Hall Effect Energy Generation

[elias]

Hi

Most of you know about the Hall Effect: Hall effect - Wikipedia, the free encyclopedia

This effect is widely used for sensing, but has it been thought to use it as an energy generation method? As it seems the the output energy flows perpendicular to the input energy, and seems to be more affected by the energy of the magnetic field, rather than the supplied current.

When we have got a conductor, and pass a current through it, the current can be deflected by using a strong magnetic field (e.g using a strong Neo Magnet) and a potential difference occurs perpendicular to the current flow. So can this potential difference used as an Energy Source? Any ideas? It seems that when we have got a current draw, a force can be applied by the magnetic field to create a potential difference which can provide energy. The question is: How much energy can be generated this way to surpass the energy needed to keep the current flowing. By using a very low voltage source, high currents can be generated by very low power levels.

I think that this system if properly designed can become a COP > 1 system.

To increase the potential difference, an n-type semiconductor is the best choice as it gives a very good potential difference.



I don't have n-type semiconductors at hand, any suggestions for buying?

Elias

[sebosfato]

Hello my friend, I'm why don't you try a thin copper foil having a big north pole and a big south pole glued on it and apply maybe 1 volt high amps longitudinally and measure the voltage on the sides? Would be a nice test.

I'm not sure if in a perfect conductor this would work but the voltage on its sides will be a function of the magnetic field, length and of the current passing... the internal resistance of the copper would be very small so even if the voltage is small it would have a big current capacity.


I know it works for particles and is related to the MHD studies but i have no idea if a conductor would work so well... Maybe if it is part of a resonant tank with very high current... don't know... when i can perform some tests here i will try it too. I have 100 x 4x2x1 neo magnets... would just need a big iron thick plate to stick the magnets to it so as to make a big pole. Maybe a good idea is to make this without the magnets maybe using two sheets having the current going in contrary direction. I only know the magnets will raise its induction...

[boguslaw]

Testatika Linden Experiment

[elias]

Hello my friend, I'm why don't you try a thin copper foil having a big north pole and a big south pole glued on it and apply maybe 1 volt high amps longitudinally and measure the voltage on the sides? Would be a nice test.

Yes my friend, I used copper, but copper, due to very high density of mobile carriers, leads to low voltages, fraction of millivolts, but by using an n-type semiconductor, one can yield voltages as high as 100 volts, because of lower density of mobile carriers. To yield a better voltage by using copper, one needs to use a very very thin copper foil, which seems not to be feasible for experimentation and requires nano-technology. The voltage produced is linearly related to the strength of magnetic field, so the power output increases by a power of 2, if you increase the magnetic field strength, while the current draw remains the same.

To get real results, semiconductors are needed. This would make us more voltage, thus increasing the COP, and making us produce usable power.

I am looking for buying an n-type semiconductor bar to test on it. Anyone can offer any suggestions for obtaining one?

This is really important people!, hall effect means creating a dipole by using the "free magnetic force", thus creating a free battery, by paying the price of some current at a very low voltage. (negligible power input, milliwatts)

[elias]

Testatika Linden Experiment

Thanks for the link, this effect is rather interesting, It is different though from the Hall Effect.

[elias]

would just need a big iron thick plate to stick the magnets to it so as to make a big pole.

No the thinner your plate becomes the higher the resulted potential difference you get, so go thinner. For thin copper, we can get about a mV, and for a thin n-semiconductor, you will get a much much higher voltage.

[sebosfato]

No the thinner your plate becomes the higher the resulted potential difference you get, so go thinner. For thin copper, we can get about a mV, and for a thin n-semiconductor, you will get a much much higher voltage.

I will give it a try here man, i have a copper foil like 0,3mm thick, and some powerful neo magnets. i will take a piece and insulate and than will take some magnets and stick on one another having the copper in the middle than i will apply a voltage on one side and check the voltage on the side.

[elias]

Hi,

Well, you need to go really thin to see some mVolts, about 0.05 mm or so.
A material that is lower mobile carrier density and low impedance is needed to generate usable power. I will post as soon as I get myself a slice of n-doped semiconductor. Still don't have a clue where to buy one. Maybe physics lab stuff?

