Different diode give different radiant output current

[sucahyo]

I found out that different diode may have siginicant difference of resistance/impedance. 1N4007 measured as 500 using 2000K setting of my ohm meter. FR302 shown as 450. I found a couple of diode which has resistance of under 100 in few weeks back, 1N5822 and SB?040CT series. I already suspect the difference but never test it. I decide to do comparation test:

YouTube - Diode important role on output current

The result is, 1N4007 is the weakest, FR302 give around 20% more, SB1040CT give around 35% more. This seems to relate more to amperage rating than impedance, so excuse the reasoning in the video. Also excuse for tha lack of audio synchronization which make viewing unpleasant.

1N4007 rate as 1A, Maximum Instantaneous Forward Voltage is 1.1V at 1A
FR302 rate as 3A, Maximum Instantaneous Forward Voltage 1.3V at 1.5A
SB1040CT rate as 10A, Maximum Instantaneous Forward Voltage 0.5V at 5A

Wether this data is relevant or not, SB1040CT give the best output current. I got it from broken computer power supply in TO-220AB shape.

If anyone has 100+Amp diode, I would love to know wether it will give more radiant output than what currently being used.

[Zooty]

do you mean current output as in amps?

[theremart]

Diodes...

Other things to try...

1. use multiple diodes put 4-5 in in the same place. see what a difference this makes..

2. measure over the output diode. want to get an quick idea of how much you are hitting the battery put a multimeter on the anode and cathode of the diode for an interesting reading.

I have several types of diodes but I have not taken the time to test them each... I think you have a great idea here.

One thing if you have energy from the vacuum series. take a CLOSE look at the circuits. You will find some rather large diodes.

[nvisser]

The diodes that this guy uses are the MUR410. http://www.energeticforum.com/renewa...ead.php?t=4867
· High Surge Capability
· Low Leakage
· Low Forward Voltage Drop
· Ultra Fast Switching Speed For High Efficiency
Reverse Recovery Time 60nsec
I think it is the speed of the diode that makes the difference here when you are looking for radiant energy
Aint we looking for very fast switching high voltage spike with very little current?

[sucahyo]

do you mean current output as in amps?

yes.

1. use multiple diodes put 4-5 in in the same place. see what a difference this makes..

Yes, this improve output. I have 7 FR307 (same as 1N4007, forget to include it in video) which perform as good as SB1040CT.
Edit: using digital meter 7 x FR307 output current is slightly less than SB1040CT.

2. measure over the output diode. want to get an quick idea of how much you are hitting the battery put a multimeter on the anode and cathode of the diode for an interesting reading.

I see the same voltage as measured on the battery. What do you mean?

One thing if you have energy from the vacuum series. take a CLOSE look at the circuits. You will find some rather large diodes.

I see. Thanks for the info .

I think it is the speed of the diode that makes the difference here when you are looking for radiant energy
Aint we looking for very fast switching high voltage spike with very little current?

Voltage without current will only fluffy charge the battery and eventually make the battery unusable. The key is h shaped waveform, where a spike is followed by some current. But I maybe wrong.

Unfortunately I don't have scope so I can't do comparation of slow diode vs very fast diode.

I am thinking that at the recovery part the diode should has as little as resistant as possible to avoid diode become part of the load. I don't see fast diode is needed because we need the diode to prevent the charged battery to power the radiant coil, where there is chance that slight bounce back from the battery would actually improve circuit efficiency.

Allowing as much current, highest voltage in a forward mode is what we need. We should allow as much radiant stream as possible in forward mode to be able to capture more of the aether energy. I think reverse voltage, blocking voltage, voltage leakage, or reverse recovery time is not important because we don't collect it at reverse mode. I think forward recovery time, or Maximum Instantaneous Forward Voltage is what important.

MUR 405 mentioned to has 4 Amp capability, I think it would has the same performance as FR302.

[dambit]

I don't see fast diode is needed because we need the diode to prevent the charged battery to power the radiant coil, where there is chance that slight bounce back from the battery would actually improve circuit efficiency.

