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Stanley Meyer Explained

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  • So how many volts do we think we need for the final voltage zone that puts the image charge on the water? I do believe it can be straight DC for yoU don't need a pulse to put an image charge on water. As shown in the kelvin generator videos.

    Comment


    • As far as I can tell water has a threshold of 20k volts. At 20k volts and above the voltage starts to fource the water droplets to divid into smaller water droplets. The droplets are not round they are cylindical in shape but a bent cylindical shape of about 109 degrees. You will have to refresh your mind by going over all of these lectures over and over again for we just don't always think in the right frame of mind: MIT OpenCourseWare | Physics | 8.02 Electricity and Magnetism, Spring 2002 | Video Lectures

      Now the question you ask, pmazz850, is a very important one for it has to do with the timing or if you will the frequency used for the different lengths of the voltage zones and tempertures used on the water molecule while it is under perssure. Meyer takes the time to tell us that the voltage zones have to be from 0.25-1.00 inches. For it is a timing issue, as the hot water leaves the injector into a low pressure zone it imedeatly turns into vapor, or that is to say the time frame is very short. These little water droplets then pick up an image charge while flowing through the voltage zone but every time they reach 20k volts they divid in physical size and the pulsing from the voltage zones power supply recharges the water droplet and the process repeats. The thing we want is the water droplets to reach a critical mass and the micro capacitor shorts out creating hydrogen and oxygen as it does. That is the reason the voltage zones must be pulsed so that this process repeats enough times to break down the water molecule. Evaporation also plays a key role in this happening for as the water divids it is also evaporating thus the surface area of the physical micro capacitors are shrinking at the same time they are dividing and being recharged. That is the main reason I am starting off at 50k Hz for I have only enough room for a 0.25 inch voltage zone and my temps might also have to be higher than 90 degrees C to decrease the time it takes for the water to turn into a vapor. It's all about the time frame in which you have to work with over the distance you have to do work on the water molecule. As far as power consumption we are only dealing with micro amps.

      Go over all the lectures for none of us keep all that is given in there in our minds all the time so we need a refresher from time to time so that we stay on track and keep sharpe.

      Hope that aided in your understanding of how the injectors work using known science to answer the question.


      h2opower.

      Comment


      • Thanks H2opower, I'll refresh my mind!!

        Comment


        • Correction...

          Originally posted by sebosfato View Post
          Meyer said it was series resonance ok so the less the resistance of the wire the greater the Q so if you make a circuit with a Q about 5000 6 mili ohm resistance and about 10uH coil you calculate to the capacitor value the resonant frequency and just drive it near this frequency you will see what happens. High amp diodes.


          If you want to believe good for you my friend.
          The PATENT DRAWINGS show the electrical connections between the chokes and the secondary...

          The Connections are in SERIES....

          WHEN FULLY ASSEMBLED, THE VIC COIL BECOMES A PARALLEL CONNECTED INDUCTOR IN RELATION TO THE TAPER RESONANT CAVITY OR WFC.

          The final connection of the VIC uses a parallel LC RESONANT calculation.
          THIS RESULTS IN HIGH VOLTAGE AND MINIMUM AMPS AT THE RESONANT FREQUENCY BASED ON THE CAPACITANCE AND INDUCTANCE.

          I dont mind explaining that the circuit that you are looking at ( where the chokes are shown one on each side in series...) is drawn to LEAD PEOPLE AWAY from stealing the design.

          Just as any assembly of pancake coils spirally wound side by side are SERIES CONNECTED, but when combined by capacitive and inductive reactance on a common core, they end up as a UNIT CONNECTED in PARALLEL to the LOAD.

          Im done with you... from now on im just going to ignore your foolish posts...
          sorry... do some reading of this thread from page one and try to leave out of your mind all the silly ideas from casual commenters, who do not understand science... as you read this thread, the explanations will teach you common electrical theory and beginning physics.. Good Day SIR!

          Comment


          • RE:Final Voltages

            Originally posted by pmazz850 View Post
            So how many volts do we think we need for the final voltage zone that puts the image charge on the water? I do believe it can be straight DC for yoU don't need a pulse to put an image charge on water. As shown in the kelvin generator videos.
            There are NO final voltages... the voltage level is variable to allow different volumes of gasses depending on the demand from the engine... as far as i know, the Kelvin Generators can produce straight DC but the DC comes from a static charge build up on the rings and the containers, and in my opinion will not give enough amperage to drive any useful loads, like motors or lights of any wattage. There can be huge voltages generated with static charges, but the amperages are in the milliamp range...
            please correct me if i am wrong...

