Pulsed energy capture circuit

[SkyWatcher]

Hi folks, i posted this in big joule thief thread but thought the results were interesting enough to start a thread. Just want to share an interesting circuit I've been testing. It captures normally wasted energy similar to whats called a tesla switch. It also lights up the halo bulb equally well as it did without the energy capture. Reason for using the lower voltage 1.2V rechargeable cells in parallel was to make it more efficient, similar to the idea of Peter L's attraction motor, less counter voltage to detract from input. heres a cad pic, hope you find it useful.

[Sephiroth]

I'm interested in:

"Step down transformer used as step up transformer"

Could you describe the transformer please?

I'm afraid I have a lot more questions

Would you mind posting measurements like input current, output current, voltage across the halogen, how you would describe the brightness of the halogen as a percentage of "full" brightness, power rating of the halogen, frequency, and duty cycle.

Don't want much, do I? No pleasing some people....

[SkyWatcher]

Hi Sephiroth, the transformer I'm using was from a battery powered drill charger, though wall warts or other small trafo's. would work, i'm using it as a step-up transformer. I'm not running a halogen bulb, its a fluorescent round, ring, halo shaped bulb like Lidmotor is using in one of his efficient setups. The transformer I've been using that works the best, here is the resistance numbers for transformer.
low voltage winding = approx. 400 milliohms
high voltage winding = approx. 12.6 ohms
I'm using a darlington pair to power it and frequency is around 1.4 khz, adj. with pot of course. it can light from 200 milliamps on up at 12volts at usable brightness levels. The whole idea here as Bedini has shown something similar to this, was to increase the efficiency by using the lower voltage receiving charge battery bank and hope to extend the run time of the bulb by swapping the battery banks back and forth, and in this case it may be more efficient this way. The batteries in the charge side are charging up good and if we increase load on transformer secondary it gives us even better charging.
as far as light output, compared to using a normal one battery 12v pulse driving the transformer, the light output is the same and is more than adequate I must say, it illuminates a whole room where you could read a book at any point in the room even at 300 miiliamps, with only a minor pulse width on time adjustment to compensate for the fact that we now have 1.2volts countering our 12v input voltage, but as far as the transformer primary being between two negative polarities I don't see any difference. hope that helps so far, and feel free to ask any more questions or offer your own input.
peace love light
Tyson

[nvisser]

Can you try 2 x 12v batt. in series (24v) as drive and then 2 x 12v batt. in parralel (12v) as charge battery in the same setup. That would give a voltage drop of 12v over the transformer coil and maybe better cfl brightness.
That will be exactly like the Tesla switch and very easy to swop batteries.
As I understand it with that kind of setup where the load does not draw a lot of current nearly all the current that goes through the load (coil in this case) will be used by the 2 parralel batteries to recharge them. When the load draws a lot of current some of the energy gets wasted as the batteries cannot charge so fast with electron current. I ran a setup like that with a 6 pole 2 way switch that could swop the batteries from parralel to series and vice versa like in the tesla switch. Of cause unlike the tesla switch it was only switched ones or twice a day. With a motor as load connected between the positives or the negative of the 2 sets of batteries, the parralel set charge as much as the series sets lost in voltage if the load draw only about 100mA.

[SkyWatcher]

Hi nvisser, I have already in the past run those tests. The main idea here is to lessen the counter voltage between source battery bank and receiving battery bank. With the arrangement you speak of we would have 12volts of counter voltage whereas with this setup we only have 1.2volts of counter voltage. I thought this concept would be fairly easy to see.
peace love light
Tyson

[SkyWatcher]

