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COP 17 Heater | Rosemary Ainslie

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  • Hi folks, Henieck I want to thank you for such honesty, I fully understand what you mean about human comfort zones, as I see it very clearly to varying degrees in people i know, as well as myself im sure to some degree. You know you should read Peter L. attraction motor thread if you have not already because its almost the same idea and could be a way to help clear that academic conditioning a little more.
    peace love light

    Comment


    • Originally posted by witsend View Post
      We need to use our own logic to increase our own understanding of the subject.
      - you say a lot about logic in your essay. There is only ONE LOGIC. If you change it - it ceases to be the logic, no matter how you call it. Just stop rewriting the reality in your head and start to apply some legitimate, proven logic, based on sensory perception to your circuit’s performance. Sure, that every expert will confirm, that this is the way to calculate power – but it is pulled out of full context. You have invented the circuit that unnecessarily make additional portion of energy circulate. It is just like you had two bank accounts (charging and discharging battery) and was swapping or circulating the same money (energy) over and over again (using small portion of it besides). At the end of the day you may have very high and impressive volume of transactions – but it doesn’t mean that you have become a millionaire! Every expert will confirm, that they have used certified computers and highest bookkeeping standards, and that the volume of few millions of dollars was no doubt undeniably REAL. But my battery is f. empty! I cannot pull out all those millions at the same time which I can clearly see on my "certified" print-outs. I simply debunk that you are a millionaire. It is just an illusion based on faulty logic (which, logically - is not logic). Don’t change your logic at this critical moment, because it is literally all you have to get out from this trap. Not only you will be equally pore (no millionaire) but in addition to that problem you will become insane as well. Are you going to end up in psychiatric facility among other insane people and the only difference will be not the process you are going through – but its content – many believe that they are the Jesuses (very many of them , others - that they have discovered zipons…

      Comment


      • Originally posted by witsend View Post
        Apologies for so many consecutive posts but I would very much like to share something that I saw on one of the Discovery programmes aimed at learning more about the human 'mind'. The example was a little girl who was able to get a sweet out of a black box by series of complicated manouvres shown to her by the experimenter. So was a chimpanzee. Both learned the required series of steps. Then the blind was taken off the box and both could see a short cut to the 'steps' needed to get to the sweets. The chimp dispensed with the ritualised extra steps. The little girl did not. She faithfully performed all the steps albeit that ALL were not required. The conclusion was that something in the wiring of all of us requires an excessive respect for prior learning. Clearly the girl was more intelligent. But, notwithstanding the benefit of this IQ, she did not exploit the obvious.
        Just for the people who are interested, here is the video from Human Ape (with Dutch subtitles).

        YouTube - Human Ape (2007) [3/6]

        Comment


        • henieck, there was a time when it was logical that the earth was flat, that the earth was the centre of the universe, that the illness was the result of individual or collective sin - and on and on. At the turn of the century it was logical that one could not split the atom, that there was only one galaxy the Milky Way and that flight was impossible. Logic is not the point. It is collective assumption that I am addressing. And this changes with time.

          But there is one point that is true. Every new perpspective, be it a view into the atom or a view of our earth in relation to the universe, every introduction of a new idea is criticised as being based on some new level of insanity. If I were not accused of being insane then I would very much doubt that I would thereby also be close to the truth.

          My own logic does not need the assurance of historical fact. Nor am I insane. And I would thank you not to tell me what I may or may not write. I woud not presume to prescribe your own contributions.

          Comment


          • Originally posted by witsend View Post
            henieck - I think the problem of what makes 'current flow' goes to the heart of this problem. But at this stage - all I am asking is this. Does your battery discharge energy during that period of the duty cycle when the switch is closed? In other words the 'spike' - is it a result of more energy coming from the battery?
            - of course not - that is - the battery only delivers the energy during the "on" part of the cycle.

            if it's not coming from the battery where does it come from?
            - exactly like you say - it comes from the coil's collapsing magnetic field.

