Originally posted by rickoff
View Post
The quickest formula I could set my hands on for you that I use is -
Area - Wikipedia, the free encyclopedia
The formula is for a cylinder or tube (exterior) -
2 x Pi x r2 + 2 x Pi x r x h
Tubing - .250 od x .125 id (.125 r x .0625 r)
OD - .098 + .785 = .883 sq.in.
ID - .024 + .392 = .416 sq.in
(OD + ID) .883 + .416 = 1.299 sq.in. Total
Wire - .077 dia. x 7 (strands) #4AWG CU WIRE "95 amps" NOTE-(AWG cir.mil. "is" AWG cir.mil. regardless of strand qty.)
.009 + .238 = .247 sq.in. (1-strand)
.247 x 7 (strands) = 1.729 sq.in.
1.729 Wire sq.in.
1.299 Tube sq.in.
.430 sq.in smaller the tube is
I'm sure this is the correct formula, radius squared not diameter ?
Regards,
Glen
Comment