Combining radiant output, 0.2 + 0.2 = 1.5

[sucahyo]

I found that my circuit produce more output than it originally is when combined.

Just recently measure the actual output.
0.18A + 0.19A resulted in 1.5A .

YouTube - Combining radiant output, 0.18A+0.19A = 1.5A

This is the circuit:
edit: fixed diode



I would love to hear the result of anyone replicating the correa's converter combiner and use more than two radiant oscillator. I only have two at the moment. Bedini SSG, joule thief, Bedini SG, Imhotep oscillator, etc can be used.

[Zooty]

I didn't really understand what was going on in the video, what you was measuring and where from.

[Joit]

sucahyo
What size of Caps did you use and the Coil is only this handwounded one,
what you have there? What is the Wire size, what you have there?
The Transistors i guess are the one, you did use still 2n29?? and KLC????.
The Caps are maybe anyway oversized, this size can store a lot of Energy but have slower decharge Cycle.
And you take the measurements there, where the Charge actually is?

[juju]

hi sucahyo

this is really an interesting effect...

whats your input power?

[Harvey]

It is somewhat confusing

I think we need to know the particulars like Frequency, Amplitude,
Phase, AC, DC, Test conditions for each reading etc.

All of these will help us determine what is being added and how.

For example:
Consider a 2 Phase AC electrical system - each phase is 180° shifted from the other referenced to a single neutral. The frequency for both is 60Hz. The Amplitude of either leg is 120V to neutral. Now, if we take Ph1 through a 120 Ohm resistor to N we get 1A. And if we take Ph2 the same thing, so each offers 1A. But if we put that resistor between Ph1 and Ph2, it will produce 2A because the phase difference results in 240V between Ph1 and Ph2.

Another example:
Circuit 1 has an output stage that routes through an inductor, so the current lags the voltage by 90 degrees and the inductive reactance only allows a current of 0.18A, AC at 12V.

Circuit 2 has an output stage that routes through a capacitor, so the current leads the voltage by 90 degrees and the capacitive reactance only allows a current of 0.19A, AC at 12V

When Circuit 1 and Circuit 2 are joined, they both change frequency (altering the reactance) and find a resonant condition and the reactance drops through both outputs to allow 1.5A to flow. Also, the power is increased as the two combined bring the current back in phase with the voltage.

[sucahyo]

Thank you all for the interest .

Here is a better video.
YouTube - SO + MJT, more power, better video


What I do is combining my modified joule thief circuit and my sting oscillator circuit with the help of FWBR. The video show charging of 12V 7Ah battery, a dead one.

1. With only modified joule thief, output current is 30mA, consuming 1.09A.

2. With only sting oscillator, output current is 60mA, consuming 0.4A.

3. Both circuit output current is 160mA, consuming 1.4A.

Combining circuit increase efficiency.

Oops, just realize that my MJT is actually lower in efficiency than SO. Sorry juju, my post at other thread is actually wrong....


I don't have scope so that video is the best I can get. Open to suggestion.


capacitor is 105K, 250V.
diode is FR302.
transistor is 2 x KSC5027, 1 x TIP2955, 1 X 2N2955.
1 x transformer coil of 24V/240V 1 Amp
1 x hand wound coil on small ferrite with unknown impedance and inductance. maybe smaller than 1 Ohm. (my ohm meter give false reading).

When Circuit 1 and Circuit 2 are joined, they both change frequency (altering the reactance) and find a resonant condition and the reactance drops through both outputs to allow 1.5A to flow. Also, the power is increased as the two combined bring the current back in phase with the voltage.

Would that also apply to pulsed DC output and stable DC input?

For frequency, I do notice change of coil sound pitch.

I also thought that input current surely increase with more output current. However, the more detailed video of input output show it isn't. Confusing indeed. It do charge dead battery to 10V standing, 7 volt while litting 24V lightbulb. Battery dead again the next day though lol.

[Joit]

Hi sucahyo and thanks for posting the Parts, but anyhow seems there a misunderstanding,
Is it now 1,5A Output or Input, because first you wrote Output,
then consuming.

1. With only modified joule thief, output current is 30mA, consuming 1.09A.

2. With only sting oscillator, output current is 60mA, consuming 0.4A.

3. Both circuit output current is 160mA, consuming 1.4A.

Right now, i got no time, to play around with it, maybe in a few Days.

[sucahyo]

Hi sucahyo and thanks for posting the Parts, but anyhow seems there a misunderstanding,
Is it now 1,5A Output or Input, because first you wrote Output,
then consuming.

Previous experiment do not use any load, anything is send directly to the meter, and thus it produce more current (less resistant, more amp).

The latest experiment is using a dead battery (not dead anymore though ), which should have considerably resistant. Which is why the output is lower.

I don't think I can mimic the resistant of amp meter and thus I decide to redo the experiment with 12V battery.

rewriting:
1. With only modified joule thief, input current is 1.09A, output current is 30mA.

2. With only sting oscillator, input current is 0.4A, output current is 60mA.

3. Both circuit input current is 1.4A, output current is 160mA.



To sum up. With battery as load combined circuit input current is 1.4A, output current is 160mA. Without load output current is 1.5 with unknown input current.