Allowing as much current, highest voltage in a forward mode is what we need. We should allow as much radiant stream as possible in forward mode to be able to capture more of the aether energy.

Hi Mate,

Remember what Bedini said, "if you have current , you've got no radient."

Now, we do need a small amount of current to kick start the charge process, but this should be as small as practical (based on battery size). IMO the faster we can collapse the coils field, the larger the radient spike will be, and the more efficent the charge process.

Comparing my wave form to that of Bedini's in EFTV 2, he must be using high speed diodes (knowing him, probably mil-spec) because his h-wave actually looks like a "h". Most of ours look like elongated h's. Also, with faster switching we can hit the battery with more spikes in the same amount of time.

Cheers,

Steve

[sucahyo]

Hi Mate,

Remember what Bedini said, "if you have current , you've got no radient."

Now, we do need a small amount of current to kick start the charge process, but this should be as small as practical (based on battery size). IMO the faster we can collapse the coils field, the larger the radient spike will be, and the more efficent the charge process.

Do you know at what spesific time Bedini mention that to? after collapse or before switch off?

I take that phrase as get as low current as possible in the coil. Bedini mention that to charge a battery you need current too.

his is the essence of the “regauging” that Bearden talks about so much. It is believed that any experimenter trying to duplicate the work of JB needs to keep firmly in mind that the waveform is the final goal.

The output from the SSG contains a HV component spike combined with a small current component. This current component is the “few electrons” that JB says we need and what is referred to by some as the threshold current. This threshold current puts the battery into a charge state, rather than its
usual resting self discharge state. As the battery conditions (after many charge and discharge cycles), the internal resistance is lowered, (the plate surface area is increased as well) meaning that we need even less threshold current to place the battery into the charge mode. Over all this process
is also a good basic experience with DC power sources in impulse current configuration.

My current circuit draw 150ma, output 90mA using less than 1 ohm load. which is much less than the required instruction by John Bedini.

John has suggested testing the output of an SG machine using a 1ohm resistor. If you measure less than 1V on the output then clearly there is less than 1W actually charging the battery as far as conventional understanding is concerned.

1V at 1 ohm to produce 1 Watt require 1Amp of current.

I think radiant will be accompanied with current if the output part have low impedance.
YouTube - Joule thief can light up neon or charge battery but not both.

Comparing my wave form to that of Bedini's in EFTV 2, he must be using high speed diodes (knowing him, probably mil-spec) because his h-wave actually looks like a "h". Most of ours look like elongated h's. Also, with faster switching we can hit the battery with more spikes in the same amount of time.

Agree, this is the reason using KHZ range solid state might be better than mechanical which require 2 second to fire.

[Sephiroth]

I agree with dambit... there is no radiant when there is current. The radiant precedes the current so for maximum radiant output you want to use the fastest switching diode you can find. I like the UF4007 just because it is the super speedy equivellant of the 1N4007 though there could be better diodes out there.

Though comparing the current output using different diodes is an interesting experiment.

A few quotes from John's website:

Their are no meters to measure this radiant current

If you kill the dipole you loose the energy. The dipole killer is the electron current in the circuit.

Very reputable experimenters besides Tesla continued claiming that "space flowing electricity" is the real electricity. Tesla's classic demonstrations proved that rapid electrical impulses actually exceed the ability of fixed charges to transmit the applied forces. Charges lag where electrostatic forces continue propagating. One is compelled to see that electrostatic forces precede the movement of charges.

and a quote from Peter Lindemann
http://www.energeticforum.com/renewa...nt-energy.html

According to Tesla, the "fast transient phenomena" is a Longitudinal Wave, a time compressed zone of electrostatic charge or pure voltage, traveling ahead of the electron current. It appears BEFORE the current starts moving and is separate and distinct from it.

Edit : Forgot to point out that this is all theory... i can't vouch for it personally since I haven't confirmed it.

