Understanding batteries

[ibpointless2]

In the textbooks I’ve have been taught that a battery is like an hourglass, When its full at the top it falls through the load of the small hole and rest at the bottom. In a circuit a battery is present and the power that is taken out of that battery to run the circuit is the same as the power that is returning to that battery. So if i’m using 1 amp i’m returning 1 amp, but that is my problem. Back to what I was saying about the hourglass, the sand falls to the bottom, so 1 grain falls from the top then it will be 1 more grain at the bottom. So what do you do when there is no more sand at the top? you flip it and start again, so why doesn’t the same hold true for batteries? It seems like battery chargers use high pressure air to push the sand from the bottom to the top when they could have just flip the glass. The whole concept of a battery seems to go against the law of conversation, where the battery has 1 amp and when its done with it it destroys it, but its got be somewhere?

Sorry for my ignorance of batteries, but I come here in hope of someone being able to help me. One would think that you don’t need to recharge a battery, all you should need to do is just flip it like the hour glass. Going off that idea I did some experiments where I took two 12 volt batteries, I hook both positives up and connect my multimeter across each negative post. It seems that even though both terminals say their negative it creates a positive post and i’m able to get a volt reading. I get from the two 12 volt batteries a reading of .174 volts, a constant steady voltage that is strong enough to charge a capacitor. I wouldn’t say that I have been able to flip the battery like the hourglass but it is something interesting to note. This also works on some AA batteries too but with less voltage of course. What is this energy, how has it been put there? Could this energy be used to help charge other things? The batteries don’t get hot and they seem to keep their charge. Please help me to understand.

[Farmhand]

Hi ibpointless2, I just tried what you did and I measured at first about .006 volts
but it is rising above .01 volts and still going, I can't help you with an explanation but it is interesting.



Cheers

[sucahyo]

One would think that you don’t need to recharge a battery, all you should need to do is just flip it like the hour glass. Going off that idea I did some experiments where I took two 12 volt batteries, I hook both positives up and connect my multimeter across each negative post. It seems that even though both terminals say their negative it creates a positive post and i’m able to get a volt reading.

When you connect it like that, they will even out their voltage. They usually have different charge at first. When they reach completely same voltage, what to do next?

From what I recall if you invert the positive to be a negative, you will destroy the battery.

[Duncan]

OH oh such a question. Batteries? We are taught that what we put in (ampere hours) is what we get out. Then along comes a genius like Bedini who shows us how to “condition” the batteries how to charge with radiant energy why we now have a different beast and a different technique.
I have also heard of people who can simply use chi and project power straight into a battery I’ve never seen that done and couldn’t even start an explanation.
From what you describe I would suggest you are reading the difference between each battery voltage. Could you take each battery voltage first?

[ibpointless2]

Duncan is correct

OH oh such a question. Batteries? We are taught that what we put in (ampere hours) is what we get out. Then along comes a genius like Bedini who shows us how to “condition” the batteries how to charge with radiant energy why we now have a different beast and a different technique.
I have also heard of people who can simply use chi and project power straight into a battery I’ve never seen that done and couldn’t even start an explanation.
From what you describe I would suggest you are reading the difference between each battery voltage. Could you take each battery voltage first?

I believe Duncan has it correct, i’m just merely reading the difference of the two batteries and I feel stupid for not thinking about that. One battery is at 12.61 volts while the other is at 12.44 and when you subtract those two you get .17 volts. So what I have made is a type of battery charger, where the higher voltage is positive on the negative terminal and the lower voltage is the negative on the terminal and the higher voltage wants to go to the lower voltage battery to recharge it until both are equaled out. You’ll get a better reading if one of the batteries is nearly dead and one that is charged fully, hook them up positive to positive and the charged battery negative terminal is the positive and the dead battery negative terminal is still the negative terminal and then you can supply a load such as a light or fan and then the dead battery will charge until both are equal. This is one of those real life things that can supply a load and recharge a battery too. I don’t really know what this can be used for as the more you use it the less the difference becomes and the less power you’ll have over time.

I guess I could hook one battery up to a inverter and when its done draining it I can hook enough of the batteries that makes the poetical difference of that new dead battery and some freshly charge batteries 12 volts to run a inverter for even longer. Its like one door was closed and many of windows were opened. I wonder if this concept will work on batteries that will no longer take charge? So many possibilities now .