            So really to answer this we need to go back to basics. According to Inductive Laws - we're taught. Changing electric fields induce magnetic fields. Changing magnetic fields induce electric fields. That's not open to question. We know this. Then the ON cycle from the battery enables current to flow through the circuit. During that flow, which is instantaneously evident throughout the circuit - that same flow establishes a voltage across the load resistor. And, as Donovan pointed out, the rate of flow is determined by the level of voltage measured across the load resistor. The two are directly proportional and measurable in terms of know classical measurement.
            - so far, so good...

            So measure that voltage - square that value and then divide it by the Ohms value of the resistor - v^2/r - to determine the actual wattage delivered by the battery during this ON period. Again. We now have the actual measure of the energy delivered by the battery.
            - I would have objection to this. You entirely omit that initially the electricity (in broad term) must “perceive” the coil as a coil – until the magnetic field establishes and there is no more change of electric parameters in time. “Change in time”… Take a look at this animation again: http://www.falstad.com/circuit/e-induct.html Every coil have some resistance. The fact that yours happened to have a little bit bigger than the other typical ones – doesn’t decide that it is not a coil anymore. You maintain that it is not a coil during “on” time – but it behaves like a coil during “off” time. It is ridiculous. There is magnetic field collapse – but it didn’t appeared out of nothing like you propose. This the place that you have to revise your approach. It happened thanks to this phenomena explained nicely in graphic form in the link above. Study it, because I am telling you - your coil is not free from it! And certainly not form one half of it it is like trying to get rid of one side of coin – you cannot get rid of one side of coil law either…

            During the OFF cycle - when the switch is open - the battery is effectively disconnected from the circuit. It allows no further flow of current from the battery. NO MORE ENERGY. Whatever now happens on the circuit is not the result of more energy from the battery. And in the final analysis we are trying to evaluate the amount of energy that is coming from the battery. So - we all know there's an immediate spike - as you rightly pointed out - followed by some ringing
            until the duty cycle either defaults to zero or moves into the next cycle - depending on the frequency of that duty cycle. So what actually happens to cause that spike?
            My take - which is strictly in terms of Inductive Laws is this. The potential difference from the battery supply source is disconnected. The current flow from the battery is 'stopped' - instantaneously. The voltage across the load collapses. The voltage is simply a measure of the magnetic fields that were first extruded as a result of that current flow. These fields collapse to zero. The measure of that collapse is equal to the applied voltage during the previous ON cycle and also a reasonably exact measure of the energy first applied by the battery. These collapsing fields are simply magnetic fields changing in time. A changing magnetic field induces an electric field. Now the inductor becomes a supplier of energy. In effect the resistor becomes its own energy source.
            - yes, but the establishing of the inductor’s field does not happen for free- like you see it. Search around that some more…

            SO. If your ammeter is showing a doubling of the current then your actual question should be - where does that 'doubled' current come from? It has NOT come from the battery
            - yes and no at the same time. To evaluate this circuit’s performance it will be very helpful if you divide the operation into steps and don’t mix everything at once. First check how it operates when the flyback output is not close-looped. Take a note on energy usage. Than take a big capacitor and connect it the Bedini way – output from the diode to capacitor’s +, and capacitor’s minus connect to + of the battery. You can connect this “your way” as well- but it complicates operation and calculations because capacitor will charge directly from the battery until voltage equalize. Now run the circuit and you will notice immediately, that the circuit does indeed “know” somehow that some form of load has been hooked up to it’s other end and automatically increases the intake to equalize and compensate that additional load. Basic calculation will reveal the truth that both quantities (output gain and increase form the battery) are essentially equal So the output from the coil comes from the battery – but it happens indirectly. If you now connect this flyback to the battery again – it will “somehow sense” that there is a heavy load connected. Engineers will be able to explain it to you in terms of dynamically changing impedance, saturations, timing, phases and who knows what else… After connecting the battery the circuit will increase the input even more – but the output in your circuit is also the input in the next phase – so it makes no sense to fluffily circulate the energy that way. This is what causes many amperes displayed on your nice piece of expensive equipment. Don’t go for additional certificates for it – better go for certificate of your own logic. How both of you couldn’t find it out for so many years?! Or is it that I don’t know of something?

