Originally posted by redrichie
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When the battery is connected +/- to cap then the breakdown voltage of the dielectric isn't exceeded, and the cap will only fill up to the voltage of the battery. When the battery is connected in the captret configuration, then the capacitor's dielectric breakdown voltage is exceeded and conduction occurs just like a diode (this is the virtual or phantom diode Dr. Stiffler has already mentioned). Don't forget the LED is also a diode. This allows the capacitor to be charged slightly higher than the battery voltage. The captret isn't anymore OU than a voltage multiplier by means of capacitors and diodes. Don't kill the messenger.
GB
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