Hi lighty
I am using those cheap multimeters that can measure up to 10A of current. I tried to get a shunt out from a cheap meter, but there was just a thick copper wire used as a shunt with no specs on it, so I can't use that. I also searched for some shunts in local electronics shops, but they do not have anything around, I can just order some from them, but they are charging about 50$ a piece for a 5A, 60mV shunt, like this:
So I really have not pursued the shunt measuring idea
What about these shunts:
20A 75mV DC Current Shunt Good4 Digital Analog meter - eBay (item 350072790126 end time Jun-29-08 09:16:37 PDT)
do you think they would be suitable? If yes, I will buy them now!
Of course, I am not an expert, but do you really think, that all those spikes would make an error this big on my cheap amp meters? The power supply current reading is about 30% less than the amp meter reading, but that, of course, is because of the recovery. I mean, to get at least 60% efficiency in my calculations, it would require a current draw of about 1A (instead of 2.45) for the same other readings. Could those spikes make an error this big on the meter?
Maybe the problem is somewhere else
Thank you!
I am using those cheap multimeters that can measure up to 10A of current. I tried to get a shunt out from a cheap meter, but there was just a thick copper wire used as a shunt with no specs on it, so I can't use that. I also searched for some shunts in local electronics shops, but they do not have anything around, I can just order some from them, but they are charging about 50$ a piece for a 5A, 60mV shunt, like this:
So I really have not pursued the shunt measuring idea
What about these shunts:
20A 75mV DC Current Shunt Good4 Digital Analog meter - eBay (item 350072790126 end time Jun-29-08 09:16:37 PDT)
do you think they would be suitable? If yes, I will buy them now!
Of course, I am not an expert, but do you really think, that all those spikes would make an error this big on my cheap amp meters? The power supply current reading is about 30% less than the amp meter reading, but that, of course, is because of the recovery. I mean, to get at least 60% efficiency in my calculations, it would require a current draw of about 1A (instead of 2.45) for the same other readings. Could those spikes make an error this big on the meter?
Maybe the problem is somewhere else
Thank you!
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