Thanks H2OPower for your clarity. I will look into it. The WFC is easily built, the gas processor needs more attention as you say. The steam resonator is it really included in the Meyer buggy engine? If so, is it the final step before ignition?
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charged water and electrons
Originally posted by h20power View PostThe injectors sent in a charged water mist
The EEC's job is to consume the positive electrons so the negative electrons have nothing to combine
Also, what is your definition of a positive electron and negative electron?
There are 3 flows on a circuit. Positive voltage potential, negative voltage potential and electrons that are of negative potential.Sincerely,
Aaron Murakami
Books & Videos https://emediapress.com
Conference http://energyscienceconference.com
RPX & MWO http://vril.io
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This is getting interesting, about the EEC I always thought he did that trick rotating the HHO gas(which is magnetic) inducing a rotating magnetic field causing the electrons to flow away(or whatever happens when HHO is rotated near a conductor, I bet very few people know for sure) in a conductor, at the moment I do not find that drawing in one of his patents, it looks like a solenoid coil.
Anyway a unipulsed magnetic field could do the work too, remember south pole ionizes one way and north pole the other way. And then of course he can use his laser/LEDs. Finally it seems his steam resonator comes in handy too before ignition.
So we have 3 main steps(as fas as I see it very quickly, I am surely wrong about some details):
1) Make HHO with WFC - easy and clear
2) Ionize HHO and air(O2) ambient by magnetic pulses/laser/LEDs etc. Not very clear to me.
3) Spray water mist into the mix and use the steam resonator to separate everything before ignition. Ignite for suction(implosion) power. Pretty clear.
?? Feel free to summarize better and more exact. Thanks.
Stan Meyer worked hard and he was a practical genius, that is clear to me, most of his theory we should forget though.
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Turns out I was completely wrong, I found that drawing and the solenoid coil turned out to be a solenoid spring....
However the idea about rotating HHO to get the electrons away might not be the worst I have had, a rotating magnetic field is somehow familiar territory here I believe....
Please help us uninformed with the short and simple story of the ionizer part of Meyerīs patents. Thanks.
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Originally posted by Aaron View PostWhat is this charged water mist? Water is charged when it is in a WFC and is separated and actually allowed to recombine back into water...then it is charged and it is supposedly acts different than regular water that hasn't been through that process.
Also, what is your definition of a positive electron and negative electron?
There are 3 flows on a circuit. Positive voltage potential, negative voltage potential and electrons that are of negative potential.
For that Aaron we go to the Taylor Cone and how it relates to Meyer's injectors. In a Taylor cone the tip of the needle is subjeted to a high voltage field. The fuild,(in our case water) picks up this positive charge, and when it is injected into the combustion chamber the engine itself is the collector and the water mist starts to break up into a plume of ever decreasing water droplets aiding in combustion with the freshly primed air gases.
Qute from the reading you gave us to read:
In order to explain this phenomenon, we must return to the ionization process itself: By external action ( for example, by X-rays) one electron is separated from a gas molecule (or atom), and thereby it becomes a positively charged ion. Under the normal conditions, which held in Fig. 508, the separated electron will attach itself soon to a gas molecule, because free electrons can hardly exist in a dense gas. The molecule with the excess electrons form then a negative ion and remain so until it reaches the electrode or recombines with a positive ion, whereby both molecules return to the normal state.
Now to tie all of this in with the EEC from the reading you gave us to read:
Recombination and velocity of ions
If you also earth in the ionization chamber of Fig. 507 the plate P, the number of ions in the chamber K increases, since the field which extracted them from the air space is absent. Does the ionization process last until all gas molecules have been split into ions or are there other processes to stop this? To start with, one expects that individual ions approach by themselves by diffusion the plates P, P' and the housing and thereby lose their charge. In fact, this is what happens, however, in general, the number of ions destroyed in this manner is very small compared with the direct reunion (recombination) of the ions in the gas space as a result of the forces of attraction, which are present between oppositely charged ions. This recombination apparently takes place the faster, the larger is the number of positive and negative ions in the space. Hence, if you focus your attention on a definite negative ion, the probability that it will disappear by recombination with a positive ion is proportional to the number N+ of the present ions; the same applies to the positive ions. The frequency of recombinations in a gas is therefore kN+N- or kN�, since, as a rule, equal numbers of positive and negative ions are present. K is a factor which differs with the state of the gas. Hence the number of recombinations increases quadratically with the ion density. A strongly ionized gas de-ionizes on its own very quickly unless an external agent generates continually new ions. You can measure the recombination of ions in a strongly ionized gas: For example, Rutherford discovered that of 106 initially present ions half of them disappear after 0.7 sec and 90% after 6 sec. Also, under the action of a very strong ionization, the number of ions, which accumulate in a gas space (free of an electric field), remains very small compared with the number of present gas molecules.