            It has NOT come from the battery - not in terms of classical analysis
            - it came from the battery, where else could it come from – from zipons or something?!

            But how could it have come from the battery? The battery delivers a monodirectional current flow. It cannot recharge from this cycle.
            - there is a delay… Battery gives energy to the coil, transistor switch this cycle off – and few fractions of the second later there is its own energy in the form of higher voltage and lower amperes coming back at it… Swing a hammer hanging on a string in front of you and you will get the message - although I am not sure if in your case it will not come back to you in the form of few zipons

            Find a second battery. Attach the negative rail ONLY to this second battery. Put the diode to the positive terminal of that second battery. And watch the battery recharge. At the same time watch the temperature over the load resistor. That wont change. And the battery will recharge.
            - sure the circuit will recharge the other battery, but it will increase its input accordingly. I haven’t make the test – at this moment it is just my speculation about that, but I did make the capacitor charging, which in principle is the same.

            I keep losing posts.
            - then stop doing that!
            Last edited by henieck; 07-09-2009, 03:21 PM.

            Comment


            • Veggiel - thanks for the link. It's exactly the same as I saw. I got the sweet reward wrong. The girl seems to be happy to be rewarded with a sticker. But the point is interesting. It seems that this is both our strength and our weakness.

              Many thanks in any event. It's always nice to know that what's written is also read.

              Kindest regards
              Rosemary

              Comment


              • Originally posted by witsend View Post
                And I would thank you not to tell me what I may or may not write.
                - I hope it wasn't an indirect attempt of telling me what I may or may not write...
                Last edited by henieck; 07-09-2009, 04:16 PM.

                Comment


                • Originally posted by henieck View Post
                  - I hope it wasn't an indirect attempt of telling me what I may or may not write...

                  Comment


                  • Originally posted by witsend View Post
                    My own logic does not need...
                    - according to my own logic, which may as well be the wrong one - because I can only judge it using my own logic - which can be false, this is the performance of your circuit in wide perspective:


                    It has tried to trick me to believe that it used 56 000J while it really used 34 000J to heat up the resistive element which can be heated directly to the same degree without transistor switching losses using just 18 000J


                    The main point is that thanks to the flyback diode there is a redundant, almost doubled flow of energy permanently present in this circuit. It is always less than double, because the coil is not capable of giving back more than it was delivered to make the magnetic field establish, and always loses some part of energy as heat in the process How much - depends on timing. With the additional, looped current you can interpret it differently. I say “it tried to trick me to believe it used 56000J” - because I measured total amount or current flowing. Depends where you place the meter you may come to the conclusion, that this additional current can be not added like I did but subtracted if you measure the reverse flow to the battery, and in this case you may come to equally false conclusion, that it used not 34+22=56 but 34-22=12. In this case I should have written, that “It has tried to trick me to believe that it used 12 000J while it really used 34 000J...” Doesn’t matter either way.

                    The point is that the flow goes to the battery terminal and returns to the coil – and if you measure “backward” ghost flow (but real!) to the battery it falsely represents itself as charging current. Then at the battery terminal you can think of it, that it turns to the coil again in the loop – and if you measure it in this direction like I did – it shows that almost double current is present. The point is that this ghost current doesn’t do any work, just circulates here, introduces confusion and shouldn’t be taken into account in power distribution, either way. It is like having the same constant multiplier on both sides of an equation – you can just forget about it as well, it doesn’t matter to the equation at all, and the whole story behind the equation will become clearer.

