Bedini motor question

[LostInSpace]

I see a lot off circuits on the all off them use Transistor to drive the motor

Is it possible to use nFET transistor ?????

and use Shottkey diode ?????

thy have LOW DSon
thy can go very high freq


I will to make my first Bedini motor from a computer fan 12v 2.3a (from a big server)

[faramog]

I see a lot off circuits on the all off them use Transistor to drive the motor

Is it possible to use nFET transistor ?????

and use Shottkey diode ?????

thy have LOW DSon
thy can go very high freq


I will to make my first Bedini motor from a computer fan 12v 2.3a (from a big server)

I dont see why not. The transistor is primarily a switch and the faster it switches the sharper the radiant pulse (at least thats whay Bedini says). Watch the gain though if you are just using a trigger coil or you may end up in a very linear region and fets are not massively keen on that unless they are expensive power fets.

I have plans to try this but it will be later in the year when I get to v3 bedini (bigger and more chocolaty !!)

[LostInSpace]

I dont see why not. The transistor is primarily a switch and the faster it switches the sharper the radiant pulse (at least thats whay Bedini says). Watch the gain though if you are just using a trigger coil or you may end up in a very linear region and fets are not massively keen on that unless they are expensive power fets.

I have plans to try this but it will be later in the year when I get to v3 bedini (bigger and more chocolaty !!)

I think off a High power nFET 15A DS under 1ohm DSon

[faramog]

I think off a High power nFET 15A DS under 1ohm DSon

Got no idea what you are saying ?

[citfta]

Hi faramog,

what he is saying is that a high power n channel FET has a drain to source resistance of less than one ohm when it is carrying a current of 15 amps. My personal favorite is to use an n channel mosfet and a mosfet driver chip. This combo gives really fast on and off times and can carry some large currents.

Carroll

[LostInSpace]

Hi faramog,

what he is saying is that a high power n channel FET has a drain to source resistance of less than one ohm when it is carrying a current of 15 amps. My personal favorite is to use an n channel mosfet and a mosfet driver chip. This combo gives really fast on and off times and can carry some large currents.

Carroll

In most Bedini motor normaly a power NPN(3055) transistor

What i want is to change that to Power N channel mosfet is that possible

[citfta]

Hi Lost,

I don't know of anyone that has tried that with just the plain SSG. I don't think Bedini recommends that for the same reason faramog stated. It is hard to get a FET to switch all the way on and off without a driver circuit. If you want to keep things simple just change the 2N3055 to a MJL21194. This will make a noticeable improvement in the running and charging of the SSG. If you don't mind getting complicated then you could use an external trigger such as a hall-effect transistor and a driver chip and probably get good results with a n-channel FET. Good luck.

Carroll

[tony_mig]

questions

i apologize for the first grade questions, but i was reading the bedini patent 6,392,370 and i have some questions about it.

1. does the permanent magnet induce a current in the primary winding before the circuit is turned on?
2. if so (or if not) how does a current through that winding reverse the polarity of the stator pieces? wouldn't they remain the same because they are still in contact with a permanent magnet?
3. why run the current through transistors before the coil? is it so that when the polarity reverses, the back emf will flow to the diode bridge? why not run it directly into the coil?
4. is the hall effect pickup reversing the polarity or is the current through the coil doing it?

5. is there a way to take a 12V car battery (or a series of them) and with the diode bridge, capacitors and transformers invert the DC to 480V/60Hz/3phase AC? i would think that a back emf would be ideal for reversing the polarity like AC.



thank you for any and all assistance.

[faramog]

i apologize for the first grade questions, but i was reading the bedini patent 6,392,370 and i have some questions about it.

1. does the permanent magnet induce a current in the primary winding before the circuit is turned on?
2. if so (or if not) how does a current through that winding reverse the polarity of the stator pieces? wouldn't they remain the same because they are still in contact with a permanent magnet?
3. why run the current through transistors before the coil? is it so that when the polarity reverses, the back emf will flow to the diode bridge? why not run it directly into the coil?
4. is the hall effect pickup reversing the polarity or is the current through the coil doing it?

5. is there a way to take a 12V car battery (or a series of them) and with the diode bridge, capacitors and transformers invert the DC to 480V/60Hz/3phase AC? i would think that a back emf would be ideal for reversing the polarity like AC.



thank you for any and all assistance.

1. Yes ... but its sort of a grey area. The induced voltage lifts the thresholds and allows the transistor turn on.

2 & 3... you need to re-read: its about the radiant spike (in the negative direction). Its not about current flow in the traditional positive direction - thats a consequence. Bedini says (and it seems demonstrated) that the radiant spike is when the good stuck in the battery happens.

--- I do sort of wonder if you could separate the two, so you get the benefit of the current out of the circuit and the benefit of the radiant spike into the battery.

4. depends how you use the signal of the hall effect device and where you place it. All the Hall effect device is, is a sensor for detecting a passing magnetic field.

5. Electrically, sure, efficiently, not really (80-85% max).. and why ?

[tony_mig]

faramog, thank you for your reply.

however, i still don't understand how running a current through the bar reverses the polarity of the magnet. as i understand how the magnet motor works, the magnet polarity at the stator is opposite the rotor magnets, and therefore attracts the rotor to the stator, then a current from the circuit through the coil reverses the polarity of the stator and pushes the rotor magnets away, and then the current shuts off, attracting the next rotor magnet, etc., and also when it shuts off, it induces a back emf which goes back to the diode bridge to continually power the circuit.

is this correct? either way, i don't understand how a coil current can reverse polarity. is this something well known in EE (i'm a ChE with some (but not that extensive EE work)) or is it something bedini discovered?

i also don't understand why he uses a secondary coil to charge another battery. why doesn't he put the secondary coil into the diode bridge? it would seem he wouldn't have to use a transistor at all in the primary, if so.

unless he is just trying to maximize use of, what otherwise would be, wasted flux.

