Peter, whatever happened with Eric P. Dollard?

[jake]

@ Mad:

Yea, I posted that on the yahoo groups. I liked the "inches conversion" you added. But I'm a chemist so it's all metric for me.

The skin depth calculator will help me tramendously when I build my second generation crystal set. Im anal about using more wire then you neek. but I have to stick with 10/sqrt(F) when building the tesla transformer or until I understand what Im even trying to do there.



I knew nothing about crystal sets 5 months ago but after going through what feels like 100s of "how to's" form the 40s, 50s and 60s I am overwhelmed by the variaty and impressed by the simplicity of a crystal reciever.


I am waiting on a peizo earpiece and some germanium diodes I'm using a shottky for now. but I really want to hear it, but for now I can only see it on a DSOnano. It's taking every ounce of restraint to keep from building a simple amplifier.

[Kokomoj0]

If I read his Fq right that's 3.725Mhz which makes the secondary coil about 8" in Dia. that's small.

thats pretty high freq to put through the ground, and the higher the freq the more difficult I imagine it would be to get resonant with the earth since the earth is not a perfect sphere.

[Raui]

I very recently came into possession of the following documents that I thought might be helpful. Two of them are by Arthur Kennelly entitled 'Vector Power in Alternating Current Circuits' and 'Impedance, Angular Velocities & Frequencies of Oscillating Currents' both of which have been referenced by Eric and I've yet to see any mention of them here. The other has not been directly referenced but is related to complex quantities applied to electrical engineering which is related to Eric's 4 quadrant theory.

Vector Power in Alternating Current Circuits
Impedance, Angular Velocities & Frequencies of Oscillating Currents
--
Complex Quantities and their use in Electrical Engineering

Raui

[madhatter]

if you are going to build one that big might I suggest that you tune it near a harmonic of the earths resonance?

If I read his Fq right that's 3.725Mhz which makes the secondary coil about 8" in Dia. that's small.

[Kokomoj0]

Thanks! I have seen Eric's restatement of Tesla's "equal weights" dictum to "equal effects." What I had been thinking about was a copper strip primary, with the 14AWG secondary. Now, I'm guessing that he means 14 ga. solid?

One of my questions was whether Eric was using it to transmit -- or just as a receiving outfit. The SBARC video seemed to indicate, from a comment he made in response to a question, that he was using it for both.



Thanks! Looks like that should be (4.8 x 10*9/f in cycles)/100 to get that answer?

In that case I'll plug my numbers: (4.8 x 10*9/3725000)/100 = 12.8859 metres.

I was thinking about something a metre in diametre at the primary, which at a 3-lamba/4 secondary would be somewhere around 20 turns in a spiral. I approximated number of turns (at velocity C) by figuring the diametre of progressively smaller circles, using a 1 cm turn spacing. Nice to work at low freqs where a centimetre more or less is essentially insignificant (instead of five wavelengths )

Thanks for the input. I'm obviously still trying to make sense of all this!

if you are going to build one that big might I suggest that you tune it near a harmonic of the earths resonance?

[Skiv]

Hi Skiv. Rather than answering all your questions directly I will give you my flat spiral coil specs to give you an idea, built before any of the crystal radio stuff came up so wasn't intended for any of this, using the method described a few pages back (starting with primary and matching copper weight for secondary).

Thanks! I have seen Eric's restatement of Tesla's "equal weights" dictum to "equal effects." What I had been thinking about was a copper strip primary, with the 14AWG secondary. Now, I'm guessing that he means 14 ga. solid?

One of my questions was whether Eric was using it to transmit -- or just as a receiving outfit. The SBARC video seemed to indicate, from a comment he made in response to a question, that he was using it for both.

In relation to Eric's equation for calculating secondary conductor length:

ls = 4.8 x 10*9 / 882000 = 54.421768707482993197278911564626 metres

Thanks! Looks like that should be (4.8 x 10*9/f in cycles)/100 to get that answer?

In that case I'll plug my numbers: (4.8 x 10*9/3725000)/100 = 12.8859 metres.

I was thinking about something a metre in diametre at the primary, which at a 3-lamba/4 secondary would be somewhere around 20 turns in a spiral. I approximated number of turns (at velocity C) by figuring the diametre of progressively smaller circles, using a 1 cm turn spacing. Nice to work at low freqs where a centimetre more or less is essentially insignificant (instead of five wavelengths )

Thanks for the input. I'm obviously still trying to make sense of all this!

[madhatter]

Jake, I believe you posted the xcel sheet on groups. I've edited it a bit to match my notes and the noticeable issue is that as the Fq increases the scale decreases to where it's physically impossible to build such a unit based on Erics dimensions.

I had to take some liberties and ignore the skin depth equation as it's not the one I know of, and use the long version with permeability resistivity etc...

Active copper dia I take to mean as the skin depth in cmils converted to a wire gauge that utilizes the full current depth. Not familiar with Erics eq but there are some out there on the net that will calculate it based on Fq. need to run some calcs on that and see if that's what his intent was.

For those who have managed to build this receiver, what dimensions were used? as noted the worksheets posted by Eric are not going to get one all the needed information.