and this too:
Saturation current
Can a strong electric field remove the freshly formed ions from the gas so fast that no recombination whatsoever occurs? An experiment with the plate condenser (Fig. 507) gives the answer! Ionize the gas with a lastingly applied X-ray tube and increase, starting from zero, the field between P and P' by connecting to P at first one, then two, three, etc. accumulators. For each field value measure by means of G the current flowing through the gas. If you plot the strength of the ionization current against the field strength (Fig. 508), you obtain a curve, which at first rises very steeply almost linearly, then flattens out and levels out parallel to the abscissa. This behaviour is easily understood. In a weak field, the ions wander only slowly, whence they are in the gas space a relatively long time and therefore do not readily encounter opposite charged ions for recombination. As their velocity increases, the probability of a recombination drops. The number of ions, which reach the plate, and therefore also the current strength grow with increasing field strength to a value, at which the ions pass through the gas so fast, that recombination cannot occur in appreciable numbers. A further increase of the voltage cannot now cause an increase in the current, because all forming ions are transmitted to the plates P and P'. The maximum current is called saturation current, the corresponding Voltage saturation Voltage. - The saturation current measures directly the number of ions, generated in unit time, and hence also the strength of the ionizer. If there arise each second N pairs of ions in a gas space and each ion carries the load e, then I = eN, for the current is nothing else but the charge which flows each second through the conductor's cross-section.
What I get out of this is if you consume the positive electrons the negetive electrons have no positives in which to recombine with and the probability of recombination cannot occur in appercialbe numbers before the primed air gases reach the combustion chamber.
The last thing in the Meyer's set up just prior to combustion is the Gas Processor, for you only have .74 sec to get the primed air gases into the combustion chamber due to they are in an unstable state. Also, I think the Meyer made the steam resonator due too the fact he lived in a place that snowed and could freeze the water. It is sketchy in my mind, but that is what I think I read about the purpose of the steam resonator.
Aaron, now can I ask you to do something. Post the math of the process so I can see if you understand what the Gas Processor is doing? Thanks.
Best Regards,
h2opower.
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Originally posted by Gauss View PostThis is getting interesting, about the EEC I always thought he did that trick rotating the HHO gas(which is magnetic) inducing a rotating magnetic field causing the electrons to flow away(or whatever happens when HHO is rotated near a conductor, I bet very few people know for sure) in a conductor, at the moment I do not find that drawing in one of his patents, it looks like a solenoid coil.
Anyway a unipulsed magnetic field could do the work too, remember south pole ionizes one way and north pole the other way. And then of course he can use his laser/LEDs. Finally it seems his steam resonator comes in handy too before ignition.
So we have 3 main steps(as fas as I see it very quickly, I am surely wrong about some details):
1) Make HHO with WFC - easy and clear
2) Ionize HHO and air(O2) ambient by magnetic pulses/laser/LEDs etc. Not very clear to me.
3) Spray water mist into the mix and use the steam resonator to separate everything before ignition. Ignite for suction(implosion) power. Pretty clear.
?? Feel free to summarize better and more exact. Thanks.
Stan Meyer worked hard and he was a practical genius, that is clear to me, most of his theory we should forget though.
This is how I see it:
1) Make WFCw/gas injectors or water mist injector( a real injector for you have to control the amount of water that goes in and the timing).
2) Make the Gas Processor, for it is present in both Meyer's gas injection and water mist injection setups. The Gas Processor uses high voltage(electron bombardment) and photon bombardment of coherent light from the LEDs to push the income air to a higher energy level, and then a electron extraction circuit to consume the negetive electrons that where just striped so the primed air gases don't reform back to their ground state, and/or form ozone.
3) If you live in an envirenment that can freeze water insulate all water lines and make the steam resonator to keep the water from freezing.
Let me know if that helped,
h2opower.
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math
I'm not a mathematician. When I need to know electrical circuit equations or what the simple answer is, I consult experts that can tell me.Sincerely,
Aaron Murakami
Books & Videos https://emediapress.com
Conference http://energyscienceconference.com
RPX & MWO http://vril.io
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Originally posted by Aaron View PostI'm not a mathematician. When I need to know electrical circuit equations or what the simple answer is, I consult experts that can tell me.
