Replicators should try
Okay, something simple that you can do that I hope helps you understand more about how the interface works.
The bulb in my last video that has a completed circuit via my body, if you try to measure current AC or DC, the best I have ever obtained is ~13uA. So that says something does it not? If an equivalent DC voltage of 2.5V@28mA or 2.5 * 2.8E-2 = 70mW then what is the voltage for 13uA. Well 7E-2/1.3E-5 = 5.385E3 or 5,385 volts. Think that could be right?
Now what would happen (I leave this up to you to answer) if one connected to L3 a 10ohm, a 1k ohm, 10k ohm and at last a 20k ohm and completed the circuit by holding the other end as is done with the light. Now to make it easy use a 1/4W carbon. You can (*carefully*) do a lip test, finger should work or get modern and use a temp gun or thermometer. Now why do we see in the resistor (one most of all out of the group) that we do not see from the bulb?
Theory I do not want, I already have the answer, but you need to see and understand this.
Okay, something simple that you can do that I hope helps you understand more about how the interface works.
The bulb in my last video that has a completed circuit via my body, if you try to measure current AC or DC, the best I have ever obtained is ~13uA. So that says something does it not? If an equivalent DC voltage of 2.5V@28mA or 2.5 * 2.8E-2 = 70mW then what is the voltage for 13uA. Well 7E-2/1.3E-5 = 5.385E3 or 5,385 volts. Think that could be right?
Now what would happen (I leave this up to you to answer) if one connected to L3 a 10ohm, a 1k ohm, 10k ohm and at last a 20k ohm and completed the circuit by holding the other end as is done with the light. Now to make it easy use a 1/4W carbon. You can (*carefully*) do a lip test, finger should work or get modern and use a temp gun or thermometer. Now why do we see in the resistor (one most of all out of the group) that we do not see from the bulb?
Theory I do not want, I already have the answer, but you need to see and understand this.
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