Parallel Self Charging

[Jetijs]

IMHO this is no OU or anything like this. Consider this, if you would take a cap of 10000uF and charge that to 12v and then you take 1uF cap with 0V, you have a total voltage of 12v, now if you put both caps in parallel, the bigger one will decrease its voltage to some small extent, but the smaller one will charge up to say 11,5V. The combined voltage is now 23.5. Does it sound like anything significant here? You can't determine anything just by looking at voltages alone.

[ibpointless2]

IMHO this is no OU or anything like this. Consider this, if you would take a cap of 10000uF and charge that to 12v and then you take 1uF cap with 0V, you have a total voltage of 12v, now if you put both caps in parallel, the bigger one will decrease its voltage to some small extent, but the smaller one will charge up to say 11,5V. The combined voltage is now 23.5. Does it sound like anything significant here? You can't determine anything just by looking at voltages alone.

no no no you've got it all wrong.

I have two batteries or capacitors and the big one has 12.54 and the little one has 12.36. There total voltage combine is 24.90 volts, nothing special about that and certainly not OU. Its the fact that you leave them connected together and they rise to a total voltage of 25.00 volts. Its not the total voltage that makes it special but its the fact that for the total voltage to go up one of the capacitors have to go up too, but how can that happen if one goes up the other must go down in-order to keep balance.

There total standing voltage at the start was 24.90 volts, but left to sit together they rise to 25.00 volts.

Better yet explain this to me this...

I have two capacitors, the big one STANDING voltage is .874 volts and the little one is .168 volts.

The big one goes down of course as anyone would expect and the little one goes up until both meet at the middle. Now why does the voltage in the capacitors start going above the standing voltage of .874 to .902 in 12 hours?

How can the voltage go above original and the highest voltage of the two capacitors. Its like i have two cups and i pour them in a bucket that only holds two cups and i let it sit. Overnight for some odd reason the water has overflowed, how can that be when i have not added any more water.

[ibpointless2]

Unfortunately it is not a real charge. Just doing small tests with a single cap and battery I have found out that the gain in voltage is not real. As I measure the voltage on the single battery it lowers the value as the meter slumps back to the voltage that the battery was when I started the test.

It seems that the cap is converting some of the real current into a fluffy charge that sits on top of the real charge of the battery. As I have said before capacitors are a very weird thing. When they are used in such a way they convert some of the heavy charge in the battery to a new light floating charge. This makes the battery charge but not in the traditional sense.

Most of my tests are on batteries with a good physical state but lacking in full charge. Meaning at 12 volt battery riding at about 10.2 volts.

I highly doubt that capacitors allow a heavy current flow and this is where you are seeing a "Charge" but that charge is very very light.

When ever you do any charging of anything there will be a slight gain of fluffy voltage. I'm well aware of this, that is why allow my capacitors to charge for a some days and disconnected them for at least 12 hours so that the fluffy voltage would disappear. The starting standing voltage on the capacitor was .874 volts. The voltage on the capacitor when connected for a few days to the simple circuit was .946 volts. Leaving it disconnected for 12 hours so that it would remove the fluffy voltage it is now at .942 volts, which is still higher than the original standing voltage of .874 volts.

Try using only capacitors.

[ibpointless2]

Why is it the simplest of things that give people the hardest to understand.

I posted this to say "hey look at this", I never said overunity, but merely wanted people to be aware of this.

It's very simple idea that has given not so simple explanation.

The simple fact is that i have batteries and capacitors resting at a higher standing voltage then what they started with. I'm not out to trick anyone, if i was i would have made the circuit very complicated so that no one could copy it.

Sometimes its the simplest of answers that solve the complex questions.

[Magneticitist]

that is interesting but i notice stuff like that on batteries all the time. because of that i have to be real careful about paying attention to temp in the room or how long ago they were charged or discharged, or how, etc..

putting the caps in parallel though would be more like automatically making them find the "mean" between them rather than adding their total voltages, that would be a series right?

i also try to stress to people that ive noticed the voltage potential across caps and batteries seems to depend on the environment at the time.
i hardly have any capacitors at this point that ever stay discharged. leaving them shorted for days then unshorting them they will still charge back up a little. i've had caps that i could just leave there and every 6 hours or so get them to turn small DC motors a millimeter or something. this leads me to believe i can store 500 of these in series to get usable power.

putting two capacitances in series definitely increases the overall plate sizes, and thus would potentially form a much better miniature version of a tesla radiant capturing device.

[sucahyo]

negative result

I replicate the experiment with two 1000mAh nicad and two 55F/2.5V maxfarad capacitor, thanks to Ben .

joined at 10.45
after 13.11 = 2.60V
nextday 11:49 = 2.58V.

[Inquorate]

I replicate the experiment with two 1000mAh nicad and two 55F/2.5V maxfarad capacitor, thanks to Ben .

joined at 10.45
after 13.11 = 2.60V
nextday 11:49 = 2.58V.

so that's the first negative result reported.

55 Farad caps are too big for the effect to manifest.

Why?

And, i am beginning to think this captret effect is not useful, except possibly to keep shelved batteries charged between uses.. Not that that is a trifle.

@sucahyo those caps were expensive, glad to see you are using them

[ibpointless2]

so that's the first negative result reported.

55 Farad caps are too big for the effect to manifest.

Why?

And, i am beginning to think this captret effect is not useful, except possibly to keep shelved batteries charged between uses.. Not that that is a trifle.

