Motor Generators

[bistander]

You have proven nothing because you have never made a controlled bridge rectifier. If you had, you wouldn't be writing this nonsense.

But I have not only done it, but also taught others. For one mini-hydropower plant.
The voltage at idle (no load) was 60-65V, and the battery voltage at which the charge occurred was 24V. So, the thyristor was given a switch-off signal when the voltage reached 27V, which corresponds to a full charge of the 24V battery. Before that, where did the rest of the voltage, or rather the EMF, go?

Mr. Rakarskiy,

One of your blunders involved a FWBR, full wave bridge rectifier, not a controlled bridge rectifier, so you have not addressed the issue.

91466693 (2).jpg
But I'll respond to your new question about the controlled bridge rectifier using the thyristor charging a battery if you supply a circuit diagram and define the "switch-off signal".
bi

[Rakarskiy]

You clearly have a perception problem. You are confusing the whole thing (isolated circuit with the household network via distribution transformers). Under load, on the capacitor will be the voltage that remains after voltage drop and current generation in the isolated circuit I am considering.

This sketch is based on motifs from Soviet technical specialist magazines, variants of adjustable rectifiers for permanent magnet generators, which I did for an amateur group on building mini hydroelectric power plants.

925982836.jpg

[bistander]

You clearly have a perception problem. You are confusing the whole thing (isolated circuit with the household network via distribution transformers). Under load, on the capacitor will be the voltage that remains after voltage drop and current generation in the isolated circuit I am considering.

This sketch is based on motifs from Soviet technical specialist magazines, variants of adjustable rectifiers for permanent magnet generators, which I did for an amateur group on building mini hydroelectric power plants.

925982836.jpg

Mr. Rakarskiy,

91466693 (2).jpg
This is the circuit where you blundered. What is the voltage V across the load R which is also across the capacitor C1?
https://www.patreon.com/posts/emf-current-112414335
It is in your published essay found at the address above. You conclude and state:

As a result, we get a constant voltage of 220V on the load.

That is incorrect. Connected as per your diagram, the load voltage is NOT 220V when the circuit input is 220VAC.
Address this issue. Or perhaps you do not care about the quality and correctness of your publications, which you offer for sale. How do your customers feel when you ignore uncorrected errors and mistakes the likes of which you've been informed?
bi