Parallel Self Charging

[ibpointless2]

Has anyone else experienced this?

You take two batteries or two capacitors and hook them up positive to positive and negative to negative; one battery or capacitor is bigger than the other and has a higher standing voltage. Once everything is all hooked up the Lower voltage battery or capacitor will go up as the higher voltage battery or capacitor will go down until they equal out. So let’s say the higher voltage battery or cap has 12.54 volts while the lower voltage one has 12.36 volts, both together have a total voltage of 12.54 + 12.36 = 24.90 volts. So when you hook them up positive to positive and negative to negative the voltage on both becomes 12.45 which makes since because their combine total voltage is still the same 12.45 +12.45 = 24.90 volts.


So here comes the crazy part, leaving it connected for some hours and it will start to climb up from the 12.45. Letting mine sit for 24 hours brought both batteries up to 12.50 volts with a combine total voltage of 12.50 + 12.50= 25 volts. 25 volts is much higher than the original 24.90 volts that I started with. So where does this extra power come from?

How to steps
1. Get two batteries or capacitors, one bigger than the other and make sure the bigger one has a higher voltage then the little one.

2. Allow both batteries or capacitors to sit for at least 12 hours not connected to anything so that they can get a standing voltage in them.

3. Measure the standing voltage of the big and little battery or capacitor, and then disconnect the meter.

4. Now hook them up positive to positive and negative to negative, see diagram below.

5. They should start to level out quickly, measure the voltage across both batteries or capacitors and when they both have the same voltage record that voltage. Disconnect meter.

6. Allow it to sit for 24 hours, you can check the voltage throughout that 24 hours but don’t leave the meter connected.

You can combine a battery and capacitor together if you want. The battery must be at a higher standing voltage then the capacitor. You would connect it up the same way, positive to positive and negative to negative.

Parallel Self Charging pic.jpg

[sucahyo]

6. Allow it to sit for 24 hours, you can check the voltage throughout that 24 hours but don’t leave the meter connected.

Do we need to sit it 12 hours un connected after that before measure it again?

[cikljamas]

25 volts is much higher than the original 24.90 volts that I started with.

Much higher ???

[Inquorate]

Much higher ???

when it should be lower in voltage, any increase is enormously significant. God this forum is full of that type of useless comment.

[FRC]

Maybe ???

This might be what was happening to me. A few years ago I was living in my
camper van while I was working on the west coast. I had an extension cord
hooked up to the battery of my truck. Each night I would come back to the
camper van and plug into the female end of the cord which was in the van hooked up to a 12 volt battery pak. I would run a small 75 watt inverter off
this and would use a 9 watt cfl, or 12 volt TV, and also my laptop. Not usually at the same time. I would sometimes be using power all night. I was not worried about running the the truck battery down to low, since I was parked on a bit of a hill, and could start it by rolling in reverse and engaging the reverse gear.I was very suprised, that even after seeming to draw lots of power on numerous occasions, never once did the truck not have enough juice to start on its own.It seemed like I was getting some kind of free energy thing happening. Usually,after going to sleep, there would not be anymore energy draw while both batteries were still hooked up, so they would be like that for a few hours resting.

FRC

[cikljamas]

when it should be lower in voltage, any increase is enormously significant. God this forum is full of that type of useless comment.

It is not useless, now we know that it is enormously significant increase !!!
Thanks !

[cikljamas]

They are made from scratch just for you

Now, you are probably thinking that custom golf clubs are even more expensive than name brand discount golf clubs. However, that is not necessarily the case. Not to mention that the fitted custom golf clubs you hear about aren’t anything at all like custom golf clubs, they are made from scratch just for you. Don’t get confused between fitted custom clubs and custom golf clubs. ishiner

Is this how you walk :
YouTube - Ministry of Silly Walks

[cikljamas]

if you do not have enough space, park like this :
YouTube - French Car Parking Technique 02

[cikljamas]

And if anybody interviewed you ever answer them like this :
YouTube - Brendan Venter's interview after a defeat to Racing Metro

[Zooty]

Has anyone else experienced this?

You take two batteries or two capacitors and hook them up positive to positive and negative to negative; one battery or capacitor is bigger than the other and has a higher standing voltage. Once everything is all hooked up the Lower voltage battery or capacitor will go up as the higher voltage battery or capacitor will go down until they equal out. So let’s say the higher voltage battery or cap has 12.54 volts while the lower voltage one has 12.36 volts, both together have a total voltage of 12.54 + 12.36 = 24.90 volts. So when you hook them up positive to positive and negative to negative the voltage on both becomes 12.45 which makes since because their combine total voltage is still the same 12.45 +12.45 = 24.90 volts.