            Also, the taper voltage waveguide is more like a water fuel cell than a kelvin ring... a kelvin ring has only one polarity on the outside and the sink (bucket of water) is the other polarity.

            Straight dc VS Pulsed DC... with a 50% duty cycle you will cut the amperage in half!

            if we could freeze time and stop the earth from turning ( just to get the whole time freezing picture established...) there would bo NO AMPERAGE in any ELECTRICAL CIRCUIT in the UNIVERSE!
            Amperage is a measure of electron flow over time.
            On the other hand Voltage is instantaneous and eternal simultaneously... without time we can have voltage but no amperage.....and no work produced except that potential energy that was waiting to do work at the moment time was frozen, at whatever level ithappened to be at.

            Thats my new paradigm, we shall call it " Quantum -Conceptual ElectroPhilosophy ".

            Comment


            • Originally posted by TRON View Post
              There are NO final voltages... the voltage level is variable to allow different volumes of gasses depending on the demand from the engine... as far as i know, the Kelvin Generators can produce straight DC but the DC comes from a static charge build up on the rings and the containers, and in my opinion will not give enough amperage to drive any useful loads, like motors or lights of any wattage. There can be huge voltages generated with static charges, but the amperages are in the milliamp range...
              please correct me if i am wrong...

              Also, the taper voltage waveguide is more like a water fuel cell than a kelvin ring... a kelvin ring has only one polarity on the outside and the sink (bucket of water) is the other polarity.

              Straight dc VS Pulsed DC... with a 50% duty cycle you will cut the amperage in half!

              if we could freeze time and stop the earth from turning ( just to get the whole time freezing picture established...) there would bo NO AMPERAGE in any ELECTRICAL CIRCUIT in the UNIVERSE!
              Amperage is a measure of electron flow over time.
              On the other hand Voltage is instantaneous and eternal simultaneously... without time we can have voltage but no amperage.....and no work produced except that potential energy that was waiting to do work at the moment time was frozen, at whatever level ithappened to be at.

              Thats my new paradigm, we shall call it " Quantum -Conceptual ElectroPhilosophy ".

              Hi Tron,
              The Kelvin Genarators is exactly how the injectors work. Remember I spoke of the relaxation time for water to carry a charge? What that is saying is the water will carry the voltage potential for a given time. This part I don't think even Stanley Meyer understood fully, given time though I am sure he would have figured it out. The part in the video I posted that shows the two 510 volt batteries is the the same as what we are doing with the injectors. Except our power source is the VIC transformer with a blocking diode that will double the voltage of the capacitor to the power supply in the capacitor. The injectors take the least about of current of all of Stanley Meyer's technologies. The reason for this is what is being done is simular to how a lightining storm works, hens a Kevlvin Genarator. The tapper part of the voltage zone allows voltage to preform work by physical changing the surface area of the capacitor. How that part works is the potential is always perpendicular to the surface(s) so is the magnetic field in a capacitor so as the surface area changes the flux density on the surface in creases but the net charge has remained the same. In doing to voltage has to preform work to keep in ballance. I happens twice in some of Meyer injector designs the water molecule is loosing surface area and the voltage zone is also loosing surface area. The time of all of this is in the miliseconds and that is why Stanley Meyer says if you want to convert more water you increase the frequency and to process more water with a fixed design you increase the voltage amplitude. The Gas Processor is a fixed design as well as the water fuel injectors, so what can be changed is the VIC transformers that will resonate at different frequencies in the LC circuit.

              Note everyone he is right on the VIC transformer for even though it says it has a primary, secondary , and two chokes, it really only has a primary and a secondary. The secondary has been broken down into more parts but it is still just one secondary and that is the same as the way an alternator is designed for all the winds only make up three secondaries for a three phase power supply, noting that each loop is equal to one bobbin cavity in the VIC transformer(though with the two layered part equals two loops). How the voltages are built up in an alternator is the same as how voltages are built up in the VIC transformer.

              I know it is not easy to see how the injectors relate to the Kelvin Genarators for it is not intuitive. You really have to understand the mechanizims involved to see that is how they are working. That was the last part of Stanley Meyer's technologies I solved and was the most difficult for it means he used two different ways to break down the water molecule. One was through equlibrium changes and the other was using the properties of water to aid in it being broken down.

