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  • ricards
    replied
    analogy

    Originally posted by Dwane View Post
    Hi,
    This concept is difficult to absorb. Let me see if I have an explanation. In a Don Smith circuit, when driving the L1 coil, the reactive power is the voltage sent to L2 when the spark gap fires? The reactive power becomes absorbed through inductive transfer by L2? But, as very little amperage is transferred, L2 becomes a container for Reactive power. We then have to be able to join this inductor to a capacitive source to obtain useable Power? Would this be what is happening?

    Regards

    Dwane
    hi dwane,

    reactive power is as simple as,
    when you push a swing and the swing comes back.
    action = reaction.

    aside from the phase shifts, which only you would understand if you graph the voltages and currents. it's all very simple.

    Leave a comment:


  • med.3012
    replied
    Originally posted by Dwane View Post
    Hi,
    This concept is difficult to absorb. Let me see if I have an explanation. In a Don Smith circuit, when driving the L1 coil, the reactive power is the voltage sent to L2 when the spark gap fires? The reactive power becomes absorbed through inductive transfer by L2? But, as very little amperage is transferred, L2 becomes a container for Reactive power. We then have to be able to join this inductor to a capacitive source to obtain useable Power? Would this be what is happening?

    Regards

    Dwane
    Hi !

    the reactive power circulate between L1 and the tank capacitor , it has all the impact of active power with one critical defect... , there's a 90° phase shift between voltage and electric current , which mean it need a simple correction possible if we use the ETBC as primary coil, at this moment we need a good circuit can do that , after i think the puzzle will be solved i hope



    regards

    Leave a comment:


  • ilandtan
    replied
    Originally posted by Dwane View Post
    Hi,
    This concept is difficult to absorb. Let me see if I have an explanation. In a Don Smith circuit, when driving the L1 coil, the reactive power is the voltage sent to L2 when the spark gap fires? The reactive power becomes absorbed through inductive transfer by L2? But, as very little amperage is transferred, L2 becomes a container for Reactive power. We then have to be able to join this inductor to a capacitive source to obtain useable Power? Would this be what is happening?

    Regards

    Dwane
    I think that's close, to my perception as well. A correctly constructed tesla coil will build "huge currents" (resonance) with the proper grounding (Ref: Stefan's Tesla coil pages - RF-gnd) That is in the RF. A capacitively coupled receiver will be able to receive that energy between Coil and Earth ground. Because your output load does not affect your input resonance, you can store that energy in capacitors(bank). From then on it's just conversion to usable format, because your capacitors become a power supply. You're compression is your Tesla transmission where you wind the power like a spring, When you receive it, it can be unwound and stored, used.

    There may be mitigating prerequisites to allow this to happen. Usable ambient energy present - as per dynatron

    Or at a frequency that allows the Earth to re-enforce the resonance

    Rick Friedrich made the statement that you have to know where to ground and when.

    My thoughts are that L1 (the HV module) grounds to the battery[isolated], L2 has to ground [Earth] to draw the RF wave, and the receiver needs to return the energy back to ground [Earth].

    It's not the parts, it's the system

    Leave a comment:


  • Dwane
    replied
    Reactive Power

    Originally posted by med.3012 View Post


    Hi Dwane !


    anytime there's a phase shift between voltage and current you have reactive power , but most likely combined with active power which do real work, reactive power is used to rise the voltage in case of huge electricity demand .. we use the reflected voltage component that came from the electric current itself so we can transport active power again effectively.. this phase shift help the system to relax !

    in our case imagine you have 10W of active power the AC voltage is 220 V ,the current is 45 ma but you need say 40 A with 100 V ? ! here it's possible to achieve this gain but you have to put your system in full relaxation this mean active power is zero .. it's like you convert voltage to current directly but at the moment when you have a max current the voltage is zero , now we are working with a pure reactive system ! this is a huge virtual gain in electric current, using the simulation software you see the input power can be as small as 5 W but the output can achieve 1000 VAR !!!


    now because the ETBC handle its capacitor with inductance you can correct the phase easily since both present together all the time .. there's other details can be added here but first we have to success in creating reactive power !


    regards
    Hi,
    This concept is difficult to absorb. Let me see if I have an explanation. In a Don Smith circuit, when driving the L1 coil, the reactive power is the voltage sent to L2 when the spark gap fires? The reactive power becomes absorbed through inductive transfer by L2? But, as very little amperage is transferred, L2 becomes a container for Reactive power. We then have to be able to join this inductor to a capacitive source to obtain useable Power? Would this be what is happening?

