Quote:
Originally Posted by MileHigh
No energy discharged from the coil goes back to the souce battery at all. In Rosemary's case, all of the current + voltage discharge from the coil goes through the resistive part of the coil and the diode.
Is this what is "supposed" to happen or did you actually verify this with this circuit?
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When the MOSFET is off, and is an open-circuit, there is no closed circuit loop that would allow current to flow into the battery. If the current could flow, it would have to go from the discharging inductor then into the positive terminal of the battery, out the negative terminal, through the shunt resostor, through the MOSFET and then back into the inductor. Oops! The MOSFET is open-circuit. There is only one place the current can flow, and that's through the diode.
Originally Posted by MileHigh
No energy discharged from the coil goes back to the souce battery at all. In Rosemary's case, all of the current + voltage discharge from the coil goes through the resistive part of the coil and the diode.
Is this what is "supposed" to happen or did you actually verify this with this circuit?
>>>
When the MOSFET is off, and is an open-circuit, there is no closed circuit loop that would allow current to flow into the battery. If the current could flow, it would have to go from the discharging inductor then into the positive terminal of the battery, out the negative terminal, through the shunt resostor, through the MOSFET and then back into the inductor. Oops! The MOSFET is open-circuit. There is only one place the current can flow, and that's through the diode.
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