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Cop>17 Here's Why This Result Was Predicted

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  • #76
    To begin with imagine this. Inside your average lead acid batteries are a whole lot of atoms and molecules. They have no intrinsic balance. Their valence electrons are such that every part of that 'amalgam' that battery acid - conflicts with every other part. Each atom vies with another. Each molecule vies with another. The liquid is agitated. Like charge conflicts. Here inside the battery is a bath of 'like charge' and it is intrinsically imbalanced. Picture in your mind's eye, if you will, a whole lot of atoms, shaped like tennis balls. They have an imbalanced electron on the outside of that ball. Every time this electron gets close to another electron on another ball the two balls move away from each other. It's a liquid state. They can move freely through that liquid. So they keep spinning - away. That's the mainstream analogy.

    Now, picture - if you will another variation of this picture. Being an amalgam - all those atoms are bound by invisible 'fields' of zipons. All those balls are linked - joined together - by zipons that spin in the opposite way to these balls. For every two atoms there is a field of zipons. For every two molecules - there is a field of zipons. That field is like a glue and they 'stick like crazy.' They hold those balls together. Then as soon as they come near another field of zipons, holding another two balls together they see that they too have a 'like charge' or a like spin. Most uncomfortable. They move away from each other and in doing so they move two or more tennis balls with them. And so it goes.

    Now - hold that picture. I need to show the other parts of the circuit.

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    • #77
      Thank you. It seems I wrongly conclude your theory. Thanks for clarifying it.

      Can you clarify more on the E=mc^2 of zipon. If zipon mass (m) and speed (c) vary, do the energy (E) varies too?

      According to your description:
      "When the field is disturbed, then the zipon loses it's orbital velocity, increases its properties of heat, and increases it's mass or volume."

      If it only the speed is changing in inverse squareroot proportion with mass, how the circuit receive excess energy if the device total mass is the same?

      If zipon energy stay constant, an excess energy in circuit would mean it gain weight because the excess energy comes from zipon, and zipon will gain mass as it slow down and thuss adding the circuit mass.

      When zipon heat up, do they release the energy so either the mass or speed reduced too?

      What is the relation of released heat with zipon energy? Would releasing heat reduce zipon energy?


      Do you expect your circuit to gain weight as it receive more energy from the manifestation of zipon?


      Is the empty space between proton and electron zipon?

      Originally posted by witsend View Post
      I believe I have done so - repeatedly.
      Originally posted by witsend View Post
      And then the next question? What form would those dipoles take once they are outside the whole of the field? To get to this answer I need to digress. Just for now - imagine that we have a machine that throws stones. Here's the rule. The force of the throw is constant. And there are no extraneous conditions of air resistance or wind or anything at all. It throws these stones inside a vacuum. That means, that all things being equal, then the bigger the stone the shorter the distance thrown. And conversely, the smaller the stone the further the distance thrown. That's logical. I'll get back to this point. But what I actually need to first concentrate on is an 'interactive constraint'. If the stone were too big then the machine could not lift it to throw it. And in the same way, if the stone was too small then the machine could not detect it to throw it. That's what the model refers to as a boundary constraint. The condition of size would threby limit the interactive capability of the machine. In the same way I'm proposing that if these little magnets in a broken string - tumbled out of the field and congregated into vast nebulae then what makes them visible and would it then be 'out of range' or 'outside the boundary constraint' of the magnetic dipoles in the field surrounding the nebula?
      I mean, I do not find it logical that bigger stone reach shorter distance if there is no opossing force. What is logical for me in that condition is the same throwing machine work harder to change a standing still bigger stone to move (slower acceleration from F=ma) and resulting in slower speed. It may not stop without opposing force. Your are suggesting bigger stone experiencing bigger opposing force, but you don't mention what the force is.


      DOR and OR closely related to ultra violet and infra red.
      Last edited by sucahyo; 02-23-2010, 07:19 AM.

      Comment


      • #78
        Originally posted by sucahyo View Post
        Can you clarify more on the E=mc^2 of zipon. If zipon mass (m) and speed (c) vary, do the energy (E) varies too?
        No. I'm suggesting that its potential energy quotient is constant. It's expression varies. If it is faster, it is correspondingly smaller and and colder. If it is slower, it is correspondingly bigger and hotter. This proportional equivalence also speaks to some constant that relates to a caloric property in the magnetic field that has not been identified by mainstream. In other words I am literally proposing that 'heat' is always related to the disturbance of zipons outside their invisible state in the field. All states of 'hot' be it flame, or friction, or anything at all - heat is a measure of these fields in a transitional state. 'Flame' or 'fire' is therefore - literally - magnetic dipoles that are 'outside' their orderly binding field state - and are experienced and measured in our dimensions. And as they find new 'abodes' they decay back to their 'invisible' field state.

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        • #79
          Originally posted by sucahyo View Post
          According to your description:
          "When the field is disturbed, then the zipon loses it's orbital velocity, increases its properties of heat, and increases it's mass or volume."

