Originally posted by Aaron
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Originally posted by Aaron
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Why? Because, in this way of look we describe a charged cap as a two near conductive material plates one containing "-" charge (excess of electrons) and other "+" charge (excess of positive metal nucleus or absence of electrons). The energy we have given to it wants to get system to more stable state - discharged, that means - get electrons from one side out, where they are more than needed, and other - where they are needed - in. But in same time. If you connect circuit to just one side (+) and want to give charge or take from there, cap has no place to send electrons or from where to take electrons at other side.
What this means?
1) cap itself won't make any asymmetry in himself, because it would be less stable than symmetric charge, so no charge "taking" from circuit at "+" side.
2) if we force circuit to produce "-" charge to "+" side of cap, we might charge it asymmetrically, yet we must construct a circuit that will give this asymmetric charge - like caps, all kind of closed circuits wants to be symmetrically used - for given electron, get one back. Of course, that is not problem, if we take this excess electron from earth, yet, that could not be so simple, in this I'm not so sure, somebody correct me, If I'm wrong.
But before I said - maybe just little bit. Well, this little bit is just microscopic effects - I suppose cap could get little charge from or give to wire going out of it, even if it is not connected to earth. But these effect should be minor. The capacitance and voltage just would give us info about what kind of circuit we want to use and how much we could try to charge our cap.
That is the way as I could describe the given situation with my present pre-university knowledge.
Would be very happy to hear non-conventional theory view at this situation too.
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