    Regards

    Dwane

    Leave a comment:


  • med.3012
    replied
    Originally posted by Netica View Post
    Thanks Med.3012

    I will look a bit further in your thread.

    Just one thing I would like to point out.

    The picture you have in your pdf of one of don smiths devices Fig24.

    I have looked carefully at this coil in his videos and can see that it is just one continuously wound coil all in the same direction and opened up in the center where the central connections are made.

    Netica

    maybe, but he mentioned the importance of CW and CCW , there's no detailed photo of his device , so the most important source of info is his words in his video.

    Leave a comment:


  • Netica
    replied
    Thanks Med.3012

    I will look a bit further in your thread.

    Just one thing I would like to point out.

    The picture you have in your pdf of one of don smiths devices Fig24.

    I have looked carefully at this coil in his videos and can see that it is just one continuously wound coil all in the same direction and opened up in the center where the central connections are made.

    Netica

    Leave a comment:


  • ilandtan
    replied
    Originally posted by med.3012 View Post
    Tesla : Hello Med how are you ?
    Me : all is well thanks , you ?
    Tesla : fine too --smile--
    Me : what do you think about the ETBC ?
    Tesla : It's a distraction




    just for smile , i didn't asked you to build the ETBC , i just need a technical help in electronic this is why i am posting here
    I stand corrected... It really is a huge distraction! LOL

    Leave a comment:


  • med.3012
    replied
    Originally posted by Netica View Post
    Hello Med.3012

    I was interested with your pdf but I don't understand what the diagrams are symbolizing in fig's 5,6 and 7. The red and black dome shapes.

    You are talking about coils and capacitors but I can not relate what you are saying to these diagrams.

    Can you please explain what they are supposed to be and how they relate to what you are trying to explain.

    Thank you
    Netica

    Hello

    please follow the answer in my thread here :

    http://www.energeticforum.com/renewa...lained-28.html

    it's better to move again to my lovely place so i feel conformable, i hope you understand

    welcome

    Leave a comment:


  • Netica
    replied
    Originally posted by med.3012 View Post


    @ilandtan

    hello

    the most important thing is the amplification factors, any coil or capacitor or whatever combination if there's no increased oscillation when the system is isolated from excitation / power source it's most likely the system can't produce such effect ... at least there's no huge gain as described by Don Smith

    the ETBC has this capability, i described this in my PDF ( part 2 )

    www.free-energy-info.com/Mohamed.pdf

    why an increased oscillation is so important even we can't use it in practice since the system will produce thousand of amps which can't be controlled ? --- Don Smith 1995 video -----

    simply because you need an internal feedback which change the magnetic field to electrostatic field within the system itself ( ETBC conducting foils ) the magnetic field tend to charge the capacitance instantly with no delay , this what produce double frequency behavior ..

    if you make a relatively large ETBC the increased oscillation can be seeing with scope, any magnetic field enter the ETBC will be translated immediately to static field through the no conservative rotating electric field , here you can change the reactive electric power into active power !!!!

    the ETBC will store this electric field and push another magnetic quantity both at the same time !!!

    i think the best is to start experiments rather than argument ..

    regards


    Hello Med.3012

    I was interested with your pdf but I don't understand what the diagrams are symbolizing in fig's 5,6 and 7. The red and black dome shapes.

    You are talking about coils and capacitors but I can not relate what you are saying to these diagrams.

    Can you please explain what they are supposed to be and how they relate to what you are trying to explain.

    Thank you
    Netica

    Leave a comment:


  • med.3012
    replied
    Originally posted by ilandtan View Post
    Well I won't build an EBTC. It's a distraction for me.