              So now for the record there are four ways to break down the water molecule, Faraday, Magnetic, Equilbrium changes, and The properties of water. I think heat and pressure can also break down the water molecule and that would make it five ways. In accelerators this is a problem they have to design for, for they don't want the water molecule breaking down with the magnetic fields and they use water as the dielectric and for cooling.

              Hope that helps everyones understanding a bit further,

              h2opower.

              Comment


              • This is for TRON or h2opower ONLY!!!

                And the reason for that is that you two are the only ones i trust to 100 % in this tread, so for that reason the next question is to you two guys. ItŽs about the GP!

                Now, first of all - the question iŽm about ask might have been covered (since iŽm asking, iŽm not sure it has) and it might something reapeting it self over again, but never mind, here it goes.
                ...

                In the beginning of this forum h2opower said this:

                Like I said the WFC is NOT IMPORTANT it is the GAS PROCESSER that is the key to this technology.

                Some numbers for you to think over:

                Gasloine has a energy level of 4846 kJ/mol
                H2 + 1/2O2 has an energy level of 286.02 kJ/mol

                Now this is what happens when it passes through the Gas Processor:
                1st ionozation level,
                H 1312 + 1/2 O 1313.9 = 1968.85 kJ/mol
                2nd for oxygen,
                H 1312 + 1/2 O 3388.3 = 3006.15 kJ/mol
                3rd for oxygen,
                H 1312 + 1/2 O 5300.5 = 3962.25 kJ/mol

                Now you can see just what the Gas Processor is doing. Note, depending on how far you ionize the Oxygen the energy levels keep going up to end up with this:
                H 1312 + 1/2 O 84,078.0 = 43,351 kJ/mol. Now that's energy

                If you get to any one of these energy states it will run your engine with ease. So, the key is to make the Gas Processor and make it to ionize the gases that go through too a energy state as far as you can so you can get these energy levels to put in the cumbustion chamber and ignite them. I suggest to make two of them one for the incoming air and the other for the hho from what every source you choose to get the hho from. Now you can see just how Stanley Meyer ran his 1.6L VW engine on just a 7L/min production rate.
                NOW, i looked over some numbers of ionization of Oxygen - the energy required to REMOVE electrons and this is what i found:

                The Oxygen Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Oxygen. O -> O+ + e-
                This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Oxygen is:
                ON+ -> O(N+1)+ + e-


                O -> O1+ = 1313.9 kJ/mol = 314.33 Kcal/mol
                O1+ -> O2+ = 3388.2 kJ/mol = 810.57 Kcal/mol
                O2+ -> O3+ = 5300.3 kJ/mol = 1268.01 Kcal/mol
                O3+ -> O4+ = 7469.1 kJ/mol = 1786.87 Kcal/mol
                O4+ -> O5+ = 10989.3 kJ/mol = 2629.02 Kcal/mol
                O5+ -> O6+ = 13326.2 kJ/mol = 3188.09 Kcal/mol
                O6+ -> O7+ = 71333.3 kJ/mol = 17065.38 Kcal/mol
                O7+ -> O8+ = 84076.3 kJ/mol = 20113.95 Kcal/mol

                from: Oxygen Ionization Energy

                For as i understand this (i might be wrong here): It requires 1313.9kj/mol to remove one elektron from one oxygen atom and if you only did that and nothing more, you whould get back 1968.85kj/mol becous you need to add the energy content of hydrogen wich is 1313.9 + 1312 = 1968kj/mol... BUT WHAIT A MOMENT.
                (next line is from Hydrogen - EniG. Periodic Table of the Elements)

                1st ionization energy of hydrogen is 1312.06kj/mole (thatŽs it, it only has one lv).
                1st ionization energy of oxygen is 1313.9kj/mol
                1312.06 + 1313.9 = 2625.96kj/mol

                When i was reading true the two pages i linked to, THAT IS WHAT I GOT OUT OF IT - 2625kj/mol of energy - but look closly.

                What h2opower is saying is this:

                Now this is what happens when it passes through the Gas Processor:
                1st ionozation level,
                H 1312 + 1/2 O 1313.9 = 1968.85 kJ/mol ... WHAT? a 1/2 oxygen atom??? (wich is 656.95kj/mol) HOW IS THAT POSSIBLE?