[jake]

dude really 62% again

I think the reason for the 62% spacing is because you have to think of each pair of windings as a capacitor. As the windings get further apart, the distributed capacitance between every turn starts to add up. The farther the plates of a capacitor are apart, the smaller the capacitor. Therefore, the farther the turns in a coil are apart, the smaller the distributed capacitance of the coil. You can see tesla calculating this and talking about it in "Colorado Springs Notes."

or

7imix,

I would have to disagree somewhat with what you just wrote. In the secondary I believe you increase the diameter of the windings and decrease the number of windingss to proportionate the magnetic field to dielectric for a subsequent balanced ELECTRIC FIELD as per Mr. Dollard's "Transmissions" have pointed out (less turns less magnetic energy, larger surface-area between turns more dielectric energy). I may be wrong but I believe that the two voltages e & E are designed to nullify one another in the secondary BUT the currents i & I DON'T. Thus creating a MONO-POLAR or longitudinal current for ONE WIRE transmission through the earth (with an appropriate receiver of course).

Ok, If we go down this road. What definations apply?

i.e.
What equation determines the capatance of the side by side windings?

What equation determines the inductance of the side by side windings?

and

Do you set them equal to each other or take the product equal to 1?



Also,

The negative numbers on the extra coil.

I agree with what some of you have said. everything about the extra coil wire size is predetermined by formula.

Therefore you may have a few options. Wind what you have on there and either:

equally space it out,
or
slowly increase the spacing as you reach the end of the coil like in the Colorado coil,
or
balance it out like others have suggested<----- I like this idea and is why I cant get over the spacing aspect.


jake

[7imix]

7imix,

I would have to disagree somewhat with what you just wrote. In the secondary I believe you increase the diameter of the windings and decrease the number of windingss to proportionate the magnetic field to dielectric for a subsequent balanced ELECTRIC FIELD as per Mr. Dollard's "Transmissions" have pointed out (less turns less magnetic energy, larger surface-area between turns more dielectric energy). I may be wrong but I believe that the two voltages e & E are designed to nullify one another in the secondary BUT the currents i & I DON'T. Thus creating a MONO-POLAR or longitudinal current for ONE WIRE transmission through the earth (with an appropriate receiver of course). The extra coil, which isn't always used, on the other hand is made to do the exact opposite, or have the least self capacity and mutual inductance while having the most self inductance and possibly mutual-capacity as well. Here the currents i & I nullify leaving only a mono-polar voltage. The terminal capacity, and its delay line, may be used to control the voltage gradient emitted by the extra coil, which is clearly seen to be a problem in the Colorado Springs transmitters. The exact relation of the secondary and extra coil is a bit cloudy for me right now. Exactly how these all work together, I'm unsure at the moment.

Garrett M

I'm sorry, I'm not sure what you are disagreeing with me about. The edit function is broken, so I was not able to make my edit to fix where I misspoke about the conductor distance affecting the capacitance. As the conductors get farther apart, the capacitor gets smaller.

I was just talking about the distributed capacitance of coils in general, and should not have made a distinction about whether it was an extra coil or secondary.

Increasing the diameter of the windings to increase inductance, and increasing the distance between turns and decreasing the number of turns to reduce capacitance, in order to balance coil (especially when taking the actual wire length versus frequency into account) is exactly what I was talking about.

[Kokomoj0]

This is real PITA! the edit function is a not working!

The above equation should read: H-(d x N)/N-1

yep I have lost several posts that way! Try and remember to hit advanced then preview then save and it will work every time.

[jake]

Active Copper Volume

Is it correct to say that:

When using a solid conductor the active copper is equal to:

[(pi) * (d/2)^2] - [(pi) * ((d/2)-g)^2)] * lenght

d=diameter
g=skin depth=10/sqrt(F)
F=frequency

And then use an equal volume of copper primary?

[madhatter]

running the eq you'll notice that the numbers will still be negative unless you use the active copper dia as the wire dia, however this poses the issue of wire gauge, as this gets into very fine gauge.

[madhatter]

This is real PITA! the edit function is a not working!

The above equation should read: H-(d x N)/N-1

[madhatter]

a note on conductor spacing, since the height is a fixed dimension per the diameter in both secondary and extra coils the spacing eq. should look something like this:

H-(d-N)/N-1

where:
H = hieght of coil
d = Diameter of wire
N = number of turns

This will give the tangent spacing between wire per turn.

I was also thinking, and this is beyond what Eric has stipulated. That the 40% size of the extra coil to the secondary might be adjusted to 37% based on the 1/e ratio. Meaning that if the secondary coil is treated as a cross section of a conductor and the skin effect is 63%, then 37% might be enough to keep the extra from being mutually induced. it also plays into the proximity effect as well.

I've been trying to figure where Eric came up with the Pi^2/4 constant for conductor length. why 1/4 of the squared ratio as a multiplier?

[garrettm4]

Tesla Transformer Windings

7imix,

I would have to disagree somewhat with what you just wrote. In the secondary I believe you increase the diameter of the windings and decrease the number of windingss to proportionate the magnetic field to dielectric for a subsequent balanced ELECTRIC FIELD as per Mr. Dollard's "Transmissions" have pointed out (less turns less magnetic energy, larger surface-area between turns more dielectric energy). I may be wrong but I believe that the two voltages e & E are designed to nullify one another in the secondary BUT the currents i & I DON'T. Thus creating a MONO-POLAR or longitudinal current for ONE WIRE transmission through the earth (with an appropriate receiver of course). The extra coil, which isn't always used, on the other hand is made to do the exact opposite, or have the least self capacity and mutual inductance while having the most self inductance and possibly mutual-capacity as well. Here the currents i & I nullify leaving only a mono-polar voltage. The terminal capacity, and its delay line, may be used to control the voltage gradient emitted by the extra coil, which is clearly seen to be a problem in the Colorado Springs transmitters. The exact relation of the secondary and extra coil is a bit cloudy for me right now. Exactly how these all work together, I'm unsure at the moment.

Garrett M