    Show me it works, and I might.

    Tesla : Hello Med how are you ?
    Me : all is well thanks , you ?
    Tesla : fine too --smile--
    Me : what do you think about the ETBC ?
    Tesla : It's a distraction




    just for smile , i didn't asked you to build the ETBC , i just need a technical help in electronic this is why i am posting here

    Leave a comment:


  • ilandtan
    replied
    Originally posted by med.3012 View Post
    the problem with an ETBC is the excitation system .. you need a relatively large current to excite it plus higher impulse rate, the more you pulse it the more power, it's possible to rise the voltage or step it down , you can use it in Mazilli driver and it oscillate perfectly, it work in Collpit or Hartley oscillator , in Mazilli driver you can take the power from it when it oscillate without further coil ! [/IMG]

    the points c prime D prime are free but you can take power from them and light a bulb !! in the above drawing those point are facing C and D which make a fixed potential !!! this mean the electrons are separated in these point , so the capacitor is talking with inductance ..in other word this special coil can differentiate the electrons based on their spin ..

    maybe the best solution is to excite it using reactive power , we can use large current with large voltage while we use few watts input , the modern electronic is more advanced now then Don smith days .
    Well I won't build an EBTC. It's a distraction for me.

    Show me it works, and I might.

    Leave a comment:


  • med.3012
    replied
    Originally posted by ilandtan View Post
    So I think that's one problem you have with an EBTC, if you make both both plates the same length, you are gaining no voltage step up or in the reverse step down. I guess it implies that it might be used best as an isolation transformer if you never join the plates, and leave a capacitive coupling. But where Don takes a voltage and makes few a few L1 windings drive many windings in the L2. The free transformation is not gained.

    the problem with an ETBC is the excitation system .. you need a relatively large current to excite it plus higher impulse rate, the more you pulse it the more power, it's possible to rise the voltage or step it down , you can use it in Mazilli driver and it oscillate perfectly, it work in Collpit or Hartley oscillator , in Mazilli driver you can take the power from it when it oscillate without further coil !

    the points c prime D prime are free but you can take power from them and light a bulb !! in the above drawing those point are facing C and D which make a fixed potential !!! this mean the electrons are separated in these point , so the capacitor is talking with inductance ..in other word this special coil can differentiate the electrons based on their spin ..

    maybe the best solution is to excite it using reactive power , we can use large current with large voltage while we use few watts input , the modern electronic is more advanced now then Don smith days .

    Leave a comment:


  • ilandtan
    replied
    Originally posted by med.3012 View Post


    @ilandtan

    hello

    the most important thing is the amplification factors, any coil or capacitor or whatever combination if there's no increased oscillation when the system is isolated from excitation / power source it's most likely the system can't produce such effect ... at least there's no huge gain as described by Don Smith

    So I think that's one problem you have with an EBTC, if you make both both plates the same length, you are gaining no voltage step up or in the reverse step down. I guess it implies that it might be used best as an isolation transformer if you never join the plates, and leave a capacitive coupling. But where Don takes a voltage and makes few a few L1 windings drive many windings in the L2. The free transformation is not gained.

    Leave a comment:


  • med.3012
    replied
    Originally posted by ilandtan View Post
    Med,

    I will never dictate other's efforts, just give my honest opinion. If you show me tomorrow that you can drive a motor with just a few input watts, I would welcome the knowledge.

    Good Luck!

    X


    i understand in 2001 video he also gave a hint about his device :

    https://youtu.be/mHhfNjPk7o4

    Don explain how the right diameter with the right Height can give plenty of amps and volts , someone asked if there is a golden ratio ( this was in the same video ) but he replied no ...

    i am also publishing my point of view honestly !

    thank you

    regards

    Leave a comment:


  • ilandtan
    replied
    Med,

    I will never dictate other's efforts, just give my honest opinion. If you show me tomorrow that you can drive a motor with just a few input watts, I would welcome the knowledge.

    Good Luck!

    X

    Leave a comment:

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