                Did you mean to write 1/2 O2 (the half of one oxygen molecule)???... becous one half oxygen atom doesent make sense to me

                So, h2opower, you are welcome to clarefy that one and it should be you
                ...

                Now, lets move over to the actual question and the main reason for me writing.

                The key to this process is the GP and EEC, okey, that means that we need to gaine energy in the GP right, becouse we know that it takes ENERGY (operator input) to dislodge electrones from the nucleus (reffering to the numbers abbow) so, according to my numbers and understanding of the GP (IMPORTANT) this is what i found reasonable.
                BUT first of all one huge question - just to see if iŽm right or not.

                "When the HHO gas enters the GP whit itŽs elektron(s) in the same inviroment we need to start a reconance action or an electron moving motion. What is important to know is that everytime you remove an electron, the remaining electrons gets puled closer to the atomic nucleus - why? becous of the decrease of energy and that is the reason for higher ionozation energy every level you wich to move to. So, between lv 1 and lv 8 in the oxygen atom there is 84076.3 - 1313.9 = 82762.4kj/mol of energy. Now in order to gain energy there must be a logic to the GP.
                For if i understand it correctly this is what happens.

                First you have no movement and 8 electrones in the oxygen atom - now you whant to remove one electrone so you start to reconate the oxygen right? -the electron shell starts to move (pulsating) in and out from itŽs orbit (higher state and back down t itŽs lower state many times a secund) - The key is to remove the electron when it is in itŽs higher state to bypass the energy level of the 1Žst ionozation level (to half it or so) - now lets assume that this number is 600kj/mol - you gained 1313.9 - 600 = 713.9kj/mol. There is no magic, only science right?.. so that is my logic - do you see the patern?

                Now lets move on to the 2Žnd lvl and follow teh same pathern. If we whant to gain energy in the 2Žnd ionozation level you need to move the electrone path back to itŽs first level (minimum) wich gives us 3388.2 - 1313.9 = 2074.3kj/mol.
                If the 2Žnd ionozation level is moved UP to the 1Žst ionozation level - THAT IS WHERE YOU GAIN ENERGY... so how whould that look like?

                3388,2 + 1313,9kj/mol (1Žst + 2Žnd lv) = 4702,1kj/mol [recuiered energy]
                713.9 + 2074.3 kj/mol (energy gained) = 2788.2kj/mol

                4702.1 - 2788.2 = 1913.9 kj/mol .. THAT IS WHAT YOU GAIN IN USING THE GP if you only remove two electrones from one oxygen atom.

                The futher away the elctrones are the easyer it is to remove them - itŽs simple, but how fare can we move them in the GP???
                ...

                This is my logic and this is how i see it. Correct me if iŽm wrong - i am only trying to understand what the photons actually do to the atom - what happens and what the reason is for the electron reduction... hope i used the right words here so you can understand me

                Take care!
                - Behold the truth -

                Comment


                • In the begining I made some misteaks, but later on to went back to the books to make sure I was doing everything the right way. This is the part where I got the math right: http://www.energeticforum.com/renewa...html#post37266

                  I assume you have no formal chemisty in that you don't know that the ionization levels are a two way street. When the energy level goes up you don't see anything, only when the energy level falls back down do you see energy in the form of light in most cases.

                  What makes the Gas Processor so powerfull at this is the rules of capacitance and the photonic energy in the form of coherent light. The rules of capacitance is the field is always hit perpendicular to the surface and every atom on the surface is working alone but in concert as you move down through the Gas Processor due to the pulse train set at the Gas Processor it is almost ever regenerative with the frequency being so fast. Now when the pulse train is switched off the coherent light energy is switched on this keeps the energies gained from falling back down. But due to LED light advancements we can now also use the coherent light to also push up the energy levels aswell. Stanley Meyer didn't have ultra vilolet or white light LEDs in his time and the LEDs he did have you could shine right in your eye and still see afterwards, do not try that with todays LEDs for you will get perminate eye damage and/or never see again. All these advancements has made it easyer for us to do the same job Stanley Meyer did. Now to see what photons do to the oxygen atom one only has to study the bora bora light over the poles for most of what you are seeing is the oxgyen ionized atoms falling in energy level that have been bombarded by light waves from our sun and magnetic fields from our planet. The Gas Processor simulates that action and is why Stanley Meyer uses that example in the patents.

