Announcement

Collapse
No announcement yet.

Faraday disk/n-machine questions

Collapse
X
 
  • Filter
  • Time
  • Show
Clear All
new posts

  • #16
    Thanks.

    I do not get any Voltage that I can tell. But then again I didnt test for mV. I was looking for current. But I think a lot is explained by the saturation of the magnetic field in the copper disk. I did a very small test today with a couple of stacked ceramic magnets. Unlike the large neos the ceramics had a noticeable drag in comparison. I will test with a ceramic and small neo setup this weekend.

    Formula 409.

    Comment


    • #17
      Originally posted by redrichie View Post
      I do not get any Voltage that I can tell. But then again I didnt test for mV. I was looking for current. But I think a lot is explained by the saturation of the magnetic field in the copper disk. I did a very small test today with a couple of stacked ceramic magnets. Unlike the large neos the ceramics had a noticeable drag in comparison. I will test with a ceramic and small neo setup this weekend.
      Did you do a continuity test to check for a complete circuit? The saturation of the magnetic field in the copper disk is total nonsense.

      GB
      Last edited by gravityblock; 11-13-2010, 01:42 AM.

      Comment


      • #18
        Continuity is good on both the solid stainless steel shaft and aluminum pipe.

        Comment


        • #19
          Originally posted by redrichie View Post
          Continuity is good on both the solid stainless steel shaft and aluminum pipe.
          Continuity needs to be good between the center of the copper disc and the outer edge of the copper disk, or between the shaft and the outer edge of the copper disk, and not just along the shaft. If you're doing the measurements correctly and there is a complete circuit between axis and rim of the copper disk, then I would have to say the inner diameter (I.D) of the ring magnet is cancelling out the voltage generated from the outer diameter (O.D) portion of the ring magnet due to an inverted field. That large hole in the ring magnet representing the I.D. has a magnetic field pointing in the opposite direction as the O.D. of the ring magnet.

          GB
          Last edited by gravityblock; 11-13-2010, 04:26 AM.

          Comment


          • #20
            Originally posted by broli View Post
            It's best to try to measure from the outer edge to as close as the inner diameter of the ring magnet for maximum voltage.
            This is what I was trying to say in my previous post. I don't see how he can do the measurements this way, because the copper disc is sandwiched between the two magnets with very little spacing (hard to get a probe between the ring magnet and the copper disc, in order to check the copper disc as close to the inner diameter of the ring magnet as possible). If he's measuring between the shaft or axle and the outer edge of the copper disc, then the inverted field of the I.D. of the magnet will work against the generated voltage induced from the O.D.

            GB
            Last edited by gravityblock; 11-13-2010, 04:35 AM.

            Comment


            • #21
              Gravity block: I do understand what you are saying. I will try to get a measurement at the disk ID and OD. I will improve the brushing mech as well. Have you seen the 18 or so videos @youtube of Brian DePalma? If not I recommend them even if this area is not of too much interest to you. Lots of good stuff in there.
              Question. If the small Voltage induced in the disk can not conduct very far distances, how will it ever conduct through brushes and into a circuit or power another homopolar motor?
              And could you please explain the noticeable increase in eddy currents when using the ceramic magnets of smaller size than the neos? Although when just holding the copper disk and run the neo magnets over the surface of the disk I can induce quite a bit of drag

              Comment


              • #22
                Originally posted by redrichie View Post
                Gravity block: Have you seen the 18 or so videos @youtube of Brian DePalma? Yes, I am very familiar with the HPM/HPG's and have done extensive research in this area. Question. If the small Voltage induced in the disk can not conduct very far distances, how will it ever conduct through brushes and into a circuit or power another homopolar motor? There are certain configurations which can dramatically increase the voltage and totally eliminate the brushes at the rim. The current can then be extracted with a slip ring on each end of the axle or by using mercury,etc. Multiple HPG's can also be connected in series to increase the voltage in addition to using really large diameter magnets which is out of the price range for most hobbyists while rotated at high rpm's. And could you please explain the noticeable increase in eddy currents when using the ceramic magnets of smaller size than the neos? Although when just holding the copper disk and run the neo magnets over the surface of the disk I can induce quite a bit of drag The ceramic magnet may not have a perfectly aligned magnetic axis, which would create a changing magnetic field and induce eddy currents. Eddy currents may also be induced if parts of the copper disc are outside of the magnetic field due to the weaker and smaller size magnets (I think this may be the reason why it's not recommended for the copper disc to be much larger in diameter than the magnet.
                The red text above are my replies to your questions. Hope this doesn't cause any confusion.

                GB
                Last edited by gravityblock; 11-13-2010, 06:37 AM.

                Comment

                Working...
                X