Hi folks, by the way thanks for the replies so far.
nvisser you said quote "When the load draws a lot of current some of the energy gets wasted as the batteries cannot charge so fast with electron current."
what you say here is true, however it would be 100% wasted anyway after it did useful work in a load and then more work by destroying the dipole in the source battery. Its the latter that I'm pointing out here, instead of the normal loop circuit that depletes the source battery at least here we are taking the energy that would deplete it and are charging a receiver battery bank, so even if it can only receive the energy at 50% efficiency its better than nothing and on top of that we still have the work done at load and the subsequent collapsing fields can be used from a coil. So we input 1 unit, get 1 unit of work in load, 1 unit of work in charging receiver batteries and 1 unit from coils collapsing field. That is 2 extra units of energy above what we input minus losses. I hope that makes my thoughts more clear on what I think is happening with this setup. Any comments are welcome.
peace love light
Tyson

[nvisser]

Exactly
Go look at double d`s circuit on this thread
http://www.energeticforum.com/renewa...switch-11.html
I am slowly busy buiding his tesla switch circuit. He claims the mosfets runs cold. In fact they froze!
It will take some time to get it finished though

[SkyWatcher]

Hi nvisser, thanks for reply. Yes thats interesting because I'm noticing with this simple circuit that my receiver batteries are not heating at all and may be getting cooler. Sounds like the Adams motor I built where the coils and transistor became cold. thanks.
peace love light
Tyson

[Lidmotor]

SkyWatcher--CFL and Charger using wall outlet transformer

@SkyWatcher
Tyson--I replicated the WHOLE thing and posted a video of it. . Unbelievable until you do it and see it working. Now lets all figure out WHY.
I not only got the FL to light up off the wall outlet transformer but your Tesla Switch idea worked also. In the video I use a super capacitor but I also tried the 1.5volt batteries and it charged them up too just like you said. This might be stealing the energy from the battery some way but I sure could not figure out how. It seems to do just what you said and capture otherwise wasted energy.
Well done Tyson. It works!
I would love to see more replications of this from other folks with more knowledge on the topic.
Here is the video of my replication:

YouTube - SKYWATCHER-- CFL and Charger using wall outlet transformer

Lidmotor

[SkyWatcher]

Hi Lid, very nice video there. As far as why, if you mean it lighting the fluorescent, I would say it's the collapsing field making a higher voltage in the secondary beyond what the turns ratio can offer similar to an ignition coil. I was testing the cap idea your using as well, however another interesting setup is to put a cap in-line with a 12volt battery and a 1.2volt bank, so if using the positive rail, put the positive of cap at the 12V battery and the negative at 1.2v battery and it charges the cap, which makes me wonder if polarity as its called is only a vector direction of flow. Then you can use the caps energy in a pulse circuit or whatever and it will still charge the receiver battery bank. This may or may not be more efficient, just something i was testing and it is curious that cap charges just fine that way. Great work though.
peace love light
Tyson

[SkyWatcher]

Hi folks, I was doing some calculations and are based on an assumed 80% efficient recovery from the captured energy. Although it may be more or less in practice. These numbers are quite astonishing, I based it on a 10 watt input for an hour, so 10 watt/hours used total and when applying this capture method these are the results.
1) Energy used to power main load acquired from recovery - 35 watt/hours
2) Captured energy - 36 watt/hours
3) Total Captured - 71 watt/hours
Now to make clear what this means, we input 10 watts, we get back 8 watts, we them reapply it through the system while lighting the bulb for another 8 watt/hours yet again while capturing 80% which is 6.4watt/hours then reapply that 6.4watt/hours and get 6.4watt/hours of light while capturing 5.12watt/hours and on, and on till we have depleted what we initially input.
peace love light
Tyson

[DrStiffler]

@SkyWatcher
Tyson--I replicated the WHOLE thing and posted a video of it. . Unbelievable until you do it and see it working. Now lets all figure out WHY.
I not only got the FL to light up off the wall outlet transformer but your Tesla Switch idea worked also. In the video I use a super capacitor but I also tried the 1.5volt batteries and it charged them up too just like you said. This might be stealing the energy from the battery some way but I sure could not figure out how. It seems to do just what you said and capture otherwise wasted energy.
Well done Tyson. It works!
I would love to see more replications of this from other folks with more knowledge on the topic.
Here is the video of my replication:

YouTube - SKYWATCHER-- CFL and Charger using wall outlet transformer

Lidmotor

@All

Well you all are heading in a good direction, albeit prepare for the screams and shouts from the EE's on this, they will and do defend this as totally incorrect observation and and measurement.

