I developed a theory about charge conservation. Based on the fact that, when you divide the charge between two similar capacitors half the energy disappear. I developed the theory that if you discharge a capacitor bigger into a smaller capacitor, conserving the charge this smaller one will have higher energy stored!
Do the calculations.
Q=V*C
V=Q/C
C=Q/V
E=1/2*V^2*C
If we add enough induction to let the current from the first capacitor to charge into another smaller capacitor the energy will be multiplied by the factor of difference between the capacitors. As the gain is per cycle, choosing a higher operating frequency will provide more energy.
Basically two resonant tanks coupled capacitively and inductively, having similar ratio between capacitor and inductors sizes to achieve the same resonant frequency. Energy must be extracted in a particular way, i'm thinking on it.
A capacitor having 3 plates forming two capacitors force coupled being one a fraction of the other, this same fraction should be respected on the inductors for the frequency be the same, and they should be made to have adjustment of coupling between them.
Than is a matter of driving the lower voltage tank, the one with less inductance.
Do the calculations.
Q=V*C
V=Q/C
C=Q/V
E=1/2*V^2*C
If we add enough induction to let the current from the first capacitor to charge into another smaller capacitor the energy will be multiplied by the factor of difference between the capacitors. As the gain is per cycle, choosing a higher operating frequency will provide more energy.
Basically two resonant tanks coupled capacitively and inductively, having similar ratio between capacitor and inductors sizes to achieve the same resonant frequency. Energy must be extracted in a particular way, i'm thinking on it.
A capacitor having 3 plates forming two capacitors force coupled being one a fraction of the other, this same fraction should be respected on the inductors for the frequency be the same, and they should be made to have adjustment of coupling between them.
Than is a matter of driving the lower voltage tank, the one with less inductance.
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