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  • Originally posted by Watson View Post
    OU? any chance you could post a link to it? Thanks.

    I got some Fuji and Kodak flash units from disposable cameras and I'd like to modify them for driving a CFL.
    There is a circuit for it on page 6 post #154
    There is also a basic Joule thief circuit on page one.

    Lidmotor also has a very nice Inverted Joule Thief curcit some where in this thread.

    I also sent you a PM for a link to the camera mod.

    Comment


    • Supercharged JT

      Originally posted by slayer007 View Post
      There is a circuit for it on page 6 post #154
      There is also a basic Joule thief circuit on page one.

      Lidmotor also has a very nice Inverted Joule Thief curcit some where in this thread.

      I also sent you a PM for a link to the camera mod.

      I got the schem, thanks for the link.

      I read some of the thread and saw that there's a quest for efficiency.

      Recently I discovered that I could double the efficiency of the JT, easily, with a diode, resistor and capacitor. I called it a Supercharged JT.

      The scary part is that I sometimes got an efficiency of over 90 percent.

      Quantsuff and I both experimented with the circuit and he and I confirmed the results. But we believe the measurements are causing too high readings. We monitor the LED current with a 1 ohm resistor in the cathode led of the LED; for every millivolt across it, there is a milliamp of LED current.

      He modified the circuit to make it flash. Problem is that it likes to flash only with air core coils, not toroids. But the real point is that by using the circuit I gave in my link above, it will double the efficiency of the JT, or conversely it will reduce the supply current in half, while still maintaining a very bright LED.

      Also, by using the circuits in the link to QS's webpage above, the drive to the transistor can be increased. He shows one circuit that can drive a 1W Luxeon to full brightness.

      I'm thinking I can use this circuit to drive an old tube radio output transformer by connecting the speaker winding to the transistor, and a CFL across the winding that goes to the tube.

      More on this later...

      Comment


      • Nice stuff! A quite different mechanism for oscillation -- did not thought about that before. Not sure what do you mean by 90% efficiency though -- do you mean electricity -> light or something else? How did you get this figure?

        Originally posted by Watson View Post
        I got the schem, thanks for the link.

        I read some of the thread and saw that there's a quest for efficiency.

        Recently I discovered that I could double the efficiency of the JT, easily, with a diode, resistor and capacitor. I called it a Supercharged JT.

        The scary part is that I sometimes got an efficiency of over 90 percent.

        Comment


        • self-charging JT (SJT)

          @all: I'd also like to suggest a self-charging JT circuit here: basically it feeds back to the same source. See attached. This makes testing OU easy: just see if the rest voltage of the source gets higher after using ...

          Edit: to play save, the diodes can be 1N4007. The battery voltages can be 6V-12V, given that you used more tolerant transistors (2N3055 and MJ2955).

          LEGAL NOTICE: This is released into the public domain for the overall goodness, nobody shall patent it. If anyone choose to implement this, you must take all the responsibilities for any bad consequences.

          Originally posted by slayer007 View Post
          There is a circuit for it on page 6 post #154
          There is also a basic Joule thief circuit on page one.

          Lidmotor also has a very nice Inverted Joule Thief curcit some where in this thread.

          I also sent you a PM for a link to the camera mod.
          Attached Files
          Last edited by lanenal; 05-24-2009, 04:27 PM.

          Comment


          • Originally posted by lanenal View Post
            Nice stuff! A quite different mechanism for oscillation -- did not thought about that before. Not sure what do you mean by 90% efficiency though -- do you mean electricity -> light or something else? How did you get this figure?

            The input power is the input voltage multiplied by the iput current. The current through the LED is found by putting a 1 ohm resistor in series with the LED cathode. For every millivolt I measure across the 1 ohm resistor, there is 1 milliamp through the resistor and the LED. Assuming 3.2 volts across the typical white or blue LED, the power to the LED is the current multiplied by 3.2.

            The efficiency is the power to the LED divided by the input power, and multiplied by 100 to get the percent.

