Originally posted by elias
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Thank you for taking the time to produce this circuit, it really helps when trying to deal with complicated topics.
The formula for calculating energy stored in a capacitor in Joules is:
0.5 x capacitance in farads x voltage ^2
Initially capacitor C1 is charged to 24volts. The stored energy is:
0.5 x 0.01 x 24 = 0.0144 Joules
Capacitor C1 is discharged into capacitor C2 via the inductor. By your calculation capacitors C1 and C2 now have 12v each and the stored energy is:
0.5 x 0.01 x 12 = 0.0036 Joules. Multiplied by 2 = 0.0072 Joules. We now have half of the energy shared between twice the capacitance.
Capacitor C3 is charged from the collapsing field of the coil to 10 volts. The energy stored in capacitor C3 is:
0.5 x 0.01 x 10 = 0.0025 Joules
All three 10000uF capacitors now store 0.0108 Joules between them. Based on calculation alone, there is a loss of 0.0036 Joules. These are ideal numbers from ideal capacitors with no account for losses anywhere in this circuit. There is also the difficulty in returning the circuit to the initial position where C1 = 24v, C2 and C3 = 0v.
To my knowledge, nobody has produced a circuit based on these principals that does not have the same losses, therefore nobody has made a valid claim of overunity using a circuit based on this typology.
Regards Lee..
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