A Free Energy Idea

[p75213]

You didn't specify V was total voltage and constant. In fact your interesting observation at the end of that post implies a higher total voltage for the series connection, doesn't it?
bi

If we switch the caps from parallel to series each cap has V volts. Therefore a total of 2V volts for the series circuit. So yes it is a higher voltage for the series circuit. I can see your point. I was just making the observation that it takes a lower voltage to charge parallel caps to the same energy level as the same number of caps in a series circuit.

Why will they discharge quicker in a series circuit as opposed to a parallel circuit. The charge/discharge time constant is RC where R = resistance and C = capacitance. In the series circuit the total capacitance is now C/2 for 2 equivalent caps. Or C/n for n similar caps. Whereas the total capacitance in the parallel circuit was 2C or nC for n similar caps.

Why do we get more power. Because power is defined as the rate of using energy. In the series circuit the energy is being used at a faster rate.

[bistander]

RC

...
Why will they discharge quicker in a series circuit as opposed to a parallel circuit. The charge/discharge time constant is RC where R = resistance and C = capacitance. In the series circuit the total capacitance is now C/2 for 2 equivalent caps. Or C/n for n similar caps. Whereas the total capacitance in the parallel circuit was 2C or nC for n similar caps.
...

Hi p75213,

For any number of identical capacitors in any series or parallel combination, the equivalent time constant for the group will be RC, the time constant of the individual capacitor.

2 in parallel -> (R/2) * (2C) = RC

2 in series -> (2R) * (C/2) = RC

bi

[p75213]

Hi p75213,

For any number of identical capacitors in any series or parallel combination, the equivalent time constant for the group will be RC, the time constant of the individual capacitor.

2 in parallel -> (R/2) * (2C) = RC

2 in series -> (2R) * (C/2) = RC

bi

Your right. I forgot about R. It was looking pretty good their for awhile.

[BroMikey]

To see what is possible, you need to use a charged capacitor with a "known" charge as the source. Then quickly connect it to several capacitors in series and measure what you have in each capacitor as well as what is still in the original capacitor. Then put ALL capacitors in parallel to send everything back to a second set of capacitors in series. Keep going back and forth with the two sets of capacitors and measure what you get. Are the voltages going up or down?

I do not understand

Charge cap 1 with 20vdc supply say then charge several caps in series then
send that to a second bank of 1 cap and several series caps but send only
using a parallel connection path?

If I don't understand your very important post, there are lots who have
no clue. I want to stress how important I consider your entries but have
found out from past exchanges that only a picture can solve my inability.

I think I understand some of it but not sure and I do not want to let this
go by without asking to find out for sure.

I picture 2 banks of caps to send energy back and forth in certain
connection paths using a single source to start out with? Again I am
unsure. Or is it that each time a test is made I am to use the same
known source?

But then I could not send that charge over to a second bank from the
first bank and make any sense out of my reasoning so I conclude charging
the first set of 1cap and several (say3 or 4 or 5) in series is done with a
known source?
Which one is right?

@everyone
I want everyone to know I consider Turion a great researcher so when
he talks, I try to understand.

[BroMikey]

To see what is possible, you need to use a charged capacitor with a "known" charge as the source. Then quickly connect it to several capacitors in series and measure what you have in each capacitor as well as what is still in the original capacitor. Then put ALL capacitors in parallel to send everything back to a second set of capacitors in series. Keep going back and forth with the two sets of capacitors and measure what you get. Are the voltages going up or down?

Does this look right so far?

[Ufopolitics]

One last thing. I firmly believe that the amount of charge in a closed system is finite and cannot be increased unless additional charge is brought in from an external source; such as a battery, generator, from the environment or from the earth.

Hello Cadman,

You are correct, however:

You could increase the amount of charge in ANY Closed System, without absolutely any direct connections (wiring) to any external sources like a battery, generator, etc, just by adding a "receiver" core-coil to the closed system....then INDUCING a charge (EMF) through a Magnetic Field from a second exciting (transmitter) coil circuit.

Closed system will remain "physically" closed, and energy will enter through Spatial Electromagnetic Induction.

But still, I understand energy would be coming from an "external source"...


Regards


Ufopolitics