Hi Gyula,
Thanks for the reply. Given your example then, if 1J is 1 watt of power discharged for a period of 1 second based on a cumulative circuit impedance of 1ohm, and with the only change to the circuit being the cumulative impedance being reduced to .1ohm and now we have 10 times the watts for the same 1 second of ON time, is that correct?
Now if we change the cumulative impedance to be .00023 ohms (or for ease of math, lets just say .001 ohms) and everything else stays the same, we now have 1000watts output for that 1 second of ON time?
I know we don't use such a slow duty to allow for 1 second of ON time and 1 second of OFF time, but this facilitates an explanation of discharging of caps into a cumulative circuit impedance. (tho some of JB's circuits run at about 3hz or so)
Is there a concept of Current "Density" with capacitive discharge? In some cap discharge circuits one notes a small capacity of 3-10uF and this capacity charges rapidly to a couple hundred volts and is then discharged into a 12volt battery. This happens pretty rapidly in terms of frequency because a small cap climbs to higher voltages faster than a large cap. So the benefit to using a small cap is to get high volt pulses at a relatively high rate of repetition. However this small caps discharges have a "lack of current density" as I've termed it. There is not sufficient Current in phase with the voltage discharge to do work.
Then I can switch that 10uF cap out for a 2400uF cap and this one takes longer to charge up, but the discharge pulses have a much more significant current "density" in their capacity to do work. The larger cap reaches the same max charge voltage but is offset in the extended time it takes to reach that peak voltage. More often this cap is regulated to only charge as JB has noted to double the voltage which keeps the frequency of discharge higher than if the larger cap was allowed to fill to the peak possible voltage.
In summation it seems to really charge batteries well one needs to use larger 10,000uF or so sized caps as this is what is doing the direct conversion to the current "density". The frequency drops but the power per discharge is increased significantly given the cophased volts/current per discharge from the large 10,000uF cap versus the small 10uF cap.
Is this observation inline with others on here?
Thanks again for the reply.
Gene
Thanks for the reply. Given your example then, if 1J is 1 watt of power discharged for a period of 1 second based on a cumulative circuit impedance of 1ohm, and with the only change to the circuit being the cumulative impedance being reduced to .1ohm and now we have 10 times the watts for the same 1 second of ON time, is that correct?
Now if we change the cumulative impedance to be .00023 ohms (or for ease of math, lets just say .001 ohms) and everything else stays the same, we now have 1000watts output for that 1 second of ON time?
I know we don't use such a slow duty to allow for 1 second of ON time and 1 second of OFF time, but this facilitates an explanation of discharging of caps into a cumulative circuit impedance. (tho some of JB's circuits run at about 3hz or so)
Is there a concept of Current "Density" with capacitive discharge? In some cap discharge circuits one notes a small capacity of 3-10uF and this capacity charges rapidly to a couple hundred volts and is then discharged into a 12volt battery. This happens pretty rapidly in terms of frequency because a small cap climbs to higher voltages faster than a large cap. So the benefit to using a small cap is to get high volt pulses at a relatively high rate of repetition. However this small caps discharges have a "lack of current density" as I've termed it. There is not sufficient Current in phase with the voltage discharge to do work.
Then I can switch that 10uF cap out for a 2400uF cap and this one takes longer to charge up, but the discharge pulses have a much more significant current "density" in their capacity to do work. The larger cap reaches the same max charge voltage but is offset in the extended time it takes to reach that peak voltage. More often this cap is regulated to only charge as JB has noted to double the voltage which keeps the frequency of discharge higher than if the larger cap was allowed to fill to the peak possible voltage.
In summation it seems to really charge batteries well one needs to use larger 10,000uF or so sized caps as this is what is doing the direct conversion to the current "density". The frequency drops but the power per discharge is increased significantly given the cophased volts/current per discharge from the large 10,000uF cap versus the small 10uF cap.
Is this observation inline with others on here?
Thanks again for the reply.
Gene
Originally posted by gyula
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