                    So to have the external, objective reference point I have made the discharge curve of my small battery. During the course or 10h I discharged it to 10,6V and calculated all the Joules along the way. This way, by referring to it the actual battery voltage (under the same load) I know how much energy the battery has already spent to this point. By this reference I know, that despite strange current present, in which I don’t know how much is really dissipated and how much of it is just going round and round – I can obtain how much from the battery was really extracted, even if there was any charging present. The battery makes all the real time measurements – it is just the matter to get them translated to real energy reading- that is why I made this controlled discharge first. After 180min of the circuit’s work, the battery’s voltage was 11,73V – what by reference to the freshly obtained battery’s characteristics curve means that there was ca 34000J missing from the battery’s full capacity. I have the exact measurements, this is just rounded… This is generally exactly the same value compared to the run without the diode connected at all. In this case after 180 min run the voltage was 11,71V and the Joules obtained form 15min intervals measurements and further interpolated were also very close. 37450 Joules corresponds to 11,71V in the reference curve – and value calculated during the course of the experiment shows, that it was used 38200J (as I mentioned I had slightly better voltage after every next battery charging, so it may account for this small difference). Meantime, measurements of flyback run shows that in this time frame 56800J were traveling from the battery terminal to the transistor. It is as simple and as idiotic as that… If you place the meter differently and just look in this one place loosing the big picture from the sight entirely - you will be enabled to subtract and have in your thoughts free energy for a while. Rosemary has had for many years, for example…

                    Finally, I have also had the temperature curve from both runs at my disposal. For the flyback operation it showed maximal temperature (reached after 90min) 33,4deg C, but for the next two hours it stabilized between 32,7 and 33,1 degC. So I have connected variable power supply and figured out after few hours of adjusting and stabilizing the temp output, that I only need 1,68W of ordinary DC power to obtain the same temperature at the same level. This gives us that at the same point of time there would be just 18150J needed to obtain the same curve. I am aware, that output from the battery is lowering with time and the power supply is not – but we could estimate this and perhaps change the final number to 18500 or 19000 to have perfect common denominator characteristics– which doesn’t change much…
                    Last edited by henieck; 07-09-2009, 06:44 PM.

                    Comment


                    • henieck - let's sum up where we agree. The battery only delivers energy during the ON period of the duty cycle. The energy from the spike is produced from collapsing fields in terms of Inductive Laws. And as you say,
                      - so far, so good...

                      I now recommend a v^2/r analysis to determine its energy and you object. You say that the battery knew it was delivering to a coil - and it somehow added extra energy. So. My question is where do you measure this energy? So let's change the parameters of the test. We now have a circuit that has no switch. The inductive load resistor is simply placed in series with the supply source. I'm sure you'd agree that we can now apply the v^2/r analysis to establish the wattage. You'll find that this is pretty well consistent with vi being the voltage from the supply source divided by the Ohms value of the resistor. No extra energy. But if you check you will find that there is an extruded magnetic field across that resistor with a measurable and identifiable justification or polarisation. That field is there. It is not changing the amount of current flow from the battery. It is simply an inevitable result of an electromagnetic interaction. Where there's a measurable electric field there is a corresponding and measurable magnetic field. And I think you'll agree that there is no EXTRA energy to apply that magnetic field.

                      So why, when the current flow is interrupted is there an assumed ability of the system to discover the existence, not of a coil, in this case on the resistor itself, but of a switch? Somehow the system knows that you are going to throw the switch and turn off the energy so it better take up more current. And if it knew this, where did it put that extra current? The voltage over the resistor on both and On and Off period of the cycle is always consistent with Ohm's Law. What I'm really asking is why do you propose that there has been an applied magnetic field at any cost greater than is determined by the measured voltages?

                      It is a coil during the on and off period. We are simply allowing the benefit of that coil to enable a second cycle generation of electric energy in terms of known inductive laws.

                      If this is 'ridiculous' as you propose, then you must surely, at its least, show me where the extra energy came to allow for that magnetic field? At all stages the voltage measurement is consistent with Ohm's Law. And this is the measured voltage. If we were using a second coil to add even more inductance - then indeed it can be argued that there has been more energy applied by the source. But we cannot claim this when we are using a standard resistor that is measuring heat dissipation in line with the known laws of physics. That 'extra' energy is only required to refute the possibility of an over unity gain. But by using a resistor to generate it's own inductance refutes any evidence or need for that 'extra' energy.

                      Don’t go for additional certificates for it – better go for certificate of your own logic. How both of you couldn’t find it out for so many years?! Or is it that I don’t know of something?

