Split Positive Boost Charger

[BroMikey]

Hi folks, the experiment is at the 42 hour mark, or 336 watt/hours.
All 3 battery voltages added and divided by 3, each battery is now at 12.62 volts.

When this experiment finishes, i will run another experiment.
Though this time, i will increase the power closer to c20 rate, to speed up testing results.
So far though, the numbers are looking pretty good, don't you folks think.
I know some are sceptical about how many watts my setup is using and i understand.
Though for now, i do not have watt meters or anything, maybe at some point i will get that.
Though tell me, does anyone disagree with my previous comments about the power usage from the series batteries.
I see mike said, great evaluation, does that mean you agree, though you would still like more solid data evidence from a watt meter.
Right now, it is similar to Peters unscientific method, just to see if we are even in the ball park and so far, it does not appear to be an illusion, as Peter said.
peace love light

Hi Sky

Hey 1 watt/hr more than should be available is as good as gold to
me. Is this the setup? No booster right? Boosters present losses.
We were told motors only but I guess those windings of yours
look pretty good to the 3 battery get up.

[BroMikey]

Hi folks, the experiment is at the 42 hour mark, or 336 watt/hours.
All 3 battery voltages added and divided by 3, each battery is now at 12.62 volts.


Right now, it is similar to Peters unscientific method, just to see if we are even in the ball park and so far, it does not appear to be an illusion, as Peter said.
peace love light

You don't need a watt meter. The voltmeter will tell the tail. 12.6v is near
a full battery so it looks like you are one of the first to prove free or extra
energy circuits do have their place in the world.

Illusion? That voltmeter is no Illusion.

[SkyWatcher]

Hi mike, thanks for the supportive reply.
Yes, that is the circuit.
It is 2 layers of 24awg. bifilar magnet wire on the ferrite c-core, taken from a TV flyback.
No booster, that did have extra losses.
And one of the keys here i think, is the coil recovery is splitting the positive again, through a load and into the charge battery.
peace love light

Oh and the diode is a high speed one.

[BroMikey]

Hi mike, thanks for the supportive reply.
Yes, that is the circuit.
It is 2 layers of 24awg. bifilar magnet wire on the ferrite c-core, taken from a TV flyback.
No booster, that did have extra losses.
And one of the keys here i think, is the coil recovery is splitting the positive again, through a load and into the charge battery.
peace love light

Oh and the diode is a high speed one.

It looks like another special circuit that is a qualifying phenomena.
Let's make sure and once we are I'll have to get this thread to go viral.
It looks like a new day is dawning.
Run Rabbit Run.

I can't wait to be up and running. Your batteries should be dead at the
60hr mark. This is based on the 13ah figure so 60 hrs at the very most.

And you say 8watts going into the lights? BTW I am looking at
battery testers but I am unsure, I will show the ones I buy.

[SkyWatcher]

Hi mike, i just noticed you updated your last post.
Yes, it is around 8 watts, .32 amps going through the circuit and into the charge battery.
Was busy all day, am going to continue experiment now.
I will watch to see the battery testers you suggest.
peace love light

[BroMikey]

Hi mike, i just noticed you updated your last post.
Yes, it is around 8 watts, .32 amps going through the circuit and into the charge battery.
Was busy all day, am going to continue experiment now.
I will watch to see the battery testers you suggest.
peace love light

Hi Sky

Measure both positive terminals with your multimeter. The 12v positive
is your negative on the meter the 24v positive terminal is your positive
on your meter. Now this is the operating voltage of the circuit.

Next multiply that voltage by the .32amp or 320ma. Typically the
differential between the 24v positive and the 12v battery positive will
range anywhere from 13v to 10v depending.

So let's say you are running a 12v differential between positives and
you say you are at 320ma? 3.84 watts is what I get, so your
circuit, if run conventionally will deplete at 120hrs. Anything past
120hrs is free power.