[Bodkins]

100 Vishay 1n5062 800V 2A Best Sound Diode 2a3 300b

100 Vishay 1n5062 800V 2A Best Sound Diode 2a3 300b

I have found these diodes to give amp from sunlight with a magnifing glass also on the sec used like a av plug the result where higher than the stock 1n4148s.
if you have some play with then.......amps from sunlight
sound diodes (first there was sound!!!)

[dambit]

Do you know at what spesific time Bedini mention that to? after collapse or before switch off?

I take that phrase as get as low current as possible in the coil. Bedini mention that to charge a battery you need current too.

He talks about it several times throughout the DVD. Would have to view it again to know exactly when.

At the moment I am restoring a moderate starter battery (660 CCA). I am inputting 375mA per coil (15 in total = 6A) and the charger is outputting roughly half of that to the battery (conventional amps). I am using a more forceful charge than I normaly would because it is sulphated and not conditioned. I fully expect to have to reduce the current going to the battery as it improves and becomes conditioned, but the spikes will still be there.

I believe that the spike itself is not the radiant, but when it hits the battery it facilitates a condition in the batteries chemistry which allows the real radiant to pour in and charge the battery. I think that this is the reason we need faster swiching, so as to hit the battery with as many spikes in as short a period of time that we can.

At the moment I can fully charge it from 11.8V to 15V in about 3 hours (rests at 12.78V). I consider this to be pretty good when compared to the amount of current going to the battery. Yes I am drawing a fair bit from the wall, but a normal charger would draw a lot more to achieve the same charge time with a new battery. Plus in time, when the battery is restored and conditioned, it will probably only require half the current to kickstart the charge. I hope

@ Seph,

I have found many diodes that are capable of ultra fast switching, but not many that can handle the current or the voltage. I'll have to get some of the UF4007's, they sound pretty good.

Cheers,

Steve

P.S. Hope I didn't ramble too much.

[nat1971a]

thanks for posting this!!!

[sucahyo]

Thanks for the photo diode info Bodkins .


About charging a battery, maybe current may remove the radiant but I don't think it will remove it entirely. On conventional knowledge, charging is a function of current. High ampere will charge the battery faster, where high voltage will make it heat up faster. Usual means to force more current to the battery is by using higher voltage.

My circuit now can charge 1000mAh nicad in two hour using 130mA input at 12V without the nicad ever heat up! While conventionally it would need 2700mA to charge for an hour, 300mA to charge for 24 hour and still heating them up considerably. Since I now charge the battery about 10 times more efficient than conventional methode, the only explanation for this are the existence of radiant current. Radiant current still exist on my circuit.

SB1040CT diode info is:
Low power loss, high efficiency
High current capability, low forward voltage drop
High surge capacity
For use in low voltage, high frequency inverters

Even with indicated low voltage usage, the direct radiant output is still high enough to light up a neon bulb. The electrode only light up brightly at one side indicating that the diode really transfer more than 70V DC.

I still interested on the difference between slow and fast diode in charging. On open measurement diode with higher internal resistance would show higher output voltage.

The quote bellow is my base for not useing pure radiant to charge battery. There must be limit on how low the current need to be.
From John Bedini Technology.pdf:

John and I built all three pendulum machines together. I was there. The circuits were test circuits based on John’s unique insights into this process. The circuits were John’s, but I helped build the frames, pendulums, and coils. I also tested some of these units for weeks. John has not disclosed the
circuits he used so I can’t either. I will say that they were similar to SSG circuits, but not exactly the same.

The system sent charge to both the run battery and the charge battery. I ran several tests where the run battery did not discharge AT ALL over a 4 day run. The charge batteries LOOKED LIKE they were charging very rapidly. The problem with the system was that the circuit returned ALL of the electron current to the run battery and sent pure Radiant Energy to the charge battery. After a while, the charge batteries all DIED!!!!!

This helped prove Bearden’s Theory that you need at least A FEW electrons in the system. Pure Radiant Energy does NOT charge batteries. All of Tesla’s circuits show Radiant Energy lighting light bulbs and running motors, but NEVER charging batteries. Now we know why.