Calculating Faraday Efficiency.

[dynamite]

I have tried looking for it on a few different sites, but it only seems to do my head in.

can someone please post the formula and possibly a link to how faraday came to his conclusion (not that i want to debate it but see if it clears my thoughts)

just some examble numbers to help me keep in context

12v, 10a, 50ml of HHO in 25 seconds. (not actuall results)

[ashtweth]

From Stefan

here is a formular to calculate the energy needed to break the overunity barrier
in HHO gas production.

As the Faraday law states, that 100 % efficient electrolysis required about 2.4 Watthours
of energy for 1 Liter of HHO gas production you can now yourself calculate, what you are using
for your energy input.

Energy input in Watthours= used (Volts x amps) x used seconds / 3600 seconds= used Watts x used seconds / 3600 seconds

So let your HHO gas generator produce 1 Liter of HHO gas and measure the time
it needs to produce this amount of gas.

Then note the Voltage and amps down and multiply it to get the Watts.
Then multiply with the seconds and divide by 3600.

Now if you get less than 2.4 Watthours you have overunity.
If you have more than 2.4 Watthours you have less than 100 % efficiency and are underunity.

Regards, Stefan.

[dynamite]

ok, thanks for that. i think i got it now.
found one of my main problems was i was trying to get my final expression to be Lh/Wh. when faradays is WH/Lh.

now i will have a clear consise way to present my findings to the community.