[Joit]

Maybe this dead Battery is not the best choice, because it can have low Resistance,
and when you feed back the Spikes, it makes something like a short,
like a Bedini stops to turn.
At the solid State it compensate it with more current, but there should be a
certain resistance when you try to feed it back.
for me it was about 300 ohm, but it is different.
And then, it has not really an effekt anymore, because there comes no current back into the Circuit.
Either change the Battery for a better one, or you may try to feed the pulse only at a certain Time back.

[sucahyo]

Maybe this dead Battery is not the best choice, because it can have low Resistance,
and when you feed back the Spikes, it makes something like a short,
like a Bedini stops to turn.
At the solid State it compensate it with more current, but there should be a
certain resistance when you try to feed it back.
for me it was about 300 ohm, but it is different.
And then, it has not really an effekt anymore, because there comes no current back into the Circuit.
Either change the Battery for a better one, or you may try to feed the pulse only at a certain Time back.

I don't get that, especially the last one. Battery resistance will reduce when full. A dead battery have rather high resistance that the charging voltage could be seen to climb much higher than normal battery.

Would using light bulb as load better? how about CFL?

Not sure if I can reliably show output voltage without load, would be out of scale.

The increase of output without the increase of input is rather weird. Maybe it is the true potential of the coil. I can replace the small coil with mallory car coil if needed.

[sucahyo]

Funny battery

Noticing something funny today. The battery that I use at latest video can be recovered. It can lit a light bulb the next morning.

The funny thing is, after I let it lit the lightbulb for 3 hours, it get noticeably warm and make popping sound (bubbling?). And it never do that, never get warm, never made popping sound when I charge them for 6 hours. It heat up more when discharging then when charging .

Bedini charger is superb
Big

Prove that my circuit is COP<1 yet though. 1.4A at 6 hours only resulted on moderate light for 3 hours...

[Joit]

I found that my circuit produce more output than it originally is when combined.

Just recently measure the actual output.
0.18A + 0.19A resulted in 1.5A .

YouTube - Combining radiant output, 0.18A+0.19A = 1.5A

This is the circuit:

I still dont know, what Coil that is, Top Left Side beside the 88k & 2K2.
And it seems like the KSC right side there can be replaced with a weaker one too, its only to drive the Base.
The resistors just lower the incoming at the Base.
Then the 2 Coils are your handwound Coils?
A CFL as load works good with high, adjustable Frequencys and a Bulb? I dont know.
About the Batteries, you are right too, some get to high resistance, that they can not be loaded anymore, some make a Short.
When the Circuit consumes more Amps, then it is mostly you have heavy load on it, or it is feeding the Spikes back in some cases.
It can consume then 4 times more.
But i need to look anyway, to get such a high ratet NPN, 1000 V, and 2 of it...
And yeah, Bedinis charger is great, what a lot Peoples absolute not can estimate, what they did get there.

[Bob Smith]

Is this basically a heterodyne of 2 oscillators?

Hi Sucahyo,
Are you saying that your return on 2 heterodyned oscillators is greater than the sums of their individual outputs?

I remember Stan Deyo saying in one of his vids that one of the big free energy guys - maybe Henry Moray - had a small unit that brought in free energy from the vacuum, with a heterodyne being an important component. Maybe you've stumbled onto something very important for all of us.
Bob

[sucahyo]

I still dont know, what Coil that is, Top Left Side beside the 88k & 2K2.

The top is the hand wound one, the bottom is off the self 1Amp transformer with its core removed.

You can replace the top one with anything, but not the bottom one (tricky).

And it seems like the KSC right side there can be replaced with a weaker one too, its only to drive the Base.

If its possible the NPN sould be the most efficient one, maybe MJL one. I found that KSC5027 twice more efficient than 2n3055.

The resistors just lower the incoming at the Base.

The resistor for top circuit should be high to prevent BEMF leaking. The resistor for bottom circuit must be selected at circuit highest output. You might also need to swap transformer leg to get the highest output.

A CFL as load works good with high, adjustable Frequencys and a Bulb? I dont know.

Just try it, bad idea, voltage is out of scale.

When the Circuit consumes more Amps, then it is mostly you have heavy load on it, or it is feeding the Spikes back in some cases.
It can consume then 4 times more.

The bottom circuit is funny in this, if you tune it right, it will consume 0 amp if you short the output. Less input current with heavier load . The top one also did although less pronounce..

But i need to look anyway, to get such a high ratet NPN, 1000 V, and 2 of it..

PNP need to be high rate too. At least I found that TIP2955 perform much better than 2SB507. For starter, a combination of tip2955 and 3055 should produce same result although at half efficiency.

[sucahyo]

Hi Sucahyo,
Are you saying that your return on 2 heterodyned oscillators is greater than the sums of their individual outputs?

I remember Stan Deyo saying in one of his vids that one of the big free energy guys - maybe Henry Moray - had a small unit that brought in free energy from the vacuum, with a heterodyne being an important component. Maybe you've stumbled onto something very important for all of us.
Bob

Interesting info .

I don't know what heterodyne is, but yes, combined output is more than 150% of individual output, but I still not sure if it works for every radiant oscillator. I will try to combine three (one more sting oscillator).