[SkyWatcher]

Hi mike, thanks for the reply.
Here is a thought, if we put two 12 volt batteries in series for 24 volts and apply this to a motor coil with a permanent magnet rotor.
Then we pulse the coil to create motor action, at a certain amperage.
The magnet will induce a voltage in the coil to reduce our amperage, but it never reduces our input voltage.
It just creates a lower potential difference, which is the reason for the lower current through the coil.
In my opinion, this is the same as with the 3 battery system, we are always applying input at the series battery voltage.
The charge battery is acting like the induced motor coil, which only lowers amperage, due to lower potential difference.
So we are still applying 25 or so volts into the charge battery, it doesn't magically disappear from the equation, what disappears, is our amperage potential, due to less voltage available between the positives.
If we applied your logic to a permanent magnet motor, we could input 100 volts at 1 amp and then claim we are only inputting a few watts, because the potential difference of the induced voltage in motor coil is only say a few volts at a certain rpm.
It doesn't work like that and it doesn't work like that in the 3 battery system either.
My point is, whenever you are using that 24 or so volts input, we multiply that by the amperage flowing between the positives, that is the real power used by the series batteries.
We are trying to recover as much of that back as we can, that is why my circuit is recovering the spike, while still splitting the positives to try and get as much back as we can and also Peter is doing something similar.

peace love light

[BroMikey]

Hi mike, thanks for the reply.
Here is a thought, if we put two 12 volt batteries in series for 24 volts .........................much back as we can and also Peter is doing something similar.

peace love light

Hello Sky

Yes 25v starting in the run battery bank at the 320ma. Well instead
of a long post I made a chart of the way we are taught voltage drop
in electricity. 4 watts is going to the circuit and 4 watts is going to
the charging battery.

If there is another way to show this let me know. But you are right
there is more going on with the circuit because it generates pulses.

So the way I see the system is in the potential difference like the
charging battery may immediately jump right up to 13volts in the first
few minutes of running the circuit leaving only 12v going to your circuit.

Now if we were to put another identical circuit like you have there already
in series that would make 2 circuits splitting up the voltage yet again. With
2 circuits in series with the charge battery that would still receive 13v
at the 320ma while circuit 1 and circuit 2 would split the difference.

In that case the wattage going to circuit one and circuit 2 would be two
watts apiece and battery 3 still getting hit with 13v@320ma.

When the charge battery hits 15v your circuit voltage is greatly reduced
at 10v X 320ma is much less at only 3.2watts going to the light and
15v X 320ma = 4.8watts going to charge battery 3. Of course my
inverter runs taught me that because it shuts down.

[SkyWatcher]

Hi mike, yes, i think it is acting like a voltage divider.
I was going to post that thought, though i did not have it properly formed in my mind yet.
At least we are in agreement, the series battery voltage needs to be multiplied by the amperage between the positives.
Your diagram seems to show what really happens to the voltage from the series batteries.
I'll have to give more thought to your idea about adding another oscillator circuit in series.
peace love light

Would also like to add small update on experiment.
Experiment is at the 48 hour mark.
Added all 3 battery voltages and divide by 3, each battery is still at 12.62 volts.

[BroMikey]

Hi mike, yes, i think it is acting like a voltage divider.
I was going to post that thought, though i did not have it properly formed in my mind yet.
At least we are in agreement, the series battery voltage needs to be multiplied by the amperage between the positives.
Your diagram seems to show what really happens to the voltage from the series batteries.
I'll have to give more thought to your idea about adding another oscillator circuit in series.
peace love light

Yes you will see after awhile but a 3rd or 4th oscillator or just having
2 oscillators will not help you because each circuit is at best 85%
efficient, meaning 15% of the energy that the circuit handles is lost
in small amounts of heat. Then we must remember that batteries do
not collect the same amount of energy they are dealt. Batteries can
be quite inefficient as low as 50% of the power they are fed is actually
assimilated. This is why John Bedini technology is focused on perfection
with battery charging devices so as to optimize energy transfers.

All of our exchanges are repeats in old threads such as the 3 battery generating or whatever. We are told that motor pulses using windings
that are pulsed can bring in new energy. This is why I like your circuit.

[SkyWatcher]

Hi mike, thanks for sharing.
I wonder how the more basic circuit you posted might work, multistrand with a dedicated transistor per strand.
Also, be aware, the NTE52 transistor i'm using is fast switching and designed for inductive switching, though it has a somewhat low amp rating.
That's why i'm wondering how your circuit might work with at least 3 power strands and these fast transistors and diodes, in the split positive setup.
peace love light

[BroMikey]

Hi mike, thanks for sharing.
I wonder how the more basic circuit you posted might work, multistrand with a dedicated transistor per strand.
Also, be aware, the NTE52 transistor i'm using is fast switching and designed for inductive switching, though it has a somewhat low amp rating.
That's why i'm wondering how your circuit might work with at least 3 power strands and these fast transistors and diodes, in the split positive setup.
peace love light

Okay now you are asking the good questions like I knew you would and I wanted to address these ideas yet we needed to go over the other material
first. We did that, so now on to the message we are given and how Peter
is using recovery windings.

