I'm working on the calculation of right wavelength's for the GP and i'm considering a UV-C light source. The initial idea came after i was looking for a LED at 91.2 nm, but we can forget that. So the next step was 250 nm and came across UV-C bulbs that emits 150 - 270 nm.
I tought it was a good idea to investigate it. Take a look at this document:
http://www.heraeus-noblelight.com/fi.../Lampe_eng.pdf
The reason for me looking into this is that i want to be as close as possible for the first ionization level and we (I) know this:
So let’s see what we can do whit the information we have so far.
First off, we know what the energy requirements are to ionize the oxygen and the hydrogen so let’s look at that first.
• Hydrogen: 1’st level = 1312.0 kj/mol
• Oxygen; 1’st level = 1313.9 kj/mol
2’nd level = 3388.3 kj/mol
3’rd level = 5300.5 kj/mol
4’th level = 7469.2 kj/mol
What is the first we can see? We can see that first ionization level of hydrogen and oxygen is fairly close whit a difference of 1.9 kj/mol, but that is a number we can live whiteout (according to me), so therefore we can look at a combination to ionize the hydrogen and the oxygen at the same time.
According to Oxygen @ Periodic Table of Chemical Elements - Chemistry Online Education the first ionization level of oxygen is:
• 13.617 eV = 109833 cm-1 = 1313.9 kJ/mol for oxygen and
• 13.598 eV = 109674 cm-1 = 1312.0 kJ/mol for hydrogen
The difference between these two are .019eV and I don’t think that we need to look for that a small difference.
So let’s convert eV to nm so we can find the right light source for this.
For the hydrogen we need a 91.2 nm wavelength and that should work well for the oxygen ionization as well.
So where can we find such a diode/LED?
To use such a light sourch is tuff to find, we are talkning about ultraviolet C (UVC = 100-280 nm) or vacuum ultraviolet (VUV = 10-200 nm) – to develop a a light sourch that deliver these kind of wavelengths whould be expensive, so lets look at an alternative.
This is from a responce i did over at oupower.com:
”To ionize (remove) a hydrogen atom from a water molecule, it takes 13.6 eV (electron volts), or a photon of wavelength 91.2nm (nanometers). (Note: Visible light is roughly 380nm starting ultraviolet, to 750nm starting into infrared. The shorter the wavelength, the higher the energy level.) Some interesting research has been conducted that would seem to modify this rule, and sees results at 250nm.”
OUPower.com :: View topic - Light wavelength and electrolysis and
Directory:Using Light Finesse Instead of Brute Force in Water Molecule Dissociation - PESWiki
Now look closly, do you see that 91.2 nm is the same recuierments as to remove a one hydrogen from a watermolecule? Interesting right.
So if we consider this information, 150 - 270 nm whould work great right? That also means that we need to re-think the GP. Now let's say that we do this, what would the outcome be?
I would build a unit for the first ionization level, where two UV-C lightbulbs are placed - maby use a small squared box whit it's own EEC - but these bulbs dont get pulsed. After this step the next ionization levels of the GP, that is when we use ordenary LED's.
I'm still working on the calculation of them so i'll get back to you when i know more, later today, but i want you to reflect this befor you trow it away. Give me some feadback on this - if it is something to consider or not!
Don't say "it's your rule" or something like that, give positive feedback.
I tought it was a good idea to investigate it. Take a look at this document:
http://www.heraeus-noblelight.com/fi.../Lampe_eng.pdf
The reason for me looking into this is that i want to be as close as possible for the first ionization level and we (I) know this:
So let’s see what we can do whit the information we have so far.
First off, we know what the energy requirements are to ionize the oxygen and the hydrogen so let’s look at that first.
• Hydrogen: 1’st level = 1312.0 kj/mol
• Oxygen; 1’st level = 1313.9 kj/mol
2’nd level = 3388.3 kj/mol
3’rd level = 5300.5 kj/mol
4’th level = 7469.2 kj/mol
What is the first we can see? We can see that first ionization level of hydrogen and oxygen is fairly close whit a difference of 1.9 kj/mol, but that is a number we can live whiteout (according to me), so therefore we can look at a combination to ionize the hydrogen and the oxygen at the same time.
According to Oxygen @ Periodic Table of Chemical Elements - Chemistry Online Education the first ionization level of oxygen is:
• 13.617 eV = 109833 cm-1 = 1313.9 kJ/mol for oxygen and
• 13.598 eV = 109674 cm-1 = 1312.0 kJ/mol for hydrogen
The difference between these two are .019eV and I don’t think that we need to look for that a small difference.
So let’s convert eV to nm so we can find the right light source for this.
For the hydrogen we need a 91.2 nm wavelength and that should work well for the oxygen ionization as well.
So where can we find such a diode/LED?
To use such a light sourch is tuff to find, we are talkning about ultraviolet C (UVC = 100-280 nm) or vacuum ultraviolet (VUV = 10-200 nm) – to develop a a light sourch that deliver these kind of wavelengths whould be expensive, so lets look at an alternative.
This is from a responce i did over at oupower.com:
”To ionize (remove) a hydrogen atom from a water molecule, it takes 13.6 eV (electron volts), or a photon of wavelength 91.2nm (nanometers). (Note: Visible light is roughly 380nm starting ultraviolet, to 750nm starting into infrared. The shorter the wavelength, the higher the energy level.) Some interesting research has been conducted that would seem to modify this rule, and sees results at 250nm.”
OUPower.com :: View topic - Light wavelength and electrolysis and
Directory:Using Light Finesse Instead of Brute Force in Water Molecule Dissociation - PESWiki
Now look closly, do you see that 91.2 nm is the same recuierments as to remove a one hydrogen from a watermolecule? Interesting right.
So if we consider this information, 150 - 270 nm whould work great right? That also means that we need to re-think the GP. Now let's say that we do this, what would the outcome be?
I would build a unit for the first ionization level, where two UV-C lightbulbs are placed - maby use a small squared box whit it's own EEC - but these bulbs dont get pulsed. After this step the next ionization levels of the GP, that is when we use ordenary LED's.
I'm still working on the calculation of them so i'll get back to you when i know more, later today, but i want you to reflect this befor you trow it away. Give me some feadback on this - if it is something to consider or not!
Don't say "it's your rule" or something like that, give positive feedback.
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