,
h2opower.
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Old Video
There is an older video of Stan discussing this exact effect.
I searched for it lastnight no luck.
He says in the video that the water is not returned,
that it is consumed... Kind of unnerving.
I guess; Make two canal rays one of H and another O,
cause them to intersect at the center of a spark gap???
If you get a torch *like* Irving Langmuirs
http://www.geocities.com/bioelectroc...y/langmuir.htm
We all can use the heat somehow....
A very spooky and interesting topic indeed.
Dave
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Originally posted by h20power View PostLike I said the WFC is NOT IMPORTANT it is the GAS PROCESSER that is the key to this technology.
Some numbers for you to think over:
Gasloine has a energy level of 4864 kJ/mol
H2 + 1/2O2 has an energy level of 285 kJ/mol
Now this is what happens when it passes through the Gas Processor:
1st ionozation level,
H 1312 + 1/2 O 1313.9 = 1968.85 kJ/mol
2nd for oxygen,
H 1312 + 1/2 O 3388.3 = 3006.15 kJ/mol
3rd for oxygen,
H 1312 + 1/2 O 5300.5 = 3962.25 kJ/mol
Now you can see just what the Gas Processor is doing. Note, depending on how far you ionize the Oxygen the energy levels keep going up to end up with this:
H 1312 + 1/2 O 84,078.0 = 43,351 kJ/mol. Now that's energy
If you get to any one of these energy states it will run your engine with ease. So, the key is to make the Gas Processor and make it to ionize the gases that go through too a energy state as far as you can so you can get these energy levels to put in the cumbustion chamber and ignite them. I suggest to make two of them one for the incoming air and the other for the hho from what every source you choose to get the hho from. Now you can see just how Stanley Meyer ran his 1.6L VW engine on just a 7L/min production rate.
Energy independence is now yours for the taking, enjoy,
h2opower.
Now I gave a lot of the math for the reaction already, but it was incomplete.
This math is just simple math of a first year chemistry student, algebra(though not error proof).
Water2 H-H bonds and 1 0=0 bond are broken.
2(436) + 498 = +1370 kJ/mol. That is the energy it takes to break water down.
4 O-H bonds are formed when hydrogen and oxygen are ignited to form water.
4(-485) = -1836 kJ/mol
Summing the two processes: 1368 + (-1836) = -468 kJ/2mol or ~285 kJ/mol.
Now lets look at what happens when you add primed Oxygen gases to the equation.
1368 to break water down
now O(primed to 1st level 1314)-H = 2(-1096) = -2192 (only two bonds where formed due to oxygen is now single just O not O2).
Summing the two processes: H-H 2(436) + 1/2O .5(1313.9) = 1528.95 kJ/mol - 1836 kJ/mol = -307 kJ/mol. So a net 307 kJ/mol for the new reaction with the primed Oxygen gases, and remember gasoline has 4864 kJ/mol.
Note also that this is only Oxygens first energy level, the more electrons are striped the greater the energy yeild, example 2nd energy level for Oxygen is 3388 kJ/mol, this time you do the math.
Now I may have made a few mistakes but the way it works wont be hampered by my errors, so if it needs correction by all means do so.
That should help everyone to understand the importance of the Gas Processor,
h2opower.
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Well it may work and it may be important but what is the end product after ignition. The way I see it we have a lot of positively charged ions that you recombine into something! What is that something??!
Not water according to many people(ie Meyer)....
Please clarify the final chemical reaction if you ie have H+ and O4+ and ignite? Where do the electrons come from?
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Random? thoughts
Maybe Stan gives it away when he uses the words fracturing the hydrogen.
H2 - 2E = two protons.
maybe the proton fractures???? (positrons make the bonds???)
or
a naked proton draws an electron from the Vacuum??? (would return water)
or
maybe some of the O gets ripped apart and the electron debris is used for recombination?
(He deceives us by saying Hydrogen fracturing when its Oxygen fracturing???)
or....
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Or just maybe the spark(cold current) is responsible for inititiating a new kind of logic into the reaction between the protons, ie a neutrinolysis just like Meyl tells about in his book?
If so, picking one electron from the light neutrino might yield much less energy than picking many electrons/positrons, especially the really heavy types(my neutrino etc) of neutrinos with 5 electrons/positrons in their vortex chain.
For sure there must be a connection with cold fusion and a transmutation of elements? Anyone has seen a report of the exhaust pipe analysis from Stanīs buggy?
But this is very important and I am not sure I like a water consuming engine, that is for sure.
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