Elias

[sebosfato]

Hi,

Well, you need to go really thin to see some mVolts, about 0.05 mm or so.
A material that is lower mobile carrier density and low impedance is needed to generate usable power. I will post as soon as I get myself a slice of n-doped semiconductor. Still don't have a clue where to buy one. Maybe physics lab stuff?

Elias

Not sure where you can find this. Maybe you can make one. For example aluminum becomes semiconductor when oxidizes not entirely only superficially but maybe is good enough. Maybe you can use the aluminum conductive part to pass the current with low losses creating the opposing magnetic field that creates the charge separation and than add some collectors on the semi-conductive sides.

You know that in a magnetic field electrons as very low mass entities tend to fly in circles creating like a planar vortex, this creates a i my imagination a kind of vortex magnetic field. They don't behave exactly as in the drawing...

Depends on the voltage applied or movement and magnetic field too. I think that thats why electrical generators at high voltage are more efficient.

[ibpointless2]

Seems like a good idea.

This guy in this video really explains the hall effect really well.
YouTube - Hall Effect - Sixty Symbols

Simple take a flat wire and place a magnet in the middle of it, then run power from one of the wire to the other end like you would with any wire. Now measure the voltage across the wire itself. Find a way to to combine the hall voltage with the voltage that is flowing from the wire and you'll get overunity.

[elias]

Seems like a good idea.

This guy in this video really explains the hall effect really well.
YouTube - Hall Effect - Sixty Symbols

Simple take a flat wire and place a magnet in the middle of it, then run power from one of the wire to the other end like you would with any wire. Now measure the voltage across the wire itself. Find a way to to combine the hall voltage with the voltage that is flowing from the wire and you'll get overunity.

Informative video, I think we can add that we can use the hall effect for energy production from a magnetic field too?!
A current is needed to produce the hall effect, not very much voltage, so we can produce a good Potential difference with minimal power. The question is, how much current we can draw from that potential difference, without affecting the output.

[broli]

Hi,

Well, you need to go really thin to see some mVolts, about 0.05 mm or so.
A material that is lower mobile carrier density and low impedance is needed to generate usable power. I will post as soon as I get myself a slice of n-doped semiconductor. Still don't have a clue where to buy one. Maybe physics lab stuff?

Elias

Search for "silicon wafer" on ebay or some other place. You'll find both n or p types.

[broli]

Also why not consider using a stack of copper foils to increase voltage? You can fold the copper onto itself in alternating fashion. Ten folds should increase your values one order of magnitude. You can put paper between each fold or any other insulator.

In the image below either one can be input/output, perhaps you'll find better results in a particular configuration.

Edit: I actually found an extremely simple folding technique that creates any preferred fold count without dealing with the tedious side connections. If you would use adhesive foil tape it would be even easier as the tape cover would work as insulator. It's very similar to this technique:

Concertina Caterpillar

But not quite. You need to double fold one of the strips for every fold of the other strip. This will give the desired series connection.

[elias]

Hi,

Thanks Broli, This idea occurred to me, but, doesn't the copper short out the series connections? Still thinking on it.

Elias

[broli]

In the first design (the image I attached) you must place an insulator between each fold to prevent shorting. When you use copper tape the plastic of the tape cover can be used as insulator.

However you would still be stuck with the very tedious task of hooking the sides up in series. That's where the second concept comes into play. You use very similar folding to 1) prevent shorting and 2) get your series connections from the sides very easily.

However the creases that stick out from the sides may cause shorting if they are packed too close. One solution would be to stick a small piece of regular tape on the creases before you start folding. So even if they stick out there's little chance for a short.

You don't need to fold both strips at the same time. You can fold them separately and then carefully push one of them into the side of the other. Making sure they contact correctly. This way in theory a 2m long tape of 1cm width can increase voltage by 100x. Because you need 2x1m strips. But then you have to make sure you field strength doesn't drop .