Originally posted by uusedman
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very nice!! i little different approach than i was thinking, which is good! its nice to see your ideas, not just a reproduction of my ideas/answers.
so here is some more of my thoughts and then you can share what you think about it.
it looks like your getting closer to what i was suggesting in regards to 2 duty cycles. i believe we can break the process down into 2, well maybe 3 categories.
1. electrical
2. magnetic
3. mechanical
the first duty cycle i observe is a magnetic/mechanical one. or how long do we need a magnetetic field to pull the rotor into alignment.
the second duty cycle i see is an electrical/magnetic. or how much energy(electricity) do we need to create the magnetic pull.
when i look at a scope shot of my motor i notice that the time it takes for a field to build in the core is a lot quicker than the time needed to pull the rotor into alignment. also in my first motor i used an adjustable window with an optotrigger, this allowed better control to change the ontime in a 1 pulse process, and if you stick a filament light bulb on the kickback and open the ontime up a lot its easy to see that you still only get 1 short flash on the kickback bulb. i wasn't sure why until peter helped me better understand that the ontime and the collapse operate under different mathematical principals.
the ontime is easier, it operates under the simple formula V=IR so the voltage of your source and resistance of your motor coil combined with the "time" spent in the ontime phase will tell us how much energy we are paying for at the source. but what then?
once we have spent energy to build a field in the core of the motor and then precede to turn the switch "off", does the amount of energy collected(recycled) also follow V=IR? no. its math is a lot more complicated i believe it can be found in this book Lindsay: Solenoids & Electromagnets i am still rereading that book to get a better understanding of the math. but for now i think the important point is that the "rule" is completely different. as i understand it, the amount of energy returned is not a function of how long we run the ontime but instead its a function of how strong the magnetic field is (amperturns) when we kill the switch and the impedance of the motor coil plus the load the kickback is connected to. now consider that when you use a low gauge wire (say 18 gauge) and apply your source the rise time(time needed to raise/build a magnetic field) is incredibly short. 2 things can determine when this initial process is done.
1. the voltage of your source in conjunction with the resistance of your coil (v=ir) has achieved all the amps times the number of turns in your coil(amperturns) it can. or 2. your core material cant accept anymore magnetic field energy(is saturated).
once this point has been reached "no more energy can be collected when you kill the switch" so if the ontime is left on longer than this point the, field is maxed, and is no longer "storing" more energy, all you are doing is allowing more(exess) amps to travel freely through the coil to drain/short your source. when this is understood you might be able to see what i mean by 2 duty cycles.
what you want to do is find a balance of how much time(energy=amps*time) is needed to build the field to its max then kill the switch and collect/convert as much "stored magnetic energy" into generated electricity back to the system. to answer another question of yours. where you believe you are getting more energy from the kickback than what you put into the ontime, the answer is no. the electric circuit used to "run" the motor is/was never intended to be cop>1 (overunity) the magic is not in the electric circuit. if you get 70% back that's pretty good! this is why i like to use the word "recycle" when talking about the electrical part. the "secret", if you want to call it that is in measuring how much "total" mechanical energy you can harvest from the shaft after you "recycle" the 70% back into the "runtime" process. if you want something more conceptual to read about recycling electrons then i would get this book "Energy Conserver Theory" by George Wiseman found here Energy Conserver Theory, Book 1 [4901.99.00.503] - $8.00 : Eagle-Research Store
so we have an electrical/magnetic proccess (duty cycle) or balancing the energy spent in the ontime with the energy recycled in the collapse
and a magnetic/mechanical proccess (duty cycle) time spent useing a magnetic field to pull in the rotor
so far i see a few ways to design a solution.
1. figure out how much time is needed to pull the rotor, calculated from rpms and the width of the rotor then figure out how many balanced ontime pulses you would need per rotor pass
2. figure out how much time is needed to pull the rotor, calculated from rpms and the width of the rotor and design the rotor width small/short enough that at a certain rpm the time spent in the rotor pass is short enough to handle one balanced ontime pulse
3. figure out how much time is needed to pull the rotor, calculated from rpms and the width of the rotor and design the coils resistance or impedance not sure which or both to slow or lengthen the rise time of the ontime.
anouther test you can try is to go back to just 2 poles/coils, ties both run batts in series for 24v, use each tranny circuit for each pole, you will want both reeds to fire at the same time(paralel) run only 1 pole/coil from the 24v source and dump the kickback into that big blue cap you have. the cap will now be source 2 for the other pole/coil so tie the second tranny circuit into the cap source and dump the kickback from the 2nd pole into a charge batt. in my weed wacker motor setup the rpms started out slow then increased more as the voltage on the cap got higher for the 2nd pole, this is like running a second motor on recycled energy alone and then you are also recycling some of the recycled energy again into a charge batt! after you play with
that you can come up with other ways to tie in the other poles.
hope that helps!
Eric
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