            Problem is that when I do the measurements and get a figure above 90%, then double check and get the same thing, I begin to think, something is not right here. But what adds further confusion is that the power supply meter says 1.5 volts and, say, 50 milliamps, and my eyes see that the LED is very bright. The input power is only 75 milliwatts, less than half of what the conventional Joule Thief takes, yet the LED looks as bright as a conventional Joule Thief. My eyes tell me that this is really putting out the light at very low power, but my head is telling me that the circuit can't be nearly 100 percent efficient.

            We (meaning others and myself) believed that the measurements were not accurate because the meter was not measuring the LED current correctly. It is a high current pulse and the meter is not meauring the true current. I put a 100k resistor and 0.1u capacitor low pass filter between the 1 ohm resistor and the meter to average out the pulses. and I still get the same current.

            Well, hell...

            Comment


            • An explanation about JT

              Thanks for the explanations. It is fascinating. I will study your circuit more closely when I got some time.

              For those who are interested, I'd like to give an explanation of JT here:

              Let's start with the point of time where there is ZERO collector-emitter current in the 2n3055. Now because of the battery, there will be base-emitter current through the trigger coil, limited by the resister in series. This makes the transistor close (as a switch) between collector and emitter, but keep in mind that there is a ceiling cap on the current that can flow through (roughly equals the base-emitter current multiplied by the beta parameter of the transistor). So current in the power coil starts to increase, until the current ceiling cap is reached, at which point the current stops increasing. Mind you one more crucial detail: while the current was increasing in the power coil, the trigger coil can pick up a little boost and that help contribute to the base-emitter current. Now when the current in the power coil stops increasing, such a boost ceases to exist and this immediately drops the ceiling cap quite a bit (say, 20%, depending on how much boost the trigger coil picks up from the power coil). Such a drop of ceiling cap sends the power coil into its down turn at once -- the current in it starts to decrease, and such a current decrease in the power coil further lower the cap through the pick up (inductance) at the trigger coil ( in fact, the decrease is usually fast enough to shut off the transistor completely). The decrease stops until the current in the power coil reaches ZERO, and we are about to start a new cycle. That's it, folks!

              Originally posted by Watson View Post
              The input power is the input voltage multiplied by the iput current. The current through the LED is found by putting a 1 ohm resistor in series with the LED cathode. For every millivolt I measure across the 1 ohm resistor, there is 1 milliamp through the resistor and the LED. Assuming 3.2 volts across the typical white or blue LED, the power to the LED is the current multiplied by 3.2.

              The efficiency is the power to the LED divided by the input power, and multiplied by 100 to get the percent.

              Problem is that when I do the measurements and get a figure above 90%, then double check and get the same thing, I begin to think, something is not right here. But what adds further confusion is that the power supply meter says 1.5 volts and, say, 50 milliamps, and my eyes see that the LED is very bright. The input power is only 75 milliwatts, less than half of what the conventional Joule Thief takes, yet the LED looks as bright as a conventional Joule Thief. My eyes tell me that this is really putting out the light at very low power, but my head is telling me that the circuit can't be nearly 100 percent efficient.

              We (meaning others and myself) believed that the measurements were not accurate because the meter was not measuring the LED current correctly. It is a high current pulse and the meter is not meauring the true current. I put a 100k resistor and 0.1u capacitor low pass filter between the 1 ohm resistor and the meter to average out the pulses. and I still get the same current.

              Well, hell...

              Comment


              • Originally posted by lanenal View Post
                Thanks for the explanations. It is fascinating. I will study your circuit more closely when I got some time.

