Hi Luc,
If you observe the current consumption of a conventional electric motor, starting from a standstill to its unloaded full RPM, what would you find? Just at startup the current is at its highest value of the whole range (range here is from 0 RPM to full RPM, unloaded shaft), then the current gradually gets reduced as the RPM increases. Why does the current decreases? You surely know: the current decreases due to the back EMF which gradually increases as the RPM increases and works against the input EMF. But the result of the increasing back EMF is a decreasing current consumption because the two EMFs work against each other and their instantenous difference is that can only maintain current. And this EMF difference is surely much less than the input EMF itself. You may consider the back EMF as an RPM dependent voltage source, always in counter or opposite polarity wrt the input EMF.
The same thing is valid for your setup. When your coil starts moving its current consumption will only be dictated by the friction which is already a constant and given value and also by the coil mass, also a constant and given value already. When you stop the coil, it will have the maximum current consumption because in that moment there can be no back EMF develop in the coil. And when you let the coil moving again, the current immediately starts reducing to the "normal operational" value you correctly express as "The faster the coil is moving the less power it consumes."
(And the normal operational current consumption i.e. the no load consumption for your setup is established by the friction and coil mass.)
You can certainly reduce friction but not readily the coil mass. To reduce coil mass you are forced to use even more powerful magnets and also use higher wire diameter to reduce copper loss. So you ought to meet contradicting requirements: reduce coil mass versus using higher diameter wire that involves more mass eventually. Somewhere you have to find a tradeoff.
Hopefully it is clear for you now.
rgds, Gyula
If you observe the current consumption of a conventional electric motor, starting from a standstill to its unloaded full RPM, what would you find? Just at startup the current is at its highest value of the whole range (range here is from 0 RPM to full RPM, unloaded shaft), then the current gradually gets reduced as the RPM increases. Why does the current decreases? You surely know: the current decreases due to the back EMF which gradually increases as the RPM increases and works against the input EMF. But the result of the increasing back EMF is a decreasing current consumption because the two EMFs work against each other and their instantenous difference is that can only maintain current. And this EMF difference is surely much less than the input EMF itself. You may consider the back EMF as an RPM dependent voltage source, always in counter or opposite polarity wrt the input EMF.
The same thing is valid for your setup. When your coil starts moving its current consumption will only be dictated by the friction which is already a constant and given value and also by the coil mass, also a constant and given value already. When you stop the coil, it will have the maximum current consumption because in that moment there can be no back EMF develop in the coil. And when you let the coil moving again, the current immediately starts reducing to the "normal operational" value you correctly express as "The faster the coil is moving the less power it consumes."
(And the normal operational current consumption i.e. the no load consumption for your setup is established by the friction and coil mass.)
You can certainly reduce friction but not readily the coil mass. To reduce coil mass you are forced to use even more powerful magnets and also use higher wire diameter to reduce copper loss. So you ought to meet contradicting requirements: reduce coil mass versus using higher diameter wire that involves more mass eventually. Somewhere you have to find a tradeoff.
Hopefully it is clear for you now.
rgds, Gyula
Originally posted by gotoluc
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