                  Now do you get an idea of how powerfull this Gas Processor really is? It is an intermixing chamber of electrons and photons all working on the oxygen atoms in its' gas form. For this is how mother nature does it everytime you see a lightining storm, every time you see a seed growing out of the ground, everytime you see life on this planet. We all follow the same rules and that is to deal with the atoms or molecules of substances on a atomic scale( very small). For most of the work that keeps us alive is done in our small capularies and villa of the small intestants, and also the lungs. They deal with small atoms and molecules, that is why it is very dangerous injecting anything directly into your blood stream for something like a few grains of salt could kill you for the body hasn't had time to process it. I find it amazing that this technology has opened my eyes to how everything works in life, that to me shows we are tapping into the wheel work of life. Just as Teasla predicted so many years ago.

                  The reason I leave out the Hydrogen atom is that it only has only electron to strip off and the process of the injectors really only break down the water molecules into hydrogen and oxygen, though a longer voltage zone might bump up the energy levels, it was not accounted for in the math equations that I ran. Thus in my final adding I left out the hydrogen's ionization level completely for to me it is an energy carrier (just as the scince guys says it is) and in doing so I was able to see that at oxygens 4th ionization level the reactions energy content over takes the energy content of gasoline. That is when Stanley Meyer's words talking about the 4th energy level or more made sense to me and it is all the math you are going to get from him unfortunitly. These are the parts he left out of the patents, and all I did was take a very close look at the Gas Processor and the whole water for fuel technology opened up to me.

                  I hope that helps your understanding a bit more, not sure if you wanted me to go into the numbers or not, but really didn't see a need to do so.


                  h2opower.

                  Comment


                  • Good Day SIR!

                    Originally posted by TRON View Post
                    Good Day SIR!
                    Thanks to all for Your contris:
                    h20power, HMS-776, TRON, Oneminde and all the others
                    AND
                    sebosfato

                    Not sure what kind of resonance it is, but keep in mind:

                    In a SERIES resonance circuit (at resonance w0) the current Is(t) is all the same into, inside and out of circuit:
                    Is(t) = Ic(t) = Il(t) = Ir(t)
                    The voltage across the whole series resonance circuit Us is (can be) much lower then the voltage across L: Ul or across C: Uc:
                    Ul = Uc >> Us


                    In a PARALLEL resonance circuit (at resonance w0) the voltage Up(t) is all the same across circuit, across L, across C, across R:
                    U(p) = Uc(t) = Ul(t) = Ur(t)
                    The current into the parallel resonance circuit Ip is (can be) much lower then the current into L: Il or into C: Ic:
                    Il = Ic >> Ip

                    Question is, what do we want?
                    High voltage at C?
                    Or
                    High current into C?

                    The power lost (the real power into circuit) is in either cases only depending on R.


                    Thanks a lot to all,
                    and sebosfato, please, keep on posting

                    regards
                    magnetO
                    Last edited by magnetO; 07-02-2009, 08:01 AM.

                    Comment


                    • sebosfato you now seem to have an request to make your own thread. So please do so! Thanks.

                      Comment


                      • Originally posted by magnetO View Post
                        Thanks to all for Your contris:
                        h20power, HMS-776, TRON, Oneminde and all the others
                        AND
                        sebosfato

                        Not sure what kind of resonance it is, but keep in mind:

                        In a SERIES resonance circuit (at resonance w0) the current Is(t) is all the same into, inside and out of circuit:
                        Is(t) = Ic(t) = Il(t) = Ir(t)
                        The voltage across the whole series resonance circuit Us is (can be) much lower then the voltage across L: Ul or across C: Uc:
                        Ul = Uc >> Us


                        Question is, what do we want?
                        High voltage at C?
                        Or
                        High current into C?

                        The power lost (the real power into circuit) is in either cases only depending on R.


                        Thanks a lot to all,
                        and sebosfato, please, keep on posting

                        regards
                        magnetO

                        Magneto thanks for interest you mean the input current is = to the circulating current right? with no limitation it is even higher it can go up to 1Kamps with no benefit to voltage or recirculating current load impedance become very low so is like a short circuit for the imput circuit. Using the simulation i understood the vic function is to have a soft start like or a limit for the input current power if you want it is the responsable to the step charging effect if you connect it straight to a capacitor but it will create a resonant charging effect if you connect the way i said. Meyer was very inteligent he would not make it that easy but the sync pulse circuit is the right one it don't need the alternator and all the components there are clean like water. so he said series circuit.