@sucahyo those caps were expensive, glad to see you are using them

Yes his caps where to big and he should of done cap to cap and not cap to battery. Like i said, One big cap with more of a charge in it then the little cap and hook the up + to + and - to -

This Thread right here really had nothing to do with the captret, it was just to point out that a capacitors hook together would end up with a higher voltage then what they started out with.

And yes the captret works great for keeping batteries from going dead, especially where i work i see 12 volt batteries go dead because people neglect them and the capacitor can help keep its charge.

As for the captret being useless is a hard one to say.

I've had Captrets self charge batteries.

I've had captrets run a LED very nicely, and gave my 9 volts something to do instead of taking up space in a land fill.

But my latest captret is hand made and it amplifies the voltage of whats put into it. I've have a thread going on about it called " more voltage out then put it - water captret". Any power you give it and it will increase the voltage beyond what you supply. So My latest captret outputs more voltage than whats put into it.

YouTube - More Voltage out than in -- Water Captret


Its not that the captret is useless, its just that people don't care. I know that sounds rough but it is true. People want complex circuits with complex components; they want the mystery and the secret magical rock that will make it turn on and tap the ZPE field, but if you show them something simple they really don't care.

[sucahyo]

so that's the first negative result reported.

55 Farad caps are too big for the effect to manifest.

Why?

And, i am beginning to think this captret effect is not useful, except possibly to keep shelved batteries charged between uses.. Not that that is a trifle.

@sucahyo those caps were expensive, glad to see you are using them

I really thank you for that .

Yes his caps where to big and he should of done cap to cap and not cap to battery. Like i said, One big cap with more of a charge in it then the little cap and hook the up + to + and - to -

Ok. I have one 330uF/200V cap and 10000uF/50V will start with around 45V.

Edit: oops forgot, the capacitor would self discharge after 12 hours of standing. Will use as it is now 1.237V big cap, 0.95V small cap.

[elias]

two joined together would yield a greater power from the sum of two.

[sucahyo]

result:
16:17 1.221V
next day
08:00 1.280V
13:05 1.295V

still climbing, attaching meter reduce it right away.

[ibpointless2]

two joined together would yield a greater power from the sum of two.

Attaching the bigger one with more voltage to the little one with less voltage will cause the big one to give up power so that the little one can gain power. So in the end they should loose power but they gain it instead, it goes above the big ones original voltage and that should not happen. According to what we know the little one can't charge the big one because it has less power in it and the big one can't go above its original voltage because it had to give some up so that the big one and little one could equal out, but in the real world they seem to self charge off each other well above the original standing voltage on the big one.

So in the end there should be a loss, due to the internal loss of the capacitor and the wires that join them. But in the end they gain voltage.

[ewizard]

I think Jetijs was on the right track. I don't think you understood what he was saying though. I don't think you can equate voltage with buckets of water. Your buckets of water are like watts. Think of it this way. Let's say you have this big truck battery at 13.5 volts and about 150 pounds. Then you have a little Nicad pack made of 10 AAA size batteries in series that are run down to about 2 volts total (in series). You hook up the huge 12 volt truck battery that has a reading of 13.5 volts to your Nicad pack that reads 2 volts. In a few minutes you'll see your nicad pack at probably 13 volts. Your huge truck battery however is still reading 13.45 volts realistically. Starting combined voltage = 15.5 volts. Now it's 26.45 volts. Nothing special about it. You just transferred some power from a huge reserve to one that can only hold very little power.

[ibpointless2]

I think Jetijs was on the right track. I don't think you understood what he was saying though. I don't think you can equate voltage with buckets of water. Your buckets of water are like watts. Think of it this way. Let's say you have this big truck battery at 13.5 volts and about 150 pounds. Then you have a little Nicad pack made of 10 AAA size batteries in series that are run down to about 2 volts total (in series). You hook up the huge 12 volt truck battery that has a reading of 13.5 volts to your Nicad pack that reads 2 volts. In a few minutes you'll see your nicad pack at probably 13 volts. Your huge truck battery however is still reading 13.45 volts realistically. Starting combined voltage = 15.5 volts. Now it's 26.45 volts. Nothing special about it. You just transferred some power from a huge reserve to one that can only hold very little power.

You're not getting it. You're right so far about the big battery is now at 13.45 volts and so is the little battery but its when its starts going above the original starting voltage of 13.5 volts when left to sit in Parallel is what i'm talking about.

Theres nothing special about a big battery charging a little battery, whats special is when for no good reason they both start to higher in voltage than what the big battery started with. For the big battery to read higher than 13.5 volts is crazy because it hold have lost power to charge the little battery but instead they gain voltage higher than 13.5, and even if its only a 2 volt gain it's still something higher than the original voltage. When i talk about this i'm not talking about adding the voltage of the two but what one battery reads. So if one battery reads over 13.5 volts then its something very special.

[ewizard]

I missed that being the important point you were making. That would be significant but I still would have a couple concerns. I think you need a control set to run against since many batteries and especially lead acid batteries will have some self recovery over a period of time. If you start with fresh batteries at full voltage and you see this phenomenon then I'll believe you have something significant. Or if you have 2 batteries that were new and at the same voltage and both put under the same load until they are down a couple volts. Then put one in your circuit and leave the other one to just sit. After a period of time compare the voltages. Not trying to discourage as I think it's great you are an astute observer of such phenomenon but there needs to be something to compare against in this case to eliminate the possibility that it is no more than battery self recovery. Best of luck with the experiments.