If this is your first visit, be sure to
check out the FAQ by clicking the
link above. You may have to register
before you can post: click the register link above to proceed. To start viewing messages,
select the forum that you want to visit from the selection below.
Because laptop power supplies are switch mode types, their mains input impedance is mainly inductive at 50 or 60 Hz (due to the switched transformer primary coil at the input) so the AC voltage and AC current is not in phase like in case of a resistive load like a electric heater or iron etc.
The phase difference is expressed in degrees and the Power Factor number is the cosine value of this degree.
So the phase angle in your example is arc cos(PF)= arc cos(.47)=61.96 degree, this must be the phase angle between the 120V ac voltage and the .35 A AC current feeding your laptop.
The formula for power when AC voltage and current is not in phase (i.e. the phase angle is not zero or near zero degree, cos(0)=1) is:
Power=V*I*cos(theta) where theta is the phase angle between V and I.
Now multiplying your 42.05W by the PF=.47 it gives 19.76W, pretty close to what your meter showed (21W).
So the Watt display is calibrated by the actual PF involved, it is factored in.
Gyula
PS Some good reading on this: Calculating power factor : POWER FACTOR
(It shows also how to improve PF when it is caused by inductive loads, by compensating the inductance part with an equivalent AC impedance value capacitor.)
Comment