                        Stan was for sure aplying maybe 2 or even 40kv using 1 ma/h but after 1 second working at for saying on my design 500khz you have 500000*60sec*60min= 1800000000 pulses in one hour right ok if you have 1mA / 1800000000 you have 5E-13 amps per pulse ok so if you apply 500khz for a infinite Q circuit you would have 5E-13 amps * 500khz^500000. Now you know how to calculate a duty cycle for controling this. If you have about 5000 Q you have 5E-13*500000^5000 band widith would be 100 hz +-


                        About multisim you should register to demonoid to be able to download the torrent than you download it using utorrent or lime wire ... than activate it with the activation. maybe also on rapid share.

                        the program is easy and simple you put a function generator voltimeter amperimeter osciloscope transformer diode and inductor and capacitor and try try try.

                        H20 thanks you for the incentive and soon when i have everything hook up here i'm going to say if it works and from that moment we are going to be free. i sugest you all to print this all thread save the information.

                        Tron thank you for questions and doubts i hope i can show you the way not only for having a technology like this but to learn something very important to your life that is to hear even if you still not sure if its right or not because messages come in the midles of the words. P E a CE

                        Voltage across the capacitor in our case is = to dc resistance of the capacitor * the dc rectified recirculating current.

                        Stan said the circuit is self sustained oscilating he intend to say it after it start it work using most water electrons and electrons from the gas processore to run the circuit.

                        Comment


                        • Originally posted by sebosfato View Post
                          Magneto thanks for interest you mean the input current is = to the circulating current right? with no limitation it is even higher it can go up to 1Kamps with no benefit to voltage or recirculating current load impedance become very low so is like a short circuit for the imput circuit. Using the simulation i understood the vic function is to have a soft start like or a limit for the input current power if you want it is the responsable to the step charging effect if you connect it straight to a capacitor but it will create a resonant charging effect if you connect the way i said. Meyer was very inteligent he would not make it that easy but the sync pulse circuit is the right one it don't need the alternator and all the components there are clean like water. so he said series circuit.
                          In a SERIES resonant circuit we have L and C in series, and in between a Resistance R (at least the wiring of coil). The input current and the circuit current (thru coil, thru cap, thru wiring) is all the same on each part of a second (at a given frequency). At resonance the current goes as high, as the Resistance R is low (we always have Resistance of coil wiring). So the SERIES resonant current does NOT exceed all limits! It has simply a (maybe high) value. But the voltage across the coil and the voltage across the cap (WFC, tapered Resonance Cavity) does exceed all limits (if Q is very high). The (very high) voltage across C is 90° later than the current thru C, so no real power. The (very high) voltage across L is 90° prior to the current thru L. In either cases no real power is needed. But we need to have the power for current thru wiring (P=IČ*R).
                          When WFC, tapered Resonace Cavity is part of a series resonance circiut, we can put all high voltage on it.

                          In a PARALLEL resonant cirquit the voltage is the same over all parts. Input voltage = voltage across cap = voltage across coil. No voltage multiplying at all. At resonance the current thru the circuit is mostly restricted! But the current INTO the cap, and the current INTO the coil can exceed very high. (Again without being real power).
                          When WFC, resonant Cavity is part of parallel resonance circuit, we can push strong current thru it.

                          Question is, what do we want?



                          Originally posted by sebosfato View Post
                          Stan was for sure aplying maybe 2 or even 40kv using 1 ma/h but after 1 second working at for saying on my design 500khz you have 500000*60sec*60min= 1800000000 pulses in one hour right ok if you have 1mA / 1800000000 you have 5E-13 amps per pulse ok so if you apply 500khz for a infinite Q circuit you would have 5E-13 amps * 500khz^500000. Now you know how to calculate a duty cycle for controling this. If you have about 5000 Q you have 5E-13*500000^5000 band widith would be 100 hz +-
                          I dont really understand that above.


                          Originally posted by sebosfato View Post
                          About multisim you should register to demonoid to be able to download the torrent than you download it using utorrent or lime wire ... than activate it with the activation. maybe also on rapid share.

                          the program is easy and simple you put a function generator voltimeter amperimeter osciloscope transformer diode and inductor and capacitor and try try try.
                          Thanks for describing how to do. I will catch that multisim.

