Eric Dollard

[dR-Green]

You live in a beautiful historic area. How is your Welsh?

Yeah it is now that you mention it, as usual though I take it for granted. The village itself has interesting history. Oliver Cromwell is said to have liked the pub up the road, and there's a secret underground passage joining the pub to the church which was used to make their escape from the authorities. My great great grandfather was one of these too, now I know where I get it from

Rebecca Riots - Wikipedia, the free encyclopedia

The only non-Welsh speaker in the family was my grandmother so up until secondary school she and TV was the only place I came across English. They didn't make Ghostbusters in Welsh so that might be a good thing!

[dR-Green]

While some similar forces are at work here, it is different from capillary attraction, a process where glass or other solid substances attract water, but are not changed in the process (e.g., water molecules do not become suspended between the glass molecules).

The similar-sounding but unrelated word hydroscopic is sometimes used in error for hygroscopic. A hydroscope is an optical device used for making observations deep under water.

https://en.wikipedia.org/wiki/Hygroscopy

[orgonaut314]

Yeah NFG that is probable me. But it is allways the same. Create a guru, create an enemy and fill the heads with stuff. When do you people learn to be independend and grow up? Start with critisism just enough to stand on you own feet. Advise from a guru groupy himself

[Sputins]

No. But when you disect in outer space the charge will be on the plates. There is no layer of moisture on the glass that conucts the charge from the plates to the glass.

Just read the wiki article espescially the part about where the charge is stored. At first I also wanted Eric to be right but this example made me realise he just ignores recent evidence and experiments. In other occasions he just talks latin to people that do not understand latin. He is a disinformant telling that others are disinformants. Just a clever trap. But there is some truth, mixed with lies. There has to be cheese in a mouse trap

NFG!



Sputins

[Nhopa]

Lets just stay on earth for now and for a moment work with glass. I am very much interested in capacitors. One of my future project will be with Tesla's Radiant Energy patents US685957 and US685958. I got the ideal from
dR-Green who mentioned Tesla's interest in this subject. In these patents Tesla is using large capacitors first to collect the positive charges from the solar radiation and to get the complimentary negative charges from the earth.
In my previous posts I had some questions, like do I need a full size metal plate to charge the "wet" glass plate or maybe a wire contacting the glass dielectric would be sufficient to charge the glass since the charges would just "slide" all over on the glass? What if I would deposit a few microns thick metal layer on both sides of the glass dielectric. This plate capacitor would function but the question is if I take such a capacitor apart, where will the charges be, on the metal plates or on the metalized dielectric? Have anybody done this? Let me know what you think.

[orgonaut314]

I just had another thought about orgonaut314 comment, based on which this leyden jar would not function in outer space. No atmosphere, no moisture. So are we saying that plate capacitors with glass dielectrics will only function on earth?

No. But when you disect in outer space the charge will be on the plates. There is no layer of moisture on the glass that conucts the charge from the plates to the glass.

Just read the wiki article espescially the part about where the charge is stored. At first I also wanted Eric to be right but this example made me realise he just ignores recent evidence and experiments. In other occasions he just talks latin to people that do not understand latin. He is a disinformant telling that others are disinformants. Just a clever trap. But there is some truth, mixed with lies. There has to be cheese in a mouse trap

[orgonaut314]

Think about the parafin dielectric. Parafin does not absorb moisture. When you make a leyden jar with parafin you can disect the parfin and the energy will be on the plates.

Do not forget this leydn jar had people think the charge was in the dielectric for some time untill experiments proved otherwise.

[Nhopa]

I just had another thought about orgonaut314 comment, based on which this leyden jar would not function in outer space. No atmosphere, no moisture. So are we saying that plate capacitors with glass dielectrics will only function on earth?

[Nhopa]

Interesting observation. So if in the MIT demonstration the glass dielectric would have been baked in an oven to get rid of all the moisture on the surface, then the leyden jar would not work as a capacitor? On the other hand if it is really the moisture that retains the charge, then instead of a metal plate, one only needs a "charging" metal wire contacting the glass because the "conductive" glass will take all the charges that comes from the wire (let say up to break down).

[Sputins]

The Dielectric Indeed

Hi Nhopa, the glass has moisture absorbed. Moisture is the conductor that works as a metal plate. Only moisture on the surface.

This should put you back on the rails again...

https://youtu.be/NQO-p_ff0Xs

Richard Hull from TCBOR shows the dissectible capacitor experiment. No moisture in glass here. (It took me awhile to dig this out of the 60 videos).