                For those who are interested, I'd like to give an explanation of JT here:

                Let's start with the point of time where there is ZERO collector-emitter current in the 2n3055. Now because of the battery, there will be base-emitter current through the trigger coil, limited by the resister in series. This makes the transistor close (as a switch) between collector and emitter, but keep in mind that there is a ceiling cap on the current that can flow through (roughly equals the base-emitter current multiplied by the beta parameter of the transistor). So current in the power coil starts to increase, until the current ceiling cap is reached, at which point the current stops increasing. Mind you one more crucial detail: while the current was increasing in the power coil, the trigger coil can pick up a little boost and that help contribute to the base-emitter current. Now when the current in the power coil stops increasing, such a boost ceases to exist and this immediately drops the ceiling cap quite a bit (say, 20%, depending on how much boost the trigger coil picks up from the power coil). Such a drop of ceiling cap sends the power coil into its down turn at once -- the current in it starts to decrease, and such a current decrease in the power coil further lower the cap through the pick up (inductance) at the trigger coil ( in fact, the decrease is usually fast enough to shut off the transistor completely). The decrease stops until the current in the power coil reaches ZERO, and we are about to start a new cycle. That's it, folks!
                A point to remember is that there is transfer of power from the primary winding (called power coil above) to the feedback winding (called trigger coil above) *only* when there is a change of flux, which is caused by a change in current in the primary winding. Once the current reaches its maximum (called ceiling above), there is no longer a change in flux and no longer a transfer of power to the feedback winding.

                Since the feedback to the feedback winding is regenerative or in phase, once the transfer stops, the current from the feedback winding to the base of the transistor drops a slight amount. And this causes the collector current to drop, which then transfers power from the primary to the feedback winding and since it's opposing the base current, it further reduces the base current.

                Thus complete cutoff of the base current happens suddenly, and the stored energy in the primary winding has no place to go, so it tries to increase the voltage across the transistor, but when the voltage gets to the point where the LED conducts, it flows through the LED. Let there be LIGHT!

                And then the whole process repeats itself, at about a hundred thousand times each second. Cool, huh?

                Has anyone experienced this problem? I bought some LEDs on ebay and found that they have air bubbles in the epoxy, which in my opinion is something that should be caught during inspection at the factory and rejected. The seller doesn't seem to think this is a problem. What do you think? I want my money back.

                Comment


                • In the ideal situation, the trigger coil picks up almost the same amount of voltage as the power source when the current in the power coil is increasing (so it doubles the cap ceiling). In the phase when the current in the power coil is decreasing, the trigger coil picks up something equivalent to that of the output voltage of the power coil -- usually much more than that of the power source, but in opposite direction. So that shuts off the transistor completely.

                  lanenal



                  Originally posted by Watson View Post
                  A point to remember is that there is transfer of power from the primary winding (called power coil above) to the feedback winding (called trigger coil above) *only* when there is a change of flux, which is caused by a change in current in the primary winding. Once the current reaches its maximum (called ceiling above), there is no longer a change in flux and no longer a transfer of power to the feedback winding.

                  Since the feedback to the feedback winding is regenerative or in phase, once the transfer stops, the current from the feedback winding to the base of the transistor drops a slight amount. And this causes the collector current to drop, which then transfers power from the primary to the feedback winding and since it's opposing the base current, it further reduces the base current.

                  Thus complete cutoff of the base current happens suddenly, and the stored energy in the primary winding has no place to go, so it tries to increase the voltage across the transistor, but when the voltage gets to the point where the LED conducts, it flows through the LED. Let there be LIGHT!

                  And then the whole process repeats itself, at about a hundred thousand times each second. Cool, huh?

                  Has anyone experienced this problem? I bought some LEDs on ebay and found that they have air bubbles in the epoxy, which in my opinion is something that should be caught during inspection at the factory and rejected. The seller doesn't seem to think this is a problem. What do you think? I want my money back.

                  Comment


                  • LEDs Have Air Bubbles In Lens

                    Originally posted by lanenal View Post
                    In the ideal situation, the trigger coil picks up almost the same amount of voltage as the power source when the current in the power coil is increasing (so it doubles the cap ceiling). In the phase when the current in the power coil is decreasing, the trigger coil picks up something equivalent to that of the output voltage of the power coil -- usually much more than that of the power source, but in opposite direction. So that shuts off the transistor completely.

                    lanenal
                    And it can give you a shock if you touch both coil leads and there is no load on the coil.

                    I requested a return and refund, but the irascible seller refused and threatened that if I gave negative feedback and made a dispute with Paypal, they would have me banned from buying LEDs from all other ebay sellers.