So here comes the crazy part, leaving it connected for some hours and it will start to climb up from the 12.45. Letting mine sit for 24 hours brought both batteries up to 12.50 volts with a combine total voltage of 12.50 + 12.50= 25 volts. 25 volts is much higher than the original 24.90 volts that I started with. So where does this extra power come from?

How to steps
1. Get two batteries or capacitors, one bigger than the other and make sure the bigger one has a higher voltage then the little one.

2. Allow both batteries or capacitors to sit for at least 12 hours not connected to anything so that they can get a standing voltage in them.

3. Measure the standing voltage of the big and little battery or capacitor, and then disconnect the meter.

4. Now hook them up positive to positive and negative to negative, see diagram below.

5. They should start to level out quickly, measure the voltage across both batteries or capacitors and when they both have the same voltage record that voltage. Disconnect meter.

6. Allow it to sit for 24 hours, you can check the voltage throughout that 24 hours but don’t leave the meter connected.

You can combine a battery and capacitor together if you want. The battery must be at a higher standing voltage then the capacitor. You would connect it up the same way, positive to positive and negative to negative.

[ATTACH]7238[/ATTACH]

Even though they both add up to the same voltage or slightly more after the experiment, there is less energy overall after. The larger capacitor lost more joules than the smaller one gained. It's like saying a 10uf cap at 10v + 100uf at 20v is the same as 10uf@20v + 100uf@10v. It is not. Give us the capacitance and work out the joules then you will see that you have lost energy. Most people know that sorting 2 caps in parallel wastes a lot of charge, up to 50%

[ibpointless2]

Do we need to sit it 12 hours un connected after that before measure it again?

Keep it connected.

And it works better with capacitors.

[ibpointless2]

Even though they both add up to the same voltage or slightly more after the experiment, there is less energy overall after. The larger capacitor lost more joules than the smaller one gained. It's like saying a 10uf cap at 10v + 100uf at 20v is the same as 10uf@20v + 100uf@10v. It is not. Give us the capacitance and work out the joules then you will see that you have lost energy. Most people know that sorting 2 caps in parallel wastes a lot of charge, up to 50%

For the capacitor experiment....

I started out with two capacitors
The big one was a 4700uF 35volts ; its standing voltage at the start of the experiment was .874 volts.

The little one was a 220uF 50volts ; its standing voltage at the start of the experiment was .168 volts.

When i connected them the bigger one lost voltage and the little gain voltage, both equaled .874 volts. And then they started to gain voltage.

The next day it was up to .902

After 2 days it was up to .946

After letting it sit unconnected to anything for 12 hours the big one standing voltage equals .942volts and the little one equals .940 volts.

They both seem to be sitting at a higher standing voltage then with what they started with. .942volts is much higher than the original .874 volts that the big capacitor started with, Where did this extra power come from?

Here's a video of me playing with it a few days ago.
YouTube - Capacitors self charging off each other

[digitz]

Is this how you walk :
YouTube - Ministry of Silly Walks

You're replying to a computer bot sending automatic spam ads.

[quantumuppercut]

Tesla method of short pulsing a coil to achieve high radiant energy (V^2/R) and minimize current energy I^2R.

The reverse is short pulse a capacitor to achieve high I^2/R. This method is very useful to create heat or large magnetic field.

QU

[Jbignes5]

It is not real charge.

Unfortunately it is not a real charge. Just doing small tests with a single cap and battery I have found out that the gain in voltage is not real. As I measure the voltage on the single battery it lowers the value as the meter slumps back to the voltage that the battery was when I started the test.

It seems that the cap is converting some of the real current into a fluffy charge that sits on top of the real charge of the battery. As I have said before capacitors are a very weird thing. When they are used in such a way they convert some of the heavy charge in the battery to a new light floating charge. This makes the battery charge but not in the traditional sense.

Most of my tests are on batteries with a good physical state but lacking in full charge. Meaning at 12 volt battery riding at about 10.2 volts.

I highly doubt that capacitors allow a heavy current flow and this is where you are seeing a "Charge" but that charge is very very light.