Originally we were told to use a modified motor as a Tesla switch/
prime mover. That is what we were told as to where the magic was
found if you will. Magic or not the extra was for one reason or another
is realized.

First sizing and tuning is so important. To cut to the chase this modified
motor whips my batteries back side like no tomorrow. I mean to tell you
this bad boy really whips up a charge and if turned up will require that
you use 10 batteries in parallel just as we see Dave doing. I mean no
waiting, this Tesla Switch complete with electrical whip makes short
work of charging batteries and this is what we need to overcome the
losses in plate deterioration thru sulfates/resistance.

Let me stress how fast it charges a battery again when I go from
12volts on my booster to 14.75v. The booster is there to drive a
team of wild horses (Big Battery Bank) and the differential may only
be 11volts without the booster, hardly enough to blow a flea off of a
gorillas butt, let alone put the petal to the metal charging up large
lead plates.

Sure the booster presents some losses and improvements can be made
there but that does not bring us up short handed either. I believe DAVE
not just because I see it with my own eyes but because I am a great
judge of words.

Dave's battery bank is getting a 3 to 1 COP right off the bat without
a generator collecting the excess mechanical energy. A higher COP
will follow when a generator is added.

So I don't talk all night let me compare Matt motor switch to Peter's
recovery windings and I'll shut up Who me shut up? Yup!

I am a 2 fingered typist with poor literary abilities and this takes a
great effort to compose. I see how others can fly like a butterfly on a
keyboard but not me. It takes a huge amount of time.

Matt's motor Tesla Switch stops and starts the dc power relasing
accumulated energy collected in the copper windings that hit the
run batteries in the form, I guess we can say, of BEMF? Well whatever
we decide to name what is hitting the run batteries off of the mod mtr
we must take note of the fact that the voltage increases.

What do I mean? I mean if I drained 1 amp off of those
batteries other ways the voltage drops and keeps dropping but the
matt mod mtr tesla switch not only charges battery 3 with no waiting
it also keeps it's own run batteries collecting kick backs which can be
seen as a higher voltages.

Peter is using recovery winding not powered off of the 4 transistors
to collect the backlash (BEMF) so that the run batteries are assisted.

Either way we do it the windings must recovery energy not normally harvested and then sent back to keep the run batteries up.

The Tesla switch mod mtr action can be duplicated electronically but
nither your circuit nor Peter using a standard SG circuit does that so
Peter used recovery windings. Genius.

Now as for who will find another way or even circuits that give higher efficiency in lower percentages remains to be seen so keep at it. It is
my guess that in Peter's case the 4 dead strands are connected in
series, rectified and sent back to the run batteries with every pulse.

Muller did something like that.

[SkyWatcher]

Hi mike, thanks for taking the time to share that information.
Yes, i had some ideas to try and one involved a separate recovery winding, to send the coil recovery through led bulbs and into the series batteries.
A couple strands in series could work or a secondary coil with full wave bridge for both options.
I thought it wasn't good to charge the input batteries while taking current from them.
Though using recovery winding with single diode, sending pulse back to input series batteries, when we are not taking current from them, would be like bedinis original basic free energy generator device.
Testing of this particular experiment continues, the voltage actually settled out to 12.6 volts per battery, when allowed to rest over night.
peace love light

[Peter Lindemann]

Just So You Know....

Hey Guys,

Just so you know, I am NOT applying the recovery impulses from the coils to the "Run Batteries." I have already explained what I am doing with it in Post #136. The schematic of this process is part of the film of my presentation from the Conference. If you haven't seen it yet, you may want to check it out.

Here is a link to it for you convenience: CLICK HERE

Best regards,
Peter

[BroMikey]

Hey Guys,

Just so you know, I am NOT applying the recovery impulses from the coils to the "Run Batteries." I have already explained what I am doing with it in Post #136. The schematic of this process is part of the film of my presentation from the Conference. If you haven't seen it yet, you may want to check it out.

Here is a link to it for you convenience: CLICK HERE

Best regards,
Peter

Wow Peter thanks for clearing everything up, you did say that the recovery
windings energy was sent to the charging batteries. You
guys were getting air-conditioning out of your machine at low amps
I got to get one of those. Okay so the recovery windings did just as good of a job sending all of the recovered power into the charge batteries and
who knows, MAYBE the run batteries were getting a degree of assistance
right off of Peter's SG configuration which I think is a relatively standard
practice for that machine.

What a nice job you did Peter, showing the operation. Great demo.