          If it only the speed is changing in inverse squareroot proportion with mass, how the circuit receive excess energy if the device total mass is the same?
          The circuit does not receive excess energy. The energy is there - in the bound mass of circuit components. The circuit experiences these imbalanced fields as heat. What the experiment exposes is that current flow does not only come from the battery supply source. There is an alternate field of energy released in the circuit components. This is added to the sum of current flow in a circuit. The effect of imbalancing these circuit component fields through applied potential difference is able to induce an alternate current flow that is measurable. I'll explain this more fully when I get to a fuller description of current flow.

          Comment


          • #80
            Originally posted by sucahyo View Post
            If zipon energy stay constant, an excess energy in circuit would mean it gain weight because the excess energy comes from zipon, and zipon will gain mass as it slow down and thuss adding the circuit mass.
            I am only talking increase in volume. This is very evident when hot objects also expand in size. That expansion relates to the 'volume' of the zipon as it materialises or moves into our measurable dimensions. But yes. I am proposing that disassociated atoms and molecules actually do 'weigh' fractionally less than their 'bound' state. And that difference relates to the 'fields' that are introduced to 'bind' those atoms or to 'unbind' them - whichever case is applicable. And it is in the binding and in the unbinding that energy is evident and measurable.

            Comment


            • #81
              Originally posted by sucahyo View Post
              When zipon heat up, do they release the energy so either the mass or speed reduced too?
              They do not release energy. They are energy. It is a transitional state only. They immediately seek out new 'abodes'. Then they 'decay' back into their 'invisible state'. For instance - they can move from a source flame - such as burning coke - into an aggregate - say iron filings. As they do so they unbind the 'source material' - that coke so that all that is left is ash. And they then go into the material of the aggregate to bind them into an amalgam. When the source flame is removed or exhausted, then their new 'abode' would be that iron. The hot 'melted' amalgam now becomes cool and sets.. The amalgam 'sets' into a lump of iron or such like. In effect the zipons have transferred themselves from their transitional state as a source 'flame' to the aggregate. Here they found themselves an 'abode' that they can bind. Having done so they then reorganise themselves into balanced fields. And as they find that balance they disappear from view. They are now in their 'field' condition as small and fast and cold. They stay there binding those atoms unless and until they are exposed to yet more imbalanced fields.

              Comment


              • #82
                Originally posted by sucahyo View Post
                What is the relation of released heat with zipon energy? Would releasing heat reduce zipon energy?
                The zipon energy is never released. It is only transferred - from one field to another field - from one abode to another abode. It is during this transitional state of transfer that we are able to exploit that energy.

                Originally posted by sucahyo View Post
                Do you expect your circuit to gain weight as it receive more energy from the manifestation of zipon?
                No. I expect that the degradation of the 'heated' components will actually reduce the mass of the material in the circuit components. I'll get to this later when I explain more about the 'transfer of the fields'. But it is a good question.
                Last edited by witsend; 02-23-2010, 08:18 AM.

                Comment


                • #83
                  Originally posted by sucahyo View Post
                  Is the empty space between proton and electron zipon?
                  Another good question. I actually propose that the energy levels of atoms 'fill' that space - and those energy levels are simply orbiting magnetic fields. In as much as I proposed that all such fields comprise magnetic dipoles then yes, they are zipons. But the binding 'zipon' field is argued to be extraneous to these energy levels. However they only interact with these energy levels. This is because they are of 'like' mass and velocity. In other words, they can only interact with something that has an mass equivalence. Anything bigger or smaller? Then it simply does not 'find' that particle any more than the 'particle' can see the field.

                  Originally posted by sucahyo View Post
                  I mean, I do not find it logical that bigger stone reach shorter distance if there is no opossing force. What is logical for me in that condition is the same throwing machine work harder to change a standing still bigger stone to move (slower acceleration from F=ma) and resulting in slower speed. It may not stop without opposing force. Your are suggesting bigger stone experiencing bigger opposing force, but you don't mention what the force is.
                  You're quite right Suchayo. I should have clarified this. I mean you to imagine the 'throwing machine' to operate in a gravitational field. Else it does not make sense. Apologies. I should have clarified this. But this analogy will be explained hereafter. I think I need to cover the concepts related to current flow - first.

                  May I add, I am just so chuffed at these questions. Thank you very much.

                  Comment


                  • #84
                    To begin with imagine this. Inside your average lead acid batteries are a whole lot of atoms and molecules. They have no intrinsic balance. Their valence electrons are such that every part of that 'amalgam' that battery acid - conflicts with every other part. Each atom vies with another. Each molecule vies with another. The liquid is agitated. Like charge conflicts. Here inside the battery is a bath of 'like charge' and it is intrinsically imbalanced. Picture in your mind's eye, if you will, a whole lot of atoms, shaped like tennis balls. They have an imbalanced electron on the outside of that ball. Every time this electron gets close to another electron on another ball the two balls move away from each other. It's a liquid state. They can move freely through that liquid. So they keep spinning - away. That's the mainstream analogy.

