Announcement

Collapse
No announcement yet.

Dielectric emf recycler

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • #31
    Hi all,

    i triple checked that i had wired up the circuit correctly and i had.

    I tried a transformer wound according to the instructions, less volts generated on the "load"...i also tried a 240V-to-24V transformer..again..less voltage.....strangely the same current draw from the drive battery in all 3 cases...20mA.


    conclusion so far = either im missing something here......it doesnt work...

    MY next try ( right now ) unless anyone has any suggestions...will be the circuit posted in the PDF patent posted by Dave Cahoon...looks simple enough ( famous last words )

    David. D

    Comment


    • #32
      @rave154

      Try increasing the frequency. I went up to 50,000hz.

      You should be able to get most of the energy back out. At least 90%

      Try photoflash capacitors because they have much lower charge/discharge resistance.

      Try increasing the drive voltage...

      Dave

      Comment


      • #33
        after trying 4 times to edit my last post

        here
        try to find resonate frequency of your transformer

        i did not try the photoflash caps

        my measuring of this system i found the natural cap charging up effect.

        Dave

        Comment


        • #34
          Thanks for the suggestions Dave,

          when you say " i got 90% back".....do you mean.....you were generating 90% of what your total input was ?

          unfortunately, im using a 4PDT realy...so anything above 20Hz or so is out im afraid.....unless you have a MOSFET version of a circuit i could try?

          David. D

          Comment


          • #35
            mosfet versions
            The Dielectric Shuttle
            im drspark tho as i grow older i whish to be me
            I did 3fet and 6fet versions up to 160vdc

            Comment


            • #36
              ahh...small world aye !!! :-)

              thanks for the link, which of the circuits ( starting from the top )...would you recomend i start with?

              Comment


              • #37
                3fets i think its the first 3fets
                http://drspark.com/3fets10to10.jpg

                Comment


                • #38
                  Thanks, that was the one i was looking at actually :-)

                  i have some IRF540's...those would do i think?

                  i dont have any 2n5551's....but i do have some 2n2222's ( and some of its PNP equiv, no that theyre needed but )...would the 2N2222 do ok ?

                  Comment


                  • #39
                    If you look close two of the resisters on the oscillator are variable so I could controle the frequency the caps set the range. Change the caps ans you go up or down in center frequency

                    Comment


                    • #40
                      those part should work i used what i had on hand for most of the 5 versions of this i built.

                      Comment


                      • #41
                        Thanks, can you explain the methodolgy of the circuit....im confused since C3 & C4 are "always" in parallel there....

                        Comment


                        • #42
                          compare to 6fets
                          Attached Files

                          Comment


                          • #43
                            thanks for that last circuit Dave, i can "see" now how they are going from series to parallel and back.

                            Before i dismantle the realy version of the circuit i have here i just charged it up to 12V ( actually 11.85V )... IE 11.85V on each of the caps in parallel and 11.85V across the caps in series (therefore 5.9V on each cap of te 2 in series )....

                            i used my "hand" to control the relay, connecting and disconnecting the battery to the relay so i could jot down the voltages across a single cap on each side, ie the voltage on C1..and C4...

                            C1 on the left, C4 on the right....and C1 & C2 are in parallel when the relay is not activated.

                            this was using my 240V-to-12V(CT) transformer.

                            based on the total Joules in the 4 caps from the start and what is in them after each switch... the first 4 switchs appear to leave about 65% - 68% after the switch, however bare in mind that each switch is also powering a load - the transformer.

                            11.86... 5.9
                            4.78... 9.5
                            7.83... 3.91
                            3.18... 6.32
                            5.23... 2.61
                            2.13... 4.24
                            3.5... 1.75
                            1.43... 2.85
                            2.36... 1.18
                            0.97... 1.92
                            1.59... 0.80
                            0.66... 1.31
                            1.08... 0.54
                            0.45... 0.90
                            0.75... 0.37
                            0.31... 0.62
                            0.52... 0.26
                            0.22... 0.43
                            0.37... 0.18

                            David. D

                            Comment


                            • #44
                              p.s to my last post ( wont let me edit )

                              i dont have any photo-flash caps, but i do have 4 or more of the caps used in the circuits of compact CFL's.....would those be the same or at least a better quality of cap?

                              Comment


                              • #45
                                thanks for posting this idea. it really got me thinking.
                                I'm sorry my first post here is a negative one but this will never give you excess energy. When you charge a capacitor from an another capacitor trough a load you will dissipate only partly the energy thats in the original capacitor. the rest of its gets stored in the cap you charged and some stays in the original cap. the voltages even out.
                                if you then put the 2 parralel charged caps in series then yes the voltage doubles but the equivalent capacitance will only be 25% of what it was when the caps where in parralel.
                                the energy in a cap : W=1/2*C*U^2
                                u doubles so u^2 makes the result 4x bigger
                                but C is is divided by 4 so the result is 4 x smaller
                                so there's no net change in the total stored energy.
                                its probably more efficient to discharge it all from the original cap.

                                Comment

                                Working...
                                X