5. i need to power a pump 480/60/3 AC at a remote location, where power lines can't be run and it's not cost-effective to have someone continually charging the batteries, so i thought some sort of bedini circuit, (meaning a capacitor, diode bridge and transformer to recycle otherwise wasted flux) could be used to power the battery uninterrupted for long periods of time.

i haven't found a 250GPM pump that runs on DC, so i thought converting it to AC wouldn't be a problem, and in fact, because a DC-to-AC inverter uses a transformer, that "wasted" flux could be put back to the battery, as bedini does.

thanks.

[tony_mig]

i'm also confused by the drawings. i thought that for battery or generator power into a circuit, the proper designation is from negative to positive, while for the circuit itself, current flow is from positive to negative.

in fig1 of the patent, the battery suggests current is through one diode of the bridge then into the coil. however, in fig2, if the negative lead on the battery is where the emf "starts", then it travels through the diode(24a), then into the coil (22a and 22b), and simultaneously through 34 then 32, which is opposite the way bedini describes it.

if current travels from the positive of the battery, through 11, 31a, etc, as bedini describes it in the patent, it agrees with the current flow in fig1, but does not travel through the diode first. it goes through 30a then into 22a, which makes sense, but i'm not sure why he put 30a there in the first place.

and i'm not sure why 30b and 30c are necessary either.

[faramog]

faramog, thank you for your reply.

however, i still don't understand how running a current through the bar reverses the polarity of the magnet. as i understand how the magnet motor works, the magnet polarity at the stator is opposite the rotor magnets, and therefore attracts the rotor to the stator, then a current from the circuit through the coil reverses the polarity of the stator and pushes the rotor magnets away, and then the current shuts off, attracting the next rotor magnet, etc., and also when it shuts off, it induces a back emf which goes back to the diode bridge to continually power the circuit.

is this correct? either way, i don't understand how a coil current can reverse polarity. is this something well known in EE (i'm a ChE with some (but not that extensive EE work)) or is it something bedini discovered?

i also don't understand why he uses a secondary coil to charge another battery. why doesn't he put the secondary coil into the diode bridge? it would seem he wouldn't have to use a transistor at all in the primary, if so.

unless he is just trying to maximize use of, what otherwise would be, wasted flux.

5. i need to power a pump 480/60/3 AC at a remote location, where power lines can't be run and it's not cost-effective to have someone continually charging the batteries, so i thought some sort of bedini circuit, (meaning a capacitor, diode bridge and transformer to recycle otherwise wasted flux) could be used to power the battery uninterrupted for long periods of time.

i haven't found a 250GPM pump that runs on DC, so i thought converting it to AC wouldn't be a problem, and in fact, because a DC-to-AC inverter uses a transformer, that "wasted" flux could be put back to the battery, as bedini does.

thanks.

mmmhhh .. Not quite sure what all the stuff about polarity is about. The trigger part - coil across the base of the transister is to induce a voltage to switch it on - its nothing more than a simple position sensor (crude) so as the magnet moves across the coil a voltage is induced leading to a current dependent on the circuit resistance.

The reason you cant do this with a diode bridge is that you need the amplification effect to creat a large and sharp turn'on to induce the radiant spike by the interaction of the cosmos, magnetic field and coil (or something I like to think like that).

The secondary coil can be fed to battery or through a bridge rectifier to use.

Understand though - there is no COP>1 here. The 'effect' cop>1 is only via the radiant interaction with the battery so the effecive energy in terms of measurable current into the trigger and transistor is less than that got out of a condidtioned battery.

It certainly has effect, but a practical home system .... err no.

All the posts I came across when building a proto made it clear the SSG (et al) were about looking at the radiant spike and understaning there was something there.

You need to not think just in terms of current ... I find that a little tricky given my electronics background, but have been open minded so far: not fully sure there is anything real here, but its fun getting a scope and soldering iron out again :-)

[tony_mig]

i do actually understand it in terms better than just current. i say current a lot so i can mentally follow what is turning on in what order. i was just reading lenz's law, about how a magnetic rotor "stores" potential and that's what's creating the back emf to reverse the polarity of the stator magnets. i finally just got that.

i do love how bedini describes powering a circuit, saying that electrons are not literally traveling from the battery through the circuit and into ground, you are merely creating a source dipole and inducing current flow through the radiant source. and the radiant source will continue to power the circuit until the dipole extinguishes itself (for an acid battery, for instance). it is an awesome way to look at a circuit.

walter russell even went further and said there is no such thing as electron flow or current at all. all is pressure, or emf. and putting an emf on a circuit pushes the outer electrons of the circuit components into a higher resonance and that higher resonance energy is powering the circuit. that everything is essentially a standing wave. another awesome way to look at "current flow" but i still like to follow the current around just to get my head around it.

and i forgot that it is a change in field (like the amplification effect of a transistor) that actually creates a back emf.

i did speak to an EE firm that said there are pretty standard boost converters out there for taking 12V DC to 460/60/3 AC, so i think i'll be able to find one to power my skid.

i want to put either the primary or secondary coil (or maybe both) of the inverter back into the battery via a capacitor and diode bridge to keep it running indefinitely.