                    Now, picture - if you will another variation of this picture. Being an amalgam - all those atoms are bound by invisible 'fields' of zipons. All those balls are linked - joined together - by zipons that spin in the opposite way to these balls. For every two atoms there is a field of zipons. For every two molecules - there is a field of zipons. That field is like a glue and they 'stick like crazy.' They hold those balls together. Then as soon as they come near another field of zipons, holding another two balls together they see that they too have a 'like charge' or a like spin. Most uncomfortable. They move away from each other and in doing so they move two or more tennis balls with them. And so it goes.

                    Now - hold that picture. I need to show the other parts of the circuit.


                    Just repeating this for continuity.

                    Comment


                    • #85
                      Then we have the material in the resistor itself. This is a combination of some balanced and some imbalanced valence electrons. Here the proposal is this. The amalgam is a solid and not a liquid as is the battery acid. It is predominantly imbalanced else it would not be predominantly resistive. Therefore there are many zipon fields connecting the atoms - those tennis balls - that also have to best avoid contact with each other. The proposal is that the fields have separated those 'tennis balls' and are holding them in a fixed but chaotic distribution in space where the net charge value is best stabilised albeit essentially unstable. Here the easiest visual image is to imagine circles of tennis balls with zipon fields holding them and themselves apart from each other. Again. The circle is simply a visual guide and best describes an even distribution of like charge. Then the material is solid. The zipons merely decay into their 'fields' and hold that material - those tennis balls - in a fixed or 'rest' position.

                      Comment


                      • #86
                        Then we have the 'doped' material in the transistor itself. Here there's a group of atoms that have been 'wedged' together with their charges facing the same direction. Most uncomfortable. Imagine if you will those tennis balls with an electron exposed to the 'north' say and all the other tennis balls facing exactly the same direction. Or picture - if it's easier - a whole lot of magnets grouped where all their norths are exposed in a northerly direction and their souths in a south direction. Very uncomfortable for magnets and equally so for these atoms. Then too the proximity of the 'binding' zipon fields are also very uncomfortable. All that 'instability' is tailor made to advance an 'imbalanced' interaction.

                        Comment


                        • #87
                          That covers the most significant 'material' in the circuit. Now we can sit back and see the 'unfolding' of those 'imbalances' and determine what it is that 'flows' from one part of the circuit to another.

                          To start with the 'like' charge in the zipon fields in the battery interact with the copper plates. This induces a mild magnetic field that - in turn, allows some of those zipon fields to adjust and systematically unravel as they move towards the positive terminal of the battery.

                          There they find the balanced zipons that bind the copper wire. Symmetries here are easy. They force out the let us call it - northern orbit - and replace this with their own fields. The northern orbit or binding zipons then are literally ejected from the material of the copper wire. But they are atomically and anatomically required. They do not move far. They simply continue their compulsive orbit around the material of the wire.

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                          • #88
                            Zipons are stil moving through circuit components. They then find the zipons in the resistive wire. But here they hit on a problem. All the zipons are arranged in a position of net zero charge. Yet all those binding fields of zipons are, in fact, experiencing an identical charge - a single direction. Therefore, in order to 'find their path' through this field, when they eject half the zipons they also unravel the remaining fields. In doing so these unravelled fields slow down, get bigger and get hot. Those fields that the 'northerly' flow from the battery have ejected? They simply orbit the structure of the resistor - again being atomically and anatomically required by the resistor itself.

                            EDITED
                            Last edited by witsend; 02-24-2010, 07:47 AM.

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                            • #89
                              Then the fields reach the MOSFET and all those 'like' and northerly facing zipons. They avoid this at all costs and find a 'neutral' path through the MOSFET offered by an alternate 'leg'. Then they continue their path over the shunt resistor - a small little resistor that is simply added to the circuit to measure current flow. And then they reach the negative terminal of the battery. Here at last they present a northerly face to the chaotic mix of like charge and this allows them to recombine into the mix with an alternate spin. For the first time they have been able to change their northerly charge to a southerly charge and thereby - when the join some of those 'like charged' atoms - they can do so with an alternate spin. This neutralises the 'bath' of acid.

                              This is roughly akin to the effect of watching two magnets conjoin. They can't simply vary their north/south orbit. They have to change the physical position of their north's to south's in order to 'attach'. In a similar way the 'spin' in the hidden fields, needs to be adjusted through space that their 'attachments' in the amalgam are re-arranged. To do this they need to complete their path through the circuit in order to present their charge from an opposing direction.
                              Last edited by witsend; 02-23-2010, 12:16 PM. Reason: spelling

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                              • #90
                                At this stage, in the mind's eye - simply picture a line of zipons connect north to south along the copper wire, into the material of the resistor, away from the 'like' charge of the MOSFET, back onto the copper wire, through the shunt resistor and then back to the battery. Just a long line of north/south magnetic dipoles, attached head to toe - in formation and finally reaching the negative terminal. And the time taken for all this movement? The zipons move at 2C. I'll explain why later. But the effect is that there is an INSTANTANEOUS transfer of these little fields from one terminal of the supply source to the other. In doing so some of the fields in the resistors have unravelled and this has resulted in an apparent dissipation of energy at those resistors.

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