Solution Found?
V = 12
I = 2A
R = 6ohms
L = 0.96153846153846153846153846153846 H
1 TC = 0.16025641025641025641025641025633 (L/R)
V / L = 12.48 (constant rate of change of current)
1 TC * V / L = 1.999999999A
Here's how it works. At switch on, the battery will deliver a maximum current of 2 amps. It will reach 1.26A (63% increase) in a time of 0.16 for 1 TC. Switch is closed after 1 TC. A constant change in current of 12.48 for a time of 0.16 = 1.9999A. How can we have nearly 2 amps of current after 1 TC, when we only delivered 1.26 amps during the 1 TC? What am I doing wrong?
As a side note: I * 0.632120559 = 1.264241118 <---- I used .67 by accident without the extra precision in decimal digits and got 1.34 instead of the correct value of 1.264241118. This means L is close, but not the exact value needed. Regardless, we have a gain if the math and logic is right. Still trying to trace my steps in how the inductance was calculated in order to have the exact value, lol. Maybe I need some rest.
GB
V = 12
I = 2A
R = 6ohms
L = 0.96153846153846153846153846153846 H
1 TC = 0.16025641025641025641025641025633 (L/R)
V / L = 12.48 (constant rate of change of current)
1 TC * V / L = 1.999999999A
Here's how it works. At switch on, the battery will deliver a maximum current of 2 amps. It will reach 1.26A (63% increase) in a time of 0.16 for 1 TC. Switch is closed after 1 TC. A constant change in current of 12.48 for a time of 0.16 = 1.9999A. How can we have nearly 2 amps of current after 1 TC, when we only delivered 1.26 amps during the 1 TC? What am I doing wrong?
As a side note: I * 0.632120559 = 1.264241118 <---- I used .67 by accident without the extra precision in decimal digits and got 1.34 instead of the correct value of 1.264241118. This means L is close, but not the exact value needed. Regardless, we have a gain if the math and logic is right. Still trying to trace my steps in how the inductance was calculated in order to have the exact value, lol. Maybe I need some rest.
GB
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