If the container is the same shape as the item being floated,
can you not float anything in only a 1/4 inch of water surrounding
the item being floated?
If yes, then a 6 volt 120mA solar pump for $25 could do the same amount
of work in one hour as lifting a 5000+ lb car 6 inches off the ground.
The hydrostatic pressure creates the upward buoyancy force.
The magnitude of the buoyant force equals the weight of the displaced fluid (water) ..
The key here is not that it did displace any water, but how much
water would have displaced had any water been there to be displaced.
This is how I fudged the numbers to come up with the estimate of work
that could be done.
So, let us say a cubic foot of water is about 60+ lbs.
If we had a square cubic foot of AIR (a square balloon)
which is held into the water at a depth of 6 inches,
the force pushing upward would be about 30 lbs.
square balloon = 12" x 12" x 6" = 864 cu in
square container of water = 12.25" x 12.25" x 6" = 900 cu in
To obtain a 30 lb upward force requires 36 cubic inches of water.
36 cu in = 0.156 gallon = 0.59 liter
Solar Pump Garden Fountain Pond Water Feature Mini kit
1.0 Watt Solar Fountain Pond Water Pump Panel Brushless
A solar 6V, 120mA pump can pump 150L/H, max height 65cm (2 feet) $25
Say this pump does 100 Liters per hour at a 1 foot head (lift).
That would be 169 strokes @ 30 lbs per stoke = 5070 lbs per hour.
Did I get up on the wrong side of the bed or
does this have something of valve?
If it is of value, What's the COP of that?
Randy
can you not float anything in only a 1/4 inch of water surrounding
the item being floated?
If yes, then a 6 volt 120mA solar pump for $25 could do the same amount
of work in one hour as lifting a 5000+ lb car 6 inches off the ground.
The hydrostatic pressure creates the upward buoyancy force.
The magnitude of the buoyant force equals the weight of the displaced fluid (water) ..
The key here is not that it did displace any water, but how much
water would have displaced had any water been there to be displaced.
This is how I fudged the numbers to come up with the estimate of work
that could be done.
So, let us say a cubic foot of water is about 60+ lbs.
If we had a square cubic foot of AIR (a square balloon)
which is held into the water at a depth of 6 inches,
the force pushing upward would be about 30 lbs.
square balloon = 12" x 12" x 6" = 864 cu in
square container of water = 12.25" x 12.25" x 6" = 900 cu in
To obtain a 30 lb upward force requires 36 cubic inches of water.
36 cu in = 0.156 gallon = 0.59 liter
Solar Pump Garden Fountain Pond Water Feature Mini kit
1.0 Watt Solar Fountain Pond Water Pump Panel Brushless
A solar 6V, 120mA pump can pump 150L/H, max height 65cm (2 feet) $25
Say this pump does 100 Liters per hour at a 1 foot head (lift).
That would be 169 strokes @ 30 lbs per stoke = 5070 lbs per hour.
Did I get up on the wrong side of the bed or
does this have something of valve?
If it is of value, What's the COP of that?
Randy
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