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Dc Motor Over unity

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  • Dc Motor Over unity

    In a dc brushless motor the rotation depends on the force of the field created by the current on the wire in relation to the magnetic field so it does not relate completely to the energy going into dissipation on the wire. It relates only to the force. Unity was based on what? The copper conductivity? I mean that if you have super conductive wire you can and will have over unity cause you can develop a gigantic force consuming low power. I say to you that maybe the ac motors cant be over unity cause it depends on the creation of a field witch interact with the magnetic field in the worst manner possible. It always has a predetermined speed. While dc won't. The force will be aways aligned and perpendicular to the magnetic field, so is able to develop the strongest force per dissipation on the wire.

    So Why ac motors was created?

    To hide something?

    Where is the unity?

  • #2
    I would like to add that in this manner even a counter motive force would not imply in different consumption of power, as it would only be related to the voltage applied on the wire. Actually as the load increase the power consumed would reduce, as the magnets are holding the electrons on the wire. So for increasing the power you need to add more voltage.

    i would like to reinforce also that this same motor can be used as a generator.

    And the most important is that the motor of simple construction.

    If for example the wire have a resistance of 0,001 ohms and you apply 1 volt, you would have 1000 amps flowing, expending 1000 watts therefore... however as the force is dependent on the amps squared you get a Million factor in the equation.

    Think now if it was superconductive..

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    • #4
      Yeah, it's interesting. What is unity here?

      I would expand this with an example.
      Suppose we have a square coil of 1 m^2.

      1) We first use 30 awg wire = 0.25 mm, 0.05 mm^2 of area, 348.2 ohms/km, 400 turns.
      Each turn is 4 meters, so the wire will be 1600 m long, showing a resistance of 557 ohms. If we put 12V source to it, the current will be about 21.5 mA, so the power is 258 mW.
      Now, this coil creates a maximum magnetic field at the center of the coil of 0.0215 * 400 * someNumber = 8.6 * someNumber.

      2) And suppose we are going to do 800 turns with 30awg wire.
      If we use the same 12V, we will have half the current going through it, that is 12.25 mA, for 129 mW. Half the power.
      With half the power, we create a magnetic of the same intensity. What is the limit to this? What is unity?

      EDIT: the previous example didn't hold, so I modified it.
      Last edited by caru; 12-27-2010, 02:59 AM.

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      • #5
        Yes thats what i'm saying.

        if the force acting on a wire in relation to a perpendicular magnetic field depends on the amps only. Why to not use huge copper wires and very very low voltage at huge amperage to spin the motor. Ac becomes interesting if you could have a big enough capacitor to run this huge amperage, but the speed become fixed. So the best idea would be to use a faraday disc to generate huge amperage at low volts dc.

        Lets say make a motor to run at 100mv 1000 amps cause the wire will have only few microohms resistance...

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        • #6
          I'm still thinking bout this, and can't find a reason why this in theory could be wrong. Anyone any idea.


          Of course the problem would be the power supply for the motor with such a high amperage. I thought of a VLF very slow resonant tank with two huge capacitors being the coil the field coil of the motor. The tank could be controlled by with relays with zero current switch.

          anyway

          The idea is can we create magnetic force causing less dissipation to be able to run a motor into over unity?

          Will the resistance be the only thing that will consume energy in the motor if configured this way?

          Or there will be the need for a voltage greater than the voltage needed to induce the high amperage on the resistance only by a impedance of a certain kind that could consume the energy without causing heat?

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