Originally posted by Armagdn03
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The capacitive ring will direct its radial potential gradient towards a central point giving the highest potentials near its central axis,
capacitive coupling. Not only does water act as a great dielectric,
but because it is distilled water it will have a higher impedance for current flow
You can indeed use a conductive water (tap water) yet it contains such junk it fouls the works in short order. Don't mess with ionic additives like NaCl etc, kills the action.
if this were the case, it might be reasonable to assume that the L3 was detrimental to the experiment from sitting so close to the test tube in the first video.
difference. This will "pump" the diode. Because it is a rectifier, it will allow the easiest path of conduction to be through its silicon region during one half of the cycle, and during the other half of the cycle through the water, causing unidirectional flow of current.
Very good thoughts and result, looking forward to feedback on the comment answers and questions from you observation.
Oh, about forgot. If you have the instrumentation, look at the pH, you will find it of interest.
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