                    I left negative feedback, and filed a claim and dispute with Paypal, and I am still waiting for the decision from Paypal. I'm very disappointed that it ended this way, but sellers have to know that LEDs with air bubbles in the lens should be rejected at the factory and should never be sold as new, top grade parts. Sellers should be selling these as 'seconds' or factory rejects.

                    Yeah, can you believe that? Banned! I've made only 50 transactions on ebay in more than 4 years, so is being banned going to make my life any more difficult? No. But these LEDs with flaws are being sold as top grade parts and that has to stop.

                    Comment


                    • How to Convert Super Cap to JT?

                      Originally posted by Watson View Post
                      Oops, forgot the pic.
                      Here's what I (finally) got from Mouser, after waiting for over a month. I now have several 50 Farad super capacitors. I have connected them in series-parallel to a 4 volt solar cell. I can charge them up to about 4 volts.

                      But that's too high a voltage for a Joule thief. I don't know if you have tried this, but connecting a JT to over 3V has a really big problem. The JT doesn't have to work, because the voltage is high enough to make the LED conduct, and in the conventional JT, the only thing between the LED and battery is the winding of the coil. If it is low resistance, then the LED will conduct heavily and overheat, letting the smoke out.

                      So the trick here is to have a circuit that will accept any voltage between 4 volts down to less than a volt, as the super capacitor discharges. With a conventional JT the brightness varies greatly with the voltage. The circuit I want should have a constant output as the voltage decreases from 4V to 1V.

                      So does anyone have any ideas?

                      Comment


                      • constant

                        @ Watson - tried using a zener diode?
                        Atoms move for free. It's all about resonance and phase. Make the circuit open and build a generator.

                        Comment


                        • ebay story

                          Wish it ends well -- keep us updated about the ebay story.

                          Originally posted by Watson View Post
                          And it can give you a shock if you touch both coil leads and there is no load on the coil.

                          I requested a return and refund, but the irascible seller refused and threatened that if I gave negative feedback and made a dispute with Paypal, they would have me banned from buying LEDs from all other ebay sellers.

                          I left negative feedback, and filed a claim and dispute with Paypal, and I am still waiting for the decision from Paypal. I'm very disappointed that it ended this way, but sellers have to know that LEDs with air bubbles in the lens should be rejected at the factory and should never be sold as new, top grade parts. Sellers should be selling these as 'seconds' or factory rejects.

                          Yeah, can you believe that? Banned! I've made only 50 transactions on ebay in more than 4 years, so is being banned going to make my life any more difficult? No. But these LEDs with flaws are being sold as top grade parts and that has to stop.

                          Comment


                          • calling Slayer007

                            hi Slayer & all,


                            Slayer, could you be so kind as to repost a slightly clearer circuit diagram of the type you attached in post #1 of this thread as i am a little confused by the connections regarding A+ , A-, B+ B-....

                            Thanks a bunch

                            David D

                            Comment


                            • Originally posted by rave154 View Post
                              hi Slayer & all,


                              Slayer, could you be so kind as to repost a slightly clearer circuit diagram of the type you attached in post #1 of this thread as i am a little confused by the connections regarding A+ , A-, B+ B-....

                              Thanks a bunch

                              David D

                              Hello Rave154

                              There is also a differant circuit on page 4 post 117.

                              That one uses two transistors.

                              The dots show the start of the coils.

                              NOTICE that positive A goes with negative B

                              Edit:
                              When I say positive that is just the start of the coil winding.
                              And negitive is the end of the coils.
                              So positive is the start of the coil and negative is the end of the coil.
                              Last edited by slayer007; 06-04-2009, 11:49 PM.

                              Comment


                              • Updated Drawing

                                Hi guys i did a updated drawing of Slayer007 drawing
                                of the Pulse Inverted Joule Thief Circuit
                                Attached Files
                                Last edited by David_Cooksey; 06-05-2009, 05:50 AM. Reason: misspelled words

                                Comment

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