[Farmhand]

If the batteries were equalizing wouldn't the voltage reading be getting less not more. Maybe its not good to do that to them. I just tried it the other way around connected the two negatives and get .047 volts from the two positives and rising very slowly, one battery is 12.63v the other 12.68v they were charged in parallel by SSG.

[ibpointless2]

If the batteries were equalizing wouldn't the voltage reading be getting less not more. Maybe its not good to do that to them. I just tried it the other way around connected the two negatives and get .047 volts from the two positives and rising very slowly, one battery is 12.63v the other 12.68v they were charged in parallel by SSG.

It is confusing how this does work. How slow are you talking because i've have only held the measurement for only a few seconds and only kept the batteries hooked up for no more than a minute. My batteries don't get warm nor do the wires that hold them, and the wires are only 28 gauge alligator clips. As for the voltage rising i've have only seen it in the form of the capacitor. I take a cap that has been sitting for a day that reads about .080 volts on it and hook it up to let it charge, it gets to about .174 volts and will stay there in most cases, but the weird part is when i disconnect it from the batteries and the cap will keep on going up, instead of the normal drain i get when a cap is connected to my meter and instead the cap goes up in power. I'm sure its not a memory effect because i left the cap sitting for days before hooking it up.

I don't see how it would harm the batteries, it doesn't matter for me if the batteries do get harm as i got the batteries for free. More testing needs to be done, but what i do know is the greater the difference of the two batteries the more power. I also look forward to your testing to see if the voltage does go up.

This makes me wonder because you get greater power with more difference, so what would happen if i hook my 12 volt battery to a 6 or even a 1.5 battery? This could be very dangerous.

[ibpointless2]

If the batteries were equalizing wouldn't the voltage reading be getting less not more. Maybe its not good to do that to them. I just tried it the other way around connected the two negatives and get .047 volts from the two positives and rising very slowly, one battery is 12.63v the other 12.68v they were charged in parallel by SSG.

I’ve tried Farmhands way but my voltage between the two batteries don’t go up they go down, but the charge on both batteries go up. As the difference between the two batteries go down the voltage on my batteries themselves go up, this was very unexpected because I thought one battery will go up and the other will go down and they would meet in the middle. How I did the set up is that I put in a resistive load, connected the negatives together and on the positive I put a 1 k ohm resistor with the positives. I lost about .001 in both batteries difference but gain that back in both batteries individually.

[Farmhand]

I really don't know what to make of it, I left them like that for about ten minutes before that they were sitting idle and connected in parallel for hours, I didn't expect to see any change from the batteries by connecting only the positives or negatives, but i see a lot of things lately I don't expect to see. I'm stumped.

[redeagle]

Your "gain" is probably coming from the calculations that take place in your meter. Not an actual gain in energy. That's why the loss shows only on the series connection.

As far as the hour glass theory it is gravity that drives the grains of sand. You are inverting the gravity pull relative to the sand. In a battery it is a chemical reaction that drives the electrons. If you want to "reset" the battery you have to reverse the chemical reaction. You can't do that by turning the battery around.

[gmeat]

Hi Everyone,


You can get the polarity to flip its + and - by doing this simple experiment take two 9 volt batteries that are pretty much shot in my case the 1 battery had about a 5-6 volt reading on it and the other had about 7-8 volts on it.So I snapped the positive from 1 battery to the negative of the other and likewise for the other terminals and let them sit over night and the next day the higher voltage battery dropped about 2 volts and the other battery had about a -5 volt reading on it(Be warned that the batteries will tend to heat up for the first few minutes).That was the reason for using partially dead batteries.I also notice this same effect when discharging capacitors if discharge them in series using different sized caps Uf values.The capacitor reaction really has my mind working OT because I think that this could be of some importance in my future experiments But for now my latest project is to have a battery's positive terminal go through a bifilar coil and attract a piece of metal on a rotor and exit through a commutator hooked up to a capacitors positive terminal and have the capacitors negative terminal travel back through the bifilar coil in the opposite direction so that the coil maintains the same polarity and returns to the battery through another commutator and the reasoning to this is that I spin the rotor while my cap charges up and then dump my cap to a lesser cap uf value as the next piece of iron comes into close proximity of the next coil and you can begin to get the picture from here .Now if I could only figure out where that Negative cap value might come into play here .Ah shucks,Don't let me derail your guys thread.Carry on carry on


-Gary