Moving Charge
Yes, I thought I had made that clear. But the electron beam or stream is moving charges which constitute current by definition so it is current. The wire or conductor is not necessary for current. The electron beam, a single charge moving or a current all have a magnetic field around them as described in the references in my earlier posts.
There is a B field vector at every point in the magnetic field. When looking at the force on a charge traveling in that field, you must use the B vector at the field location where the charge is at the exact moment in time.
You mean this picture?
![](http://www.energeticforum.com/attachment.php?attachmentid=17104&d=1461814479)
The magnets (S of one shown & N of the other) are not independent. The same flux passes through both of them. They are simply "cut off" in the illustration for clarity; obviously there cannot be an independent S magnet on one side of the gap and a different independent N on the opposite. But that illustration does in fact show the magnetic field as uniform; for simplicity. In the real world, the field would not be uniform. It would fringe at the edges of the poles and, depending on the rest of the magnetic circuit (not shown), may even be weaker near the center of the poles.
You can see in that picture 3 force vectors. Each force vector would need to be calculated using the B vector and v vector for the charge q at that particular location and time. The force at that instant acting on q along with all the other forces acting on q at that instant will determine the acceleration according to the mass of the charge and ultimately determine the trajectory. That is why it is shown as a curve instead of a sharp upwards turn.
Hope that makes sense.
bi
Originally posted by bistander
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Originally posted by Ufopolitics
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Originally posted by bistander
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Originally posted by Ufopolitics
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Originally posted by Ufopolitics
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The magnets (S of one shown & N of the other) are not independent. The same flux passes through both of them. They are simply "cut off" in the illustration for clarity; obviously there cannot be an independent S magnet on one side of the gap and a different independent N on the opposite. But that illustration does in fact show the magnetic field as uniform; for simplicity. In the real world, the field would not be uniform. It would fringe at the edges of the poles and, depending on the rest of the magnetic circuit (not shown), may even be weaker near the center of the poles.
You can see in that picture 3 force vectors. Each force vector would need to be calculated using the B vector and v vector for the charge q at that particular location and time. The force at that instant acting on q along with all the other forces acting on q at that instant will determine the acceleration according to the mass of the charge and ultimately determine the trajectory. That is why it is shown as a curve instead of a sharp upwards turn.
Hope that makes sense.
bi
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