                          Regards
                          magnetO

                          Comment


                          • Originally posted by magnetO View Post
                            In a SERIES resonant circuit we have L and C in series, and in between a Resistance R (at least the wiring of coil). The input current and the circuit current (thru coil, thru cap, thru wiring) is all the same on each part of a second (at a given frequency). At resonance the current goes as high, as the Resistance(IMPEDANCE) R is low (we always have Resistance of coil wiring). So the SERIES resonant current does NOT exceed all limits!(IT CAN MELT COPPER WIRE>>LIMITED BY WIRE SIZE AND WATTAGE OF SOURCE) It has simply a (maybe high) value. But the voltage across the coil and the voltage across the cap (WFC, tapered Resonance Cavity) does exceed all limits ( P=IE...WITH A GIVEN >FIXED< WATTAGE SOURCE, IF THE CURRENT IS LARGE, THE VOLTAGE MUST DROP) (if Q is very high). The (very high) voltage across C is 90° later than the current thru C, so no real power. The (very high) voltage across L is 90° prior to the current thru L. In either cases no real power is needed. But we need to have the power for current thru wiring (P=IČ*R).
                            When WFC, tapered Resonace Cavity is part of a series resonance circiut, we can put all high voltage on it. (stans circuit is a parallel LC...DONT USE HIS DIAGRAMS FOR ELECTRICAL CALCS..THE FINAL VIC COIL IS A TOTAL UNIT WITHIN A SINGLE EI CORE>COMBINED IMPEDANCE<>COMBINED INDUCTANCE< TREAT IT AS A SINGLE INDUCTOR, BUILD IT AND THEN MEASURE INDUCTANCE WITH A METER, THEN CONNECT WITH THE WATER CAP IN PARALLEL TO THE VIC ASSEMBLY! ONCE YOU UNDERSTAND THE CUTAWAY SECTIONAL VIEW OF THE ASSEMBLED BOBBINS AND THE MUTUAL CAPACITANCES AND INDUCTANCES ( I THINK ITS FIGURE 580) , THEN YOU WILL UNDERSTAND WHY I SAY ITS A FINAL OPERATIONAL PARALLEL CIRCUIT THAT IS WIRED INTERNALLY AS A SERIES SET OF COILS...BECAUSE THEY ARE ALL MUTUALLY CLOSE COUPLED, THE SPEED OF LIGHT ELECTRICAL EFFECTS COMBINE AND CHANGE THE PHYSICS OF EACH COIL SIMULTANEOUSLY...SIMPLY ITS A GIANT INDUCTOR WHEN ASSEMBLED.

                            In a PARALLEL resonant circuit (SIMILAR TO AN OPEN CIRCUIT, ZERO CURRENT, BUT WITH VOLTAGE POTENTIAL PILING UP AT THE PLATES, UNABLE TO JUMP ACROSS THE GAP) the voltage is the same over all parts. Input voltage = voltage across cap = voltage across coil. No voltage multiplying at all.( RETHINK THAT ONE ) At resonance the current thru the circuit is mostly restricted! (TOTALLY)But the current INTO the cap, and the current INTO the coil can exceed very high.(WRONG) (Again without being real power).
                            When WFC, resonant Cavity is part of parallel resonance circuit, we can push strong current thru it.(WRONG, THATS THE SECRET OF THE VIC, STATIC VOLTAGE POTENTIAL, ZERO CURRENT...NOT POSSIBLE BECAUSE THE RESONANT FREQUENCY IS A MOVING TARGET, SO THERE WILL BE A FOLLOWING UP AND DOWN OF THE PEAK RESONANT FREQUENCY BY THE PHASE LOCK LOOP CIRCUIT TRYING TO KEEP RESONANCE BUT NEVER PERFECTLY, THATS WHY STAN ALWAYS HAD 1 OR 2 MILLIAMPS FLOWING IN THE AMPMETER..)

                            Question is, what do we want?


                            magnetO

                            EDITS IN RED...

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                            • Originally posted by magnetO View Post
                              In a SERIES resonant circuit we have L and C in series, and in between a Resistance R (at least the wiring of coil). The input current and the circuit current (thru coil, thru cap, thru wiring) is all the same on each part of a second (at a given frequency). At resonance the current goes as high, as the Resistance R is low (we always have Resistance of coil wiring). So the SERIES resonant current does NOT exceed all limits! It has simply a (maybe high) value. But the voltage across the coil and the voltage across the cap (WFC, tapered Resonance Cavity) does exceed all limits (if Q is very high). The (very high) voltage across C is 90° later than the current thru C, so no real power. The (very high) voltage across L is 90° prior to the current thru L. In either cases no real power is needed. But we need to have the power for current thru wiring (P=IČ*R).
                              When WFC, tapered Resonace Cavity is part of a series resonance circiut, we can put all high voltage on it.

