The episode of the closed resource. Translation from Russian.
The main theme of this study is that if the mass is equivalent always and everywhere, then the centrifugal acceleration should be equivalent to linear acceleration. Accordingly, the centrifugal force must be equivalent to the linear force. But the centrifugal acceleration is not taken into account in equivalent formulas. A centrifugal force is considered "fictitious", since it is perpendicular to the velocity vector and can not perform work consistently ... But is it so?
As is known, the centrifugal force Fc = m ω2 R = mv2 / R
Consequently, the power of the flywheel according to the centrifugal force P = mv3 / R
But official scientists abandoned this formula - arguing that the velocity and centrifugal force vectors are perpendicular. Consequently, the centrifugal force can not do the work.
P = Fv * cos @ = mv3 / R * cos 90o = 0
Therefore, the power of the flywheel is calculated only from the angular parameters.
But on the other hand, if the force applied to the flywheel surface is perpendicular to the speed, then it must stop the flywheel or move it along with its axis. But the centrifugal force does not "do it". On the contrary, it is observed experimentally that it enhances the rotation.
Hence, the vector of the centrifugal force is not only perpendicular to the velocity, but also rotates - the elasticity of the material of the flywheel makes it rotate!
After all, the moment of momentum is "spinning"! To prove the "capacity" of the moment of the pulse-for it came up with a special term - psevdovector or pseudoscalar.
If the angular momentum mvR can be a pseudovector, why can the centrifugal force mv2 / R not be the same - but not pseudo, but real - parallel to the vector of the linear rotation speed?
A comparison of the momentum and angular momentum of a rotating body proves this assumption.
As is known, the total momentum of a rotating body is equal to zero mv = 0, but the momentum moment is somehow greater than zero mvR> 0. What kind of magical power has a radius, that it restores the compensated mass and speed separately, since together they are equal to zero?
Why the radius can not have such properties in the case of centrifugal force? Hence centrifugal force can do work - contrary to existing dogma.
*For greater leveling of centrifugal force, it is often given the rule that if the body moves along a closed trajectory, the total work of the force is zero.
But there is another rule, according to which, if the force is constant in absolute value and makes the same angles with elementary displacement vectors at any place of the trajectory, then the work of the force is greater than zero, in spite of the fact that the total displacement vector of the point of application of the force is zero.
This rule is ideally matched exactly by the centrifugal force at a constant speed of rotation.
Consequently, the power produced by the centrifugal force must also be calculated by the formula:
P = mv3 / R
As is known, the centrifugal force Fc = m ω2 R = mv2 / R
Consequently, the power of the flywheel according to the centrifugal force P = mv3 / R
But official scientists abandoned this formula - arguing that the velocity and centrifugal force vectors are perpendicular. Consequently, the centrifugal force can not do the work.
P = Fv * cos @ = mv3 / R * cos 90o = 0
Therefore, the power of the flywheel is calculated only from the angular parameters.
But on the other hand, if the force applied to the flywheel surface is perpendicular to the speed, then it must stop the flywheel or move it along with its axis. But the centrifugal force does not "do it". On the contrary, it is observed experimentally that it enhances the rotation.
Hence, the vector of the centrifugal force is not only perpendicular to the velocity, but also rotates - the elasticity of the material of the flywheel makes it rotate!
After all, the moment of momentum is "spinning"! To prove the "capacity" of the moment of the pulse-for it came up with a special term - psevdovector or pseudoscalar.
If the angular momentum mvR can be a pseudovector, why can the centrifugal force mv2 / R not be the same - but not pseudo, but real - parallel to the vector of the linear rotation speed?
A comparison of the momentum and angular momentum of a rotating body proves this assumption.
As is known, the total momentum of a rotating body is equal to zero mv = 0, but the momentum moment is somehow greater than zero mvR> 0. What kind of magical power has a radius, that it restores the compensated mass and speed separately, since together they are equal to zero?
Why the radius can not have such properties in the case of centrifugal force? Hence centrifugal force can do work - contrary to existing dogma.
*For greater leveling of centrifugal force, it is often given the rule that if the body moves along a closed trajectory, the total work of the force is zero.
But there is another rule, according to which, if the force is constant in absolute value and makes the same angles with elementary displacement vectors at any place of the trajectory, then the work of the force is greater than zero, in spite of the fact that the total displacement vector of the point of application of the force is zero.
This rule is ideally matched exactly by the centrifugal force at a constant speed of rotation.
Consequently, the power produced by the centrifugal force must also be calculated by the formula:
P = mv3 / R
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