Lately, there have been many pleas to disclose information on FE and OU systems. Researchers have not come forward to release any information to satisfy the requests. I am going to release some of my designs. These are to be open sourced, as anyone can build or replicate. I have not had a chance to build this design yet, but theoretically it should work just fine. It not only should self sustain, but produce excess energy to drive a gnerator or other machinery. Although a slow moving machine, it can be geared to satisfy greater RPM. The only thing I request is that anyone who builds it, post a picture and or any improvement, so other replicators can save time experimenting. If my calculations are correct, it should produce 3 foot pounds of excess energy,OU. Keep it super simple. Stealth
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KISS- Gravity Motor
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The only thing required would be to replace the water in the top reservoir every few days due to evaporization. And adding anti-freeze in the winter. The bearings should run years without further lubrication if synthetic grease is used. Good Luck. Stealth
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Things are starting to slow down, for good or bad, so it seems I may have some time on my hands after first of the year. I may get time to actually build some of these projects I've designed to see how well they work. Some of you may have already started building this one, if so, I wish you good luck.
I have decided to build this one from 1'' steel conduit pipe, when I get started. It's fairly light weight, strong and galvanized to prevent rust. The arm should be made as light as possible, so I think I will use aluminum tubing for that. The weight will be from a barbell weight set. Keeping the ratio I've given, it should take 2 pounds of thrust to recycle the water to the reservoir. You only need to replace as much as you use, in this design it is 16 ounces(1 LB), leaving an excess of 3 foot pounds of OU energy to power a generator or other machinery. Good Luck. Stealth
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Explanation of drawing?
Stealth,
Could you please describe how this device should work based on your drawing?
You show a bin with a pipe in the lower right corner but how did the water get to the lower right bin? Does the water split at the upper right corner?
Please explain....
Thank you.....
Tj
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The arm with the container loads with water from the top reservoir with a large fast filling valve. The arm loads with 16 oz(1 Lb) of water, at 8 feet in length, it overpowers the weighted wheel, dropping to the bottom, while bringing the weighted wheel to the top. When it drops to the bottom, it empties through a large valve on the 16 oz cup on the arm. When emptied, the weighted wheel again overpowers the arm taking it back to the top to refill. The arm has 8 ft lbs of force, while the weighted wheel has a 3 lb weight on it. 2 lbs of force is required to push a piston forcing water back up into the top reservoir. The unweighted arm weighs hardly anything so its easy for the weighted wheel to relaod the cup on the end of it. It should produce 3 ft lbs of excess energy per revolution. The one way valves on the pipe to the top reservoir reduces the force needed to lift the water to the top reservoir. Good Luck. StealthLast edited by Stealth; 12-01-2009, 05:43 PM.
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No, I haven't had a chance to do a simulation, yet, but I have done the math, and theoretically it should work according to my figures. If it would require more weight on the arm or the wheel, it would be no big deal to use a larger container on the arm, and or larger weight on the wheel to return the arm. Any excess could be used to turn a generator or other machinery. Basically, this is a self running, self replinishing water wheel. Through the use of leverage on the arm, it should have 3 foot pounds of energy, just as it is drawn. This design can be upgraded to any weight differential needed by varying the weight on the arm and wheel, and or lengthening the arm. The longer the arm, the slower the machine runs, just like a waterwheel. The piston pump returning the water to the top reservoir, should only need the same amount of force of energy to lift the water as the water itself weighs, because of the one way valves in the pipe, which holds some of the weight. It is only pushing water as far as the first one way valve. Only by building these designs can you know whether or not it will work. Good Luck. StealthLast edited by Stealth; 12-02-2009, 05:51 PM.
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One way check valves
Hi Stealth,
I see a slight flaw in your understanding of check valves. In order to get the bottom one way valve to open you have to overcome the weight of water sitting on top of the valve. And of course you will also have to overcome the weight of the water sitting on top of the top valve. So in reality you are still having to overcome the weight of the entire column of water plus the restriction of the 2 valves. I don't think you will be able to pump up as much water as you have coming down. I would be curious to see what the simulation shows because I try to keep an open mind so that maybe I can still learn something in my old age. LOL good luck, citftaJust because someone disagrees with you does NOT make them your enemy. We can disagree without attacking someone.
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Yes, you are correct. It does take enough force to overcome the one way valves, but the leverage from the arm should have more than enough force to push water back to the top. The main reason for the one way valves is to prevent water from leaking back into the bottom reservoir. So you only need to push water through the first check valve. You only need to replinish the same amount you use, in this case 16 ounces of water(1 lb). In order to lift 1 lb of water, I am allowing 2 foot pounds of pressure from the arm. This still leaves 6 ft lb of energy, to overcome 3 ft lb of energy on the weighted wheel.
After the water has been emptied into the bottom reservoir, the weighted wheel should once again rasie the arm back to be refilled without any problem.
Atually you should see a difference of 3-4 ft lb on both the downstroke and the upstroke. Plenty enough to turn a generator. Good Luck. Stealth
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