Two circuits where this has been explored from my work is the CRE (Charge Recycled Electrolyzer) and the ESEC of (Exciter Stimulated Energy Coherence) where a truly AC oscillator charges a SuperCap.

Good work fellows and do not let this die, get your ducks in a row so you all can battle the fire starters.

[Lidmotor]

The "green light" from Dr. Stiffler

@ Tyson & All
I have been studying and replicating the work of Dr. Stiffler for months now and when he says "Yes" or "No" I listen carefully. I hear a "Yes" here. I am working on one of his circuits right now (ESEC) that charges a cap in a similar way to Tyson's circuit. The energy runs through it and it charges it up. I haven't gotten it to work yet but after doing this experiment and reading his comment, I believe in the idea.

Lidmotor

[DrStiffler]

THe Deep Trap and Truth

@All

When I say get you ducks in line, what I mean is be sure you are looking at the powers properly. Match Joule for Joule.

Here is the simple way to do it, open for expansion but the best starting point.

If yo have say a 10V battery and you are drawing 100mA (constant, no variation) that says that you are at 10 * 1E-1 = 1 Joule per second or one wattsecond. Now if you run the circuit for say 60 seconds you have 60 * 1 or sixty Joules total. Now compare that to the charge on the capacitor; say its a 1F and you get 2V therefore it has the potential of (1*2^2)/2 or 2 Joules.

So this says we pulled from the source 60J and have 2J on the cap so how much did the FL consume 58J? If not then this is a really inefficient system.

So you need to factor in time in all of you calculations, you pay the utility for Joules over time, in fact 1KW hour is 3.6E6 Joules or 3,600,000 so you can see why time is required.

So in my example if applied to what is going on here, where is the potential energy, only in the cap so those ducks need to take into account what that FL produced in both Heat and Light converted to Joules so you can obtain a balance. In reality you also have the 555 suffering some Heat loss as well as the cap itself by a number of factors.

The mistake we all make (me included) is to jump to fast and have not produced a full and accurate assessment of the parts.

Do indeed keep at it as I stated, but these particular configurations are probably 45-60% eff.

Sorry "Lidmotor" I may have given the wrong impression. As the fire starters say, "Its all in the numbers"

[Lidmotor]

The numbers

@All

When I say get you ducks in line, what I mean is be sure you are looking at the powers properly. Match Joule for Joule.

Here is the simple way to do it, open for expansion but the best starting point.

If yo have say a 10V battery and you are drawing 100mA (constant, no variation) that says that you are at 10 * 1E-1 = 1 Joule per second or one wattsecond. Now if you run the circuit for say 60 seconds you have 60 * 1 or sixty Joules total. Now compare that to the charge on the capacitor; say its a 1F and you get 2V therefore it has the potential of (1*2^2)/2 or 2 Joules.

So this says we pulled from the source 60J and have 2J on the cap so how much did the FL consume 58J? If not then this is a really inefficient system.

So you need to factor in time in all of you calculations, you pay the utility for Joules over time, in fact 1KW hour is 3.6E6 Joules or 3,600,000 so you can see why time is required.

So in my example if applied to what is going on here, where is the potential energy, only in the cap so those ducks need to take into account what that FL produced in both Heat and Light converted to Joules so you can obtain a balance. In reality you also have the 555 suffering some Heat loss as well as the cap itself by a number of factors.

The mistake we all make (me included) is to jump to fast and have not produced a full and accurate assessment of the parts.

Do indeed keep at it as I stated, but these particular configurations are probably 45-60% eff.

Sorry "Lidmotor" I may have given the wrong impression. As the fire starters say, "Its all in the numbers"

OK. I knew there had to be something that I was missing. Thanks One can't forget about "Time" in the calculations.
Oh well this does make a neat little light but 45-60% efficiency is not so good.

Lidmotor