Ok I don't see how it is all that much different to the effect when produced by this setup of mine. My setup is just a solid state resonant generator which puts out a sine wave at about 480 Khz the amplitude can be varied. In the video it uses just about 900 Ma at 12.5 volts, so about 11.25 watts while powering a load of 6 x 5 mm LED's, not sure of the current through those not much. Then when I load the system with the cap discharger to charge a battery more energy is used there but the input current halve's, it reduces to only about 450 mA at 12.5 volts or about 5.625 watts , thereby saving me 5,625 watts from an already loaded condition. Which in my opinion is better than a saving from an idle condition eg. (no load).
So all up I saved about half of the original input by using a couple of watts.
Started with 11.25 watts slightly loaded
Went to 5.625 watts when loaded by more load, maybe a couple of more watts not much.
Obviously this is fairly efficient as compared to over 70 watts input power to supply a load with 2 watts. And much safer too I might add.
Reduced input current with added load.wmv - YouTube
I'm not saying there is anything special about this effect, I think it happens because the load is sufficient to drag down the sine wave which in turn reduces any reverse effects, of course. And this reduces losses and thereby input power. Thats just how it works.
Incase no one noticed, the amount saved was almost exactly the same as the amount it used under the extra load.
And the effect is exactly the same when a small incandescent bulb is used in place of the battery.
Cheers
So all up I saved about half of the original input by using a couple of watts.
Started with 11.25 watts slightly loaded
Went to 5.625 watts when loaded by more load, maybe a couple of more watts not much.
Obviously this is fairly efficient as compared to over 70 watts input power to supply a load with 2 watts. And much safer too I might add.
Reduced input current with added load.wmv - YouTube
I'm not saying there is anything special about this effect, I think it happens because the load is sufficient to drag down the sine wave which in turn reduces any reverse effects, of course. And this reduces losses and thereby input power. Thats just how it works.
Incase no one noticed, the amount saved was almost exactly the same as the amount it used under the extra load.
And the effect is exactly the same when a small incandescent bulb is used in place of the battery.
Cheers
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