how much real power or(recommended power) am i changing when i cut out a section of

[johnnyfalcon]

14 gauge ( hot and neutral) wires in a circuit say in a house between two normal 125v 15amp receptacles 5 feet apart and replaced the cut out discarded peice of 14 g wires with a thicker 12 gauge wires?

Does this negatively hurt any thing
What are the effects now with thicker wires at this location ?

Thanks

[jacwebb]

12ga

No; just a waste of copper.

[johnnyfalcon]

No; just a waste of copper.

Surely something is different i just cant figure it out,i dont care how insignificant the changes are but juust wanna know from the electric champions here

I had to remove to remove the old 14g wires because rats chewed into it so at the hardware store i could only find12g wires i figured bigger is better or good enough

[Ufopolitics]

Nothing negative about it...

14 gauge ( hot and neutral) wires in a circuit say in a house between two normal 125v 15amp receptacles 5 feet apart and replaced the cut out discarded peice of 14 g wires with a thicker 12 gauge wires?

Does this negatively hurt any thing
What are the effects now with thicker wires at this location ?

Thanks

Hello Johnny,

Nothing negatively about replacing with higher gauge, the problem would be IF the gauge would be thinner than.

You are just giving the electric flow in that section a "Bigger Highway" to run at...


Regards


Ufopolitics

[Peter0001]

14 AWG wire = 0.00829 ohm/m
12 AWG wire = 0.00521 ohm/m

For your 2m length of 12 AWG you have a 0.00616 ohm lower resistance.
Your bigger wire will heat up slightly less wasting less power.

Lets assume a 1A average load for a year.
Power = Current squared X resistance
You continuously save 0.00000616kW of wasted heat.
If you pay $0.15 per kilowatt hour
8760 hours * 0.00000616 kw * $0.15 per kWh
=$0.0081 savings per year

almost a cent per year

[johnnyfalcon]

14 AWG wire = 0.00829 ohm/m
12 AWG wire = 0.00521 ohm/m

For your 2m length of 12 AWG you have a 0.00616 ohm lower resistance.
Your bigger wire will heat up slightly less wasting less power.

Lets assume a 1A average load for a year.
Power = Current squared X resistance
You continuously save 0.00000616kW of wasted heat.
If you pay $0.15 per kilowatt hour
8760 hours * 0.00000616 kw * $0.15 per kWh
=$0.0081 savings per year

almost a cent per year

Awesome reply thanks

[johnnyfalcon]

Hello Johnny,

Nothing negatively about replacing with higher gauge, the problem would be IF the gauge would be thinner than.

You are just giving the electric flow in that section a "Bigger Highway" to run at...


Regards


Ufopolitics

Thanks friend