Current measuring often causes problems and errors. The thing is, once you strike up an exciter, you'll have HV pulses travelling along DC wiring.
Powering from a wall adapter, you can use an AV plug and LED and see the LED light right up to the wall plug. So, the multimeter is going to see that HV as well.
Putting the meter in series with the Positive supply will give you a reading, but is it correct, if we consider the way that a meter can run all over the place inside an excited field ?
Another way, is to put a 1ohm resistor in the same place. Measure the voltage across that resistor and it will show the amperage (Ohms Law E/R = I), easiest with 1ohm. 50mV will be 50mA, but is subject to the tolerance of the resistor...5% will carry a possibility of a 5% error.
More info here: measuring current using 1ohm resistor. How? - diyAudio
Powering from a wall adapter, you can use an AV plug and LED and see the LED light right up to the wall plug. So, the multimeter is going to see that HV as well.
Putting the meter in series with the Positive supply will give you a reading, but is it correct, if we consider the way that a meter can run all over the place inside an excited field ?
Another way, is to put a 1ohm resistor in the same place. Measure the voltage across that resistor and it will show the amperage (Ohms Law E/R = I), easiest with 1ohm. 50mV will be 50mA, but is subject to the tolerance of the resistor...5% will carry a possibility of a 5% error.
More info here: measuring current using 1ohm resistor. How? - diyAudio
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