TinselKoala - I'm delighted to read that you positioned your probes exactly as we did in our experiment as per the paper submitted to the IET. In which case the waveform of the shunt voltage will be inverted as it relates to the waveform of the resistor voltage. You are NOT working with a 90% duty cycle. Rather, it may be that you are confused by an inverted waveform which is simply a function of the scope.
I took the trouble to speak to an expert who went to the added trouble of looking at your video. His comments are not really repeatable in any respectable context but he did propose that you are mistaken in your representations as they relate to the waveform shown. The puzzle is that anyone who knows how to use a common negative rail - required when using the dual function - does not also know what he's looking at. In other words he's asking why you are deliberately perpetrating this claim when you also appear to know what you are doing? I studied the scope waveform myself. You'll see that the load resistor stays at 0.5% or thereby. The inversion on the shunt waveform is only as it relates to zero. If it did not invert then there would have been some serious damage to your scope.
I hope this puts paid to your endless insistance that the circuit diagram is wrong. There may be some trouble with your switching circuit. But if there is - it is not altering the duty cycle as you claim.
I took the trouble to speak to an expert who went to the added trouble of looking at your video. His comments are not really repeatable in any respectable context but he did propose that you are mistaken in your representations as they relate to the waveform shown. The puzzle is that anyone who knows how to use a common negative rail - required when using the dual function - does not also know what he's looking at. In other words he's asking why you are deliberately perpetrating this claim when you also appear to know what you are doing? I studied the scope waveform myself. You'll see that the load resistor stays at 0.5% or thereby. The inversion on the shunt waveform is only as it relates to zero. If it did not invert then there would have been some serious damage to your scope.
I hope this puts paid to your endless insistance that the circuit diagram is wrong. There may be some trouble with your switching circuit. But if there is - it is not altering the duty cycle as you claim.
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