                              In a PARALLEL resonant cirquit the voltage is the same over all parts. Input voltage = voltage across cap = voltage across coil. No voltage multiplying at all. At resonance the current thru the circuit is mostly restricted! But the current INTO the cap, and the current INTO the coil can exceed very high. (Again without being real power).
                              When WFC, resonant Cavity is part of parallel resonance circuit, we can push strong current thru it.

                              Question is, what do we want?

                              Regards
                              magnetO
                              SIMPLY, STAN MEYER HAD 2 MILLIAMPS IN HIS WFC

                              SIMPLY, ONLY A PARALLEL RESONANT CIRCUIT WILL OPERATE THAT WAY...

                              SIMPLY, ANYONE USING HIGH CURRENT TO SPLIT WATER IS USING YESTERDAYS FARADAY CIRCUITS, AND PRODUCING HEAT, AND WASTING ENERGY, HEAT = LOW EFFICIENCY

                              SIMPLY, THIS EXPLAINS HIGH YIELD HYDROXY WITH LOW INPUT POWER

                              AND FURTHERMORE...ADD THOSE MAFIA IONS FROM THE GP AND SOME WATER SKULLS ARE GONNA SPLIT!

                              NOW I UNDERSTAND HOW STAN COULD GO THROUGH SO MUCH WATER, AND PRODUCE SO MUCH GASS IN SUCH A SHORT TIME...

                              THE ONLY WAY HE WAS ABLE TO CALCULATE 22 GALLONS OF TAP WATER USED FOR A TRIP FROM LOS ANGELES TO NEW YORK, WAS THANKS TO THE GAS PROCESSOR AND THE SHAPE OF THE INJECTOR NODDLE CREATING COMPRESSIONAL WAVES....MAYBE HE EVEN HAD THE WATER RECLAMATION DEVICE SET UP TO PUT A PERCENTAGE OF THAT WATER FUEL RIGHT BACK INTO THE CYCLE AGAIN AND AGAIN...WOW!

                              THE MORE I LOOK AT THIS STUFF, THE MORE I BELIEVE HE WASNT A FRAUD...WITH INCREASED FAITH IN HIM TELLING THE TRUTH ABOUT THIS TECHNOLOGY, MORE ANSWERS ARE POSSIBLE....

                              FAITH GIVES US THE ABILITY TO SEE BEYOND THE MINDSET THAT WOULD HAVE GIVEN UP A LONG TIME AGO...

                              Comment


                              • Hi TRON,



                                When a cap (WFC, tapered res. Cavity) is SERIES linked to (a) coil(s), then the voltage ACROSS the CAP can exceed all limits at (near) resonance. The current thru the res. circuit and inside the res. circuit is all the same and normally moderate. Z = R (no Xc, no Xl) (of circuit). And so: input current = inside current = output current ~ 1/R.
                                But only in series resonant curcuit the voltage ACROSS the CAP can go very, very high. The moderate current thru the cap is out of phase with the high voltage across cap. Current into cap leads 90° before voltage across cap.
                                Current into coil lags 90° behind voltage across coil.

                                When a cap (WFC, tapered res. Cavity) is PARALLEL to a coil, then the current INTO the CAP can exceed all limits at resonance. The voltage across the whole circuit and the voltage across the coil and the voltage across the cap is all the same whatever its hight is.
                                But only INSIDE a parallel resonant curcuit the current INTO the coil and INTO the cap can go very, very high. The high current thru the cap is out of phase with the moderate voltage across cap.

                                I dont know what the vic is, maybe its a series resonant circuit (from the WFC's view), inside a parallel resonant circuit.

                                But I know what the difference series - parallel is.

                                Armageddon (I believe) did a very goog video to that stuff.

                                Regards
                                magnetO


                                Additional:
                                Of course, is in series resonant circuits (at/near resonance) the voltage thruout the WHOLE circuit a minimum, and maximum current goes thru it, but the voltage AT CAP (and coil) can increase very high.

                                Exactly, gives a parallel resonant circuit (at/near resonance) the highest Resistance (and therefore lowest current) thruout the WHOLE circuit, but the current THRU CAP (and coil) can increase very high.
                                Last edited by magnetO; 07-03-2009, 11:01 AM.

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