                      I have to defy not only my logic but the evidence of my senses to assume that extra energy has been delivered by the battery. The measurements do not show it. So you tell me. Is there any earthly possibility that you don't know of something? If you claim 'extra energy delivered' during the ON period and from the battery, then should you not also be able to measure that extra energy? Do you think, just maybe, that you've been persuaded to believe that there's extra energy delivered - because without it you would defeat the second law of thermodynamics? Do you think, just possibly, that our esteemed academia may have required this 'extra' storage as they did not want to redefine unity as it relates to the electromagnetic interaction?

                      Find a second battery. Attach the negative rail ONLY to this second battery. Put the diode to the positive terminal of that second battery. And watch the battery recharge. At the same time watch the temperature over the load resistor. That wont change. And the battery will recharge.me

                      sure the circuit will recharge the other battery, but it will increase its input accordingly. I haven’t make the test – at this moment it is just my speculation about that...
                      henieck - if there's one thing I know about you is that you are both intellectually honest and intellectually courageous. Else I would not still be trying to answer your posts. And I really also appreciate how these points anger you. May I ask you to do that test. Just look at the recharge cycle. Then speculate on that recharge cycle going back to the supply source battery. Then look at the temperature on the load which will not change. Then tell me. Where is there evidence of extra energy coming from that battery to charge the coil on the resistor so that it can 'deal with' the off period in some extraordinary and predictive manner that could only be achieved by some intellectual property in the system itself - which I simply cannot believe. Not under any circumstances.

                      Comment


                      • Henieck, I've just seen your post. Please advise how did you compute those Joules?

                        Comment


                        • Mark - I've been giggling at your little emoticons, is that the term? It's just so funny. And so eloquent.
                          Last edited by witsend; 07-09-2009, 05:00 PM. Reason: spelling? still not sure that's it's right

                          Comment


                          • Its a way to throw in my 2 cents without adding to much gas to the fire!

                            You know what they say, a picture is worth a thousand words.

                            Comment


                            • input energy

                              Originally posted by henieck View Post
                              - that is right, but it doesn't mean that to make manifest this surge didn't cost anything energetically. It takes WORK to produce this phenomenon...
                              Of course it does but like any open system, you pay a small investment for a high return.

                              Any investment that gives interest violates thermodynamics. It is an open system that allows for environmental input to be added to our personal input so the output will be more than what we paid for. Over 1.0 COP.

                              As a note, just because something is an open dissipative system, that doesn't require over 1.0 cop, it just means there is an opportunity to have over 1.0 cop since there is a path for other input to be added free from the universe.

                              If you put in x amount and recover 90% for example, then you only need to keep putting in 10% to keep it going. You just have to make up for the losses while reaping the benefits of the full input that includes what the universe is giving back to us.

                              Like a merry go round. You put in x amount of energy and once it is up to speed, you put in less than x to keep it going and while you keep putting in less than x, over time, the COP keeps going up. A short duty cycle is slapping a 300 pound merry go round with your pinky once per rotation.

                              Anyway, I don't mind having to invest something up front to have more given back to me. Everyone's refrigerator is already doing this at COP 2.5~4.0 or so. 2.5~4 times more work in joules is being done than joules of "electricity" that left the wall.
                              Sincerely,
                              Aaron Murakami

                              Books & Videos https://emediapress.com
                              Conference http://energyscienceconference.com
                              RPX & MWO http://vril.io

                              Comment


                              • Originally posted by Aaron View Post
                                Like a merry go round. You put in x amount of energy and once it is up to speed, you put in less than x to keep it going and while you keep putting in less than x, over time, the COP keeps going up.
                                - sounds nice. I am searching for such a relatively easily replicable system. Can you advise something of that sort, or anything that has already showed proven, unusually high COP or over unity?

                                Everyone's refrigerator is already doing this at COP 2.5~4.0 or so. 2.5~4 times more work in joules is being done than joules of "electricity" that left the wall.
                                - that is precisely right. The question is if we can tap into the "zipon" field the same way as we do to transfer heat.


                                Rosemary, My answer is in post 385.

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