[orgonaut314]

Hi Nhopa, the glass has moisture absorbed. Moisture is the conductor that works as a metal plate. Only moisture on the surface.

[David G Dawson]

Henry Cavendish and Various

Henry Cavendish and his 'Electrical Researches' Volume 1:

https://archive.org/details/electricalresear00caveuoft

Edited by James Clerk Maxwell.
Brilliant English lone researcher that used his body as the meter to detect current.

The Cavendish Experiment:

https://www.youtube.com/watch?v=2PdiUoKa9Nw

Will be getting back into the Lab after the heat sets in with Vacuum Tubes into the TMT.
Just moved, with my wife, some 14 tonnes of gravel on the driveway, looks good - distractions!
Just bought an 8" Saxon Dobsonian Telescope to look at where the Cosmic Rays are coming from - another distraction.

Eric Dollard should have taken up my offer in the Land Of Oz, a fully equipped Lab outfitted with Henry Ford Buzz boxes and a Grey Shrike Thrush guarding the front door.
Sorry that it did not work out with John.
Preparing a snail mail with respect to the Vacuum Tube builds - Tesla Transformer Pulse Generator/Regenerative Magnifying Receiver/Cosmic Ray Detector.
Also a dual 5U4G rectifier power supply that was involved with the implosion TV event where the AC (5volt) and DC (405 volt) are together at the output.

Aetheric Weather Engineering continues successfully with 22 devices of 11 different methodologies - makes current science look a little sick.
Be back soon.

Smokey

[Nhopa]

After viewing the MIT video it is interesting to speculate about capacitors in general. The text books state that the charges reside on the metal plates.
The following experiments serve no practical purpose at this time just food for thoughts.

If I have a two plate capacitor with air as the dielectric than where would the + and - charges reside? Perhaps on the metal plates?
With this same capacitor with glass as the dielectric the charges would reside on the two sides of the glass plate, + on one side and - on the other.
So if I have a stack of glass dielectrics I can charge each glass plate to a certain Q. If I take this plate out and charge the next plate and remove it, then I can place the second plate on top of the first one so that - goes on -. The next time I repeat this I will place + on + on both sides of the two plates I already have and on the next plates I alternate as required. Of course the total charge on each plate has to be a little less than half of the break down charge of the dielectric.
So I can go as long as I want and store all those charges in one place. If I put them in a non-conducting container where I have contacts on one side to the negative charges and on the other side I have contacts to the positive charges then in essence I created a super capacitor without metal plates, or did I?
If I would charge each glass plate of say area=2A, but the metal plates on both sides would only be area=A, what will be the total charge on the glass plate? What is the limiting size that will control the total charge, the metal plates or the glass plate sizes? Please let me know what you think.

[orgonaut314]

Perhaps interesting as Dollard says charge is stored in the dielectric and used the leyden jar as example

https://en.m.wikipedia.org/wiki/Leyden_jar

It was generally believed in 1800 that the charge was in the glass because of the leyden jar untill they found out it was a special case as glass is hydroscopic (absorbs water).

The same experiment with parafin made it clear the charge was on the plates.


Addenbrook (1922) found that in a dissectible jar made of paraffin wax, or glass baked to remove moisture, the charge remained on the metal plates.[9] Zeleny (1944) confirmed these results ...


Now we have the information to understand this video
Dissectible Capacitor | MIT Video

[Nhopa]

I completed connecting the star radial grounding rods, all is left to bring the ground into the house. On the telluric antenna I added an extra 300 feet to the existing 200 feet long wire. When I was tuned to a weak station the connected the 200 feet wire the reception got much stronger and when I connected the extra 300 feet there was no change in the reception strength. Next I tuned to a weak station approximately twice the frequency than before and the result was much better reception with the 200+300 feet long antenna.
The way I see it is the AM band is 600 kHz to 1600 kHz. A full wave antenna would be 498 m (1633 Ft) to 186 m (613 Ft) long corresponding to 600 kHz and 1600 kHz respectively. Antenna books indicate that reception is good with 1/2 wave or even 1/4 wave long antennas. So in a frugal design, one can get away using a 409 feet long antenna to cover the AM spectrum.
A full wavelength design would be 1633 feet long. In Eric's case he is working with twice 6000 feet wire antenna. In the antenna books I could not find that "longer is better", but 12,000 feet definitely covers the spectrum multiple times, so it could not hurt.
I am not an antenna designer and if in case the aerial antenna rules do not apply to the telluric antennas then I would ask Eric to gives us a "primer" on antennas in general. Have a good weekend.