what is the best you can do with what you have?

First of all, notice that the calculations are easiest if you have a RECTANGULAR array. So, you can arrange your 40 capacitors in a 4 by 5 array. OR, you can arrange them in a 5 by 4 array. Or, you can leave 4 unused and create a square array, i.e. 4 by 4.

Here are the results of each: (All capacitors are 20 uF and 400 V rating.

4 lines of 5 capacitors: 16 uF and 2000 V

5 lines of 4 capacitors: 25 uF and 1600 V

4 lines of 4 capacitors: 20 uF and 1600 V

Once again, if I have made an error of calculation, please post a reply.

In the image, the capacitors are indicated to be 20 uF and 40 uF. This is an internal contradiction and you need to make the appropriate adjustment in your thinking. What can you do with that tidbit? Have fun kiddies!

Formula can be made a little simpler:

Voltage per line = nr of caps * voltage rating per cap.

Example: 20 capacitors of 400 Volt each in series will give you 20 * 400 V = 8000 Volt.

Capacitance per line = capacitance per cap / nr of caps
(only with identical caps!)

Example: 20 capacitors of 40 uF each in series will give you 40uF / 20 = 2 uF

Capacitance multiple lines = .capacitance per line * nr of lines

Example: 4 lines of 2 uF each in parallel will give you 2uF * 4 = 8 uF

===================
So....
You want 20 uF and 16000 V and you have a bag of 40 uF / 400 V

You will need to make strings of 16000 V / 400V = 40 pieces
Each string will then be 40 uF / 40 = 1 uF
You then need 20 uF / 1 uF = 20 strings

Total nr of capacitors required: 20 strings * 40 capacitors = 800 capacitors

Planning to kill someone?

Ernst.

You could use 8 of these - 40 UF 5KV High Voltage Pulse Energy Capacitor NEW HV Laser Tesla Coil | eBay Two serial strings of four connected in parallel will get you 20uF and 20kV. Enough to disable a rhinoceros

V

Yeah, top notch material....

first of all thanks to all for everything, can some one give me a one answer but good answer i need your short answer but proper i am not going to do it by formula just help me in this

i want to make lower capacitance capacitor for example 10uf or 20uf but i need the voltage of the same capacitor 16000 Volt

so how much capacitors i will use for this ?? and these capacitors will be in series or parallel and or series-parallel ?

please guide me with diagram that how i will connect these capacitors, i am totally confused......

Thank You

[Ajnabii]

......

Formula can be made a little simpler:

Voltage per line = nr of caps * voltage rating per cap.

Example: 20 capacitors of 400 Volt each in series will give you 20 * 400 V = 8000 Volt.

Capacitance per line = capacitance per cap / nr of caps
(only with identical caps!)

Example: 20 capacitors of 40 uF each in series will give you 40uF / 20 = 2 uF

Capacitance multiple lines = .capacitance per line * nr of lines

Example: 4 lines of 2 uF each in parallel will give you 2uF * 4 = 8 uF

===================
So....
You want 20 uF and 16000 V and you have a bag of 40 uF / 400 V

You will need to make strings of 16000 V / 400V = 40 pieces
Each string will then be 40 uF / 40 = 1 uF
You then need 20 uF / 1 uF = 20 strings

Total nr of capacitors required: 20 strings * 40 capacitors = 800 capacitors

Planning to kill someone?

Ernst.

Hahahhaha no bro i am not going to kill someone i have one project i want to replace the capacitor but i don't get in to shops here because it is high voltage rating capacitor,
it's value is just like that

20 uf and 16000 volt so it is just one capacitor which is not available here in the shops

so that's why i am confused bro,

[blackchisel97]

You won't find capacitor like that in any shop. Military surplus or scientific/military suppliers only and possibly custom made to order. They used to have 10uF here but currently out of stock. You may want to contact them and see if they may be available again - https://www.tedss.com/2020006080.
These are pulse capacitors designed to store and discharge large current.
You can use parallel/serial configuration of several hundred capacitors but they need to be good quality or they'll exhibit "popcorn effect" shortly after plugging in.
You connect in series to get higher voltage at the cost of total capacitance.
You connect in parallel to get higher capacitance as the individual values add together but your voltage rating will remain the same.
If you parallel 10 caps rated at 1uF/2kV you'll get 10uF total, 2kV rating and lower total ESR.
To boost their voltage rating you need to connect them in series. 10 of 1uF/2kV (microwave cap) in series will give you about 20kV rating but total capacitance will drop to only 100nF. Now, you'll need ten strings like that in parallel to get 1uF back so you're looking at 100 capacitors bank already.
40 capacitors rated at 1,000uf/400V in series will get you approx. 25uF/16kV
This is where parallel/serial calculation comes handy and will depend on the individual values you have available.

V

[wayne.ct]

Science and safety requires applied math

You need at least 800 capacitors and maybe 1600. Wire them up the way you show in your diagram. Can you imagine a diagram with 800 capacitors? You have the basic idea. Just do it. I can't do your thinking for you. If you can't understand the basic algebra then this idea you have is too dangerous for you. Please make up your mind whether you want to risk killing yourself or take some advice and stop before it is too late. I hope you decide to think about this and not hurt yourself. 15 mA of current is enough to kill you. If that much current goes through your heart it will cause heart arrest. The capacitor you are planning to build will be capable of delivery of instantaneous current of more than 15000 mA. This is a Darwin moment. All true patriots please remove your hats and salute the flag.

[Ajnabii]

.......

You won't find capacitor like that in any shop. Military surplus or scientific/military suppliers only and possibly custom made to order. They used to have 10uF here but currently out of stock. You may want to contact them and see if they may be available again - https://www.tedss.com/2020006080.
These are pulse capacitors designed to store and discharge large current.
You can use parallel/serial configuration of several hundred capacitors but they need to be good quality or they'll exhibit "popcorn effect" shortly after plugging in.
You connect in series to get higher voltage at the cost of total capacitance.
You connect in parallel to get higher capacitance as the individual values add together but your voltage rating will remain the same.
If you parallel 10 caps rated at 1uF/2kV you'll get 10uF total, 2kV rating and lower total ESR.
To boost their voltage rating you need to connect them in series. 10 of 1uF/2kV (microwave cap) in series will give you about 20kV rating but total capacitance will drop to only 100nF. Now, you'll need ten strings like that in parallel to get 1uF back so you're looking at 100 capacitors bank already.
40 capacitors rated at 1,000uf/400V in series will get you approx. 25uF/16kV
This is where parallel/serial calculation comes handy and will depend on the individual values you have available.

V

can i use this capacitors for AC Voltage ?