Ok Here we go! In for a penny, in for a pound as the saying goes…
Thanks for the replies. @Turin, I do see that the motor issue is bouncing about, and as soon as I can understand the diagram (It bends my brain somehow, UFO probably spoiled me with his lovely pics!) I will mod a motor I have here. When I can get a battery I will start my own experimenting.
Here is my take on some of it. Remember, This is what I think and may not be right! Comments are welcome….
In one of your posts you mentioned this,
I couldn't sleep this morning so as I made the wife coffee, I was pondering the 3BGS and thought I would share something. I have repeated the story many times of how, when my original device "came to life" after 15 minutes, I immediately put a meter on battery three.
What I saw was that it would read 24 volts, go slowly down to 18 IN JUST A MATTER OF MINUTES, at which point the motor would start, and it would continue to run as the voltage continued to drop down to around 8 or 9 volts, at which point the motor would shut off.
The voltage would immediately jump to 24 volts and the process would repeat over and over.
so here is my take on it -
What I saw was that it would read 24 volts,
Bat 3 is high impedance so there is no current flow to drop voltage over the motor so the supply voltage is being totally transferred to bat 3
go slowly down to 18 IN JUST A MATTER OF MINUTES,
The only way the voltage here can fall below the supply voltage (24v) is by a current flow into bat3 causing a volt drop across the motor. (24-18 = 6v across motor)
at which point the motor would start,
sufficient current flow and volt drop has been arrived at (6v – current unknown)
and it would continue to run as the voltage continued to drop down to around 8 or 9 volts,
Why is the bat3 voltage dropping? This has to be because the current into bat3 is increasing.
As the current flow into bat3 increases the volt drop across the motor also increases. The motor would speed up. And the current increased until the volt drop across the motor was approx 15v
Why does the current into bat3 increase? This has to be because the impedance of bat3 is reducing.
What is causing the impedance of bat3 to reduce?
OR maybe the right question –
What causes the impedance of bat3 to be high in the first place?
The high impedance is caused by the sulphate build up. So that would point to the reduction of impedance being caused by a reduction in the sulphate build up.
However, that is difficult to square with the next point which requires the motor to stop and the voltage to go back up to supply. (Implying no current flow! (Or more correctly, too low to cause easily measurable volt drop)) That implies the impedance has gone right back up to where it was prior to motor start.
at which point the motor would shut off.
Why would the motor shut off – because there is no current flow BUT with an implied 15v across the motor this does not make sense! There was a healthy current flow - why did it stop? Must be because the impedance has gone up. But how could the impedance jump back up if it is reducing because of a reduction in the sulphate build up? That leads us to the next point -
The voltage would immediately jump to 24 volts and the process would repeat over and over.
Which, as I said, implies the impedance has gone right back up to where it was prior to motor start.
There is only one thing that I can think of that could fit the bill here. That is that the system is entering resonance. We start with a small trickle of current that slowly grows to the point where the motor starts.
At that point the whole picture changes because we have changed our supply from a straight DC to a variable frequency pulsed DC system, and that triggers the system into a resonant phase with an increasing frequency.
As the resonance increases, it draws more current. As it draws more current the motor speeds up. As the motor speeds up the resonant frequency increases. It will climb until it reaches the point where the frequency is too high for the system to sustain. At that point it will suddenly collapse, the impedance will revert to the normal bat3 impedance, the voltage will jump to supply (No current to cause a volt drop across the motor) and the whole shebang will start again.
In one of Duncan’s posts I saw a reference to this being a tuned aerial / crystal demodulator rolled into one. I totally agree with that concept. I think that by changing the loading and the motor speed, and thereby the tuned frequency, we are attempting to tune the system to the station we want. Instead of music it gives us power.
I may be totally wrong about all this, but what the hay!
Some thoughts on bat 3
I think that the need for that initial startup current to get the motor running is what calls for a shorted battery. (Otherwise if the bat was only heavily sulphated with high impedance the process may never start.) This would imply that if one had a heavily sulphated battery with no short, one could supply a small load in parallel with the battery to cause the current to flow and start the process. It would need to be large enough to cause the motor to start.
One of the problems with bat3 is that it eventually clears the sulphate and charges, this rendering it useless as a crystal resonator. Unfortunately, the method we use as a ‘tickler’ is a very fine means of removing the sulphate build up. We are not concerned with removing the sulphate crystals, in fact quite the opposite. So, how to stop this happening?
Well, what purpose does the electrolyte play in our resonator? What if we take a heavily sulphated bat, empty out the acid and flush out the bat with a hose and tap water and then let it dry out? Could we still get the crystals to resonate?
Without electrolyte we may have a problem here in that we are using a battery not a cell. To recap, a battery is a collection of cells connected in series. We are connecting to the two end cells. Without electrolyte we may not have the connection necessary through the battery to energize the resonance with our motor pulse. Now, with a single cell, all the positive plates are connected in parallel and all the negative plates are connected in parallel. So, when we connect to one cell the pulse will energize both sides of the cell. (We could connect a number of cells in parallel, that would still work.)
This is all speculation and would need someone to try it out.
You do see, this is all speculation? I could be wildly off course here!
But it is all something to think on…. As soon as I can get some suitable batteries I will do a few experiments for myself.
In the meantime I will continue to think on this…
DaveSw
Thanks for the replies. @Turin, I do see that the motor issue is bouncing about, and as soon as I can understand the diagram (It bends my brain somehow, UFO probably spoiled me with his lovely pics!) I will mod a motor I have here. When I can get a battery I will start my own experimenting.
Here is my take on some of it. Remember, This is what I think and may not be right! Comments are welcome….
In one of your posts you mentioned this,
I couldn't sleep this morning so as I made the wife coffee, I was pondering the 3BGS and thought I would share something. I have repeated the story many times of how, when my original device "came to life" after 15 minutes, I immediately put a meter on battery three.
What I saw was that it would read 24 volts, go slowly down to 18 IN JUST A MATTER OF MINUTES, at which point the motor would start, and it would continue to run as the voltage continued to drop down to around 8 or 9 volts, at which point the motor would shut off.
The voltage would immediately jump to 24 volts and the process would repeat over and over.
so here is my take on it -
What I saw was that it would read 24 volts,
Bat 3 is high impedance so there is no current flow to drop voltage over the motor so the supply voltage is being totally transferred to bat 3
go slowly down to 18 IN JUST A MATTER OF MINUTES,
The only way the voltage here can fall below the supply voltage (24v) is by a current flow into bat3 causing a volt drop across the motor. (24-18 = 6v across motor)
at which point the motor would start,
sufficient current flow and volt drop has been arrived at (6v – current unknown)
and it would continue to run as the voltage continued to drop down to around 8 or 9 volts,
Why is the bat3 voltage dropping? This has to be because the current into bat3 is increasing.
As the current flow into bat3 increases the volt drop across the motor also increases. The motor would speed up. And the current increased until the volt drop across the motor was approx 15v
Why does the current into bat3 increase? This has to be because the impedance of bat3 is reducing.
What is causing the impedance of bat3 to reduce?
OR maybe the right question –
What causes the impedance of bat3 to be high in the first place?
The high impedance is caused by the sulphate build up. So that would point to the reduction of impedance being caused by a reduction in the sulphate build up.
However, that is difficult to square with the next point which requires the motor to stop and the voltage to go back up to supply. (Implying no current flow! (Or more correctly, too low to cause easily measurable volt drop)) That implies the impedance has gone right back up to where it was prior to motor start.
at which point the motor would shut off.
Why would the motor shut off – because there is no current flow BUT with an implied 15v across the motor this does not make sense! There was a healthy current flow - why did it stop? Must be because the impedance has gone up. But how could the impedance jump back up if it is reducing because of a reduction in the sulphate build up? That leads us to the next point -
The voltage would immediately jump to 24 volts and the process would repeat over and over.
Which, as I said, implies the impedance has gone right back up to where it was prior to motor start.
There is only one thing that I can think of that could fit the bill here. That is that the system is entering resonance. We start with a small trickle of current that slowly grows to the point where the motor starts.
At that point the whole picture changes because we have changed our supply from a straight DC to a variable frequency pulsed DC system, and that triggers the system into a resonant phase with an increasing frequency.
As the resonance increases, it draws more current. As it draws more current the motor speeds up. As the motor speeds up the resonant frequency increases. It will climb until it reaches the point where the frequency is too high for the system to sustain. At that point it will suddenly collapse, the impedance will revert to the normal bat3 impedance, the voltage will jump to supply (No current to cause a volt drop across the motor) and the whole shebang will start again.
In one of Duncan’s posts I saw a reference to this being a tuned aerial / crystal demodulator rolled into one. I totally agree with that concept. I think that by changing the loading and the motor speed, and thereby the tuned frequency, we are attempting to tune the system to the station we want. Instead of music it gives us power.
I may be totally wrong about all this, but what the hay!
Some thoughts on bat 3
I think that the need for that initial startup current to get the motor running is what calls for a shorted battery. (Otherwise if the bat was only heavily sulphated with high impedance the process may never start.) This would imply that if one had a heavily sulphated battery with no short, one could supply a small load in parallel with the battery to cause the current to flow and start the process. It would need to be large enough to cause the motor to start.
One of the problems with bat3 is that it eventually clears the sulphate and charges, this rendering it useless as a crystal resonator. Unfortunately, the method we use as a ‘tickler’ is a very fine means of removing the sulphate build up. We are not concerned with removing the sulphate crystals, in fact quite the opposite. So, how to stop this happening?
Well, what purpose does the electrolyte play in our resonator? What if we take a heavily sulphated bat, empty out the acid and flush out the bat with a hose and tap water and then let it dry out? Could we still get the crystals to resonate?
Without electrolyte we may have a problem here in that we are using a battery not a cell. To recap, a battery is a collection of cells connected in series. We are connecting to the two end cells. Without electrolyte we may not have the connection necessary through the battery to energize the resonance with our motor pulse. Now, with a single cell, all the positive plates are connected in parallel and all the negative plates are connected in parallel. So, when we connect to one cell the pulse will energize both sides of the cell. (We could connect a number of cells in parallel, that would still work.)
This is all speculation and would need someone to try it out.
You do see, this is all speculation? I could be wildly off course here!
But it is all something to think on…. As soon as I can get some suitable batteries I will do a few experiments for myself.